PrepShorts · Study sheet · Class 9 Mathematics · Chapter 5, I’m Up and Down, and Round and Round
Chapter 5 · I’m Up and Down, and Round and Round
The Corollary: a diameter stands on a right angle wherever you take the point
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The right angle in a semicircle is not a discovery. It is the doubling relation evaluated at the one arc whose central angle is a straight angle.
The idea
The right angle in a semicircle is not a new discovery; it is the doubling relation evaluated at the one arc whose central angle happens to be a straight angle. Take a diameter, take the arc on one side of it, and the swept angle from one radius to the other is 180° — because the two radii point opposite ways. Half of 180° is 90°, and the doubling relation says that half is what any point of the circle off that arc sees. So the result is a substitution, not an argument, and that is exactly why the chapter labels it a corollary and stops to explain what the word means. Knowing which results are cheap consequences of which is part of the mathematics.
What you should be able to do
- Say what a corollary is, in the sense the chapter defines
- State the right-angle result for a diameter, and identify which arc has to be chosen for the argument to work
- Explain why the swept angle for a semicircular arc is 180° and not 0°
- Derive the right angle in one step from the doubling relation
- Explain why the answer does not change as the third point moves round the circle
- Read the result backwards: given a right angle standing on a segment, place the point on a circle with that segment as diameter
- Connect the result to the circumcentre of a right-angled triangle sitting at the hypotenuse's midpoint
- Reconstruct the same result by the two-isosceles-triangle route the end-of-chapter figure sets up
Words to know
| Term | Definition in one line | First introduced |
|---|---|---|
| corollary | a result that follows at once from one already established | printed in bold in its own box, §5.7.1, p. 110 |
| diameter | the chord through the centre | printed in bold in §5.1, p. 93 |
| semicircle | half a circle, cut off by a diameter | printed in End-of-Chapter Q24, p. 116 |
| straight angle | an angle of 180° | printed in §5.7.1, p. 110 |
| angle subtended | the angle a chord or arc makes at a named point | printed in bold in §5.7, p. 106 |
| circumference | the curve of the circle itself | printed in End-of-Chapter Q6, p. 114 |
| circumcentre | the centre of the circle through a triangle's vertices | printed in bold in §5.3, p. 97 |
| hypotenuse | the side facing the right angle | printed in §5.3, p. 97, and in the caption of Fig. 5.7 |
| isosceles triangle | a triangle with two equal sides | printed in §5.7.1, p. 108 |
| diagonals | the two lines joining opposite corners of a quadrilateral | printed in End-of-Chapter Q15, p. 115 |
| Thales' theorem | the usual name for this result outside the book | not printed in this chapter, which calls it only a Corollary; the explanation may name it but the examinable phrasing is the chapter's |
| degenerate case | the explanation's phrase for the arc whose central angle happens to be exactly straight | an added term; the chapter treats this arc as one instance and does not classify it |
Where people slip up
- "The right angle is at the centre." It is at the point on the circle. The angle at the centre is the straight angle, 180°, which is what gets halved.
- "The third point has to be at the top of the semicircle." It can be anywhere on the circle other than the diameter's own ends. Fig. 5.24 draws it at the top and students read that as a requirement.
- "It only works for a semicircle drawn as a half-disc." The relevant object is the arc on one side of the diameter. Nothing has to be cut or shaded.
- "A corollary is a small theorem." The chapter's definition is about derivation, not importance: a corollary follows immediately from something already proved. This one is among the most used results in the whole chapter.
- "Choosing either arc gives the same argument." Choose the arc containing the third point and the configuration no longer matches the doubling relation's requirement. The chapter says explicitly which arc it is taking; an explanation that glosses over that step leaves the argument unjustified.
- "Any question mentioning a diameter is answered by 90°." End-of-Chapter Q20 is built to punish this. Check which chord the asked-about angles actually stand on.
- "The converse is obvious." Going backwards — a right angle placing the point on a specific circle — needs the concyclicity machinery of §5.8. It is true and it is not free.
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Worked answers to this chapter’s exercises · this video explains End-of-Chapter Exercises Q6, End-of-Chapter Exercises Q15, End-of-Chapter Exercises Q20, End-of-Chapter Exercises Q24
Transcript1,413 words
Some results are earned and some are collected. There is a word for the second kind: a corollary. A corollary is a result that follows immediately from something already proved - no new argument, no new idea, just a substitution into a machine you have already built. Be careful here: corollary sounds like it means small, and it does not. It says nothing about how important the result is. It says only where the result came from.
The one in this video is a corollary, and it is also one of the most used facts about circles there is. Knowing which results are cheap consequences of which is part of the mathematics, not bookkeeping around it. Here is the setting, and it is almost embarrassingly plain. A circle. A diameter across it, from A to B, through the centre. And then a third point somewhere else on the circle - call it D.
Anywhere else. Not at A, not at B, otherwise wherever you like. Join D to A and join D to B, and you have a triangle sitting on the diameter. The question is the angle at D. And the answer, every single time, is a right angle. That is the result. Now watch how little it costs. The relation we are about to use does not talk about chords. It talks about arcs.
So the first thing to do is say which arc. A and B cut the circle into two runs, and D is standing on one of them. Name the other one - the arc from A to B that does not pass through D. That is the requirement the relation makes: the point you are reading from has to be off the arc you named. Everything ahead is one substitution, so this is the only place there is a choice to get wrong.
Hold on to it. We will come back to it, and it will not behave the way you expect. Now, what does that arc make at the centre? Put a radius along the one going out to A, and turn it along the arc until it lies along the one going out to B. Here is the whole thing. A and B are the two ends of a diameter, so those two radii point in exactly opposite directions.
Turning from one to the other is turning through a straight angle. A hundred and eighty degrees. And notice it is a hundred and eighty rather than nothing, because the radius really does sweep - it does not just compare two directions at the end. That distinction is the whole reason the definition was set up the way it was. So now substitute. The arc makes a hundred and eighty degrees at the centre.
The doubling relation says a point of the circle off that arc reads half. Half of a hundred and eighty is ninety. The angle at D is a right angle. That is it. That is the whole derivation, and it is one line of arithmetic on top of a theorem that was already standing. No new construction, nothing added to the figure, no case to check. Which is exactly what the word corollary was reserved for.
Now slide D round the circle and watch what happens to it. The triangle changes shape completely - tall, squat, nearly collapsed - and the right angle does not budge. It cannot. Nothing in the argument mentioned where D was. The arc was fixed the moment A and B were chosen, so its angle at the centre was fixed, so half of it was fixed. This was checked at two hundred and twenty positions, and the reading was a right angle at every one of them.
And here is the check that means something: every ordinary chord was tried too - four thousand four hundred cases - and not one gave a right angle. It is not that the diameter is a convenient choice. It is the only choice. Back to the arc we named, because something strange happens here. Suppose you name the wrong arc - the one D is actually standing on. You would expect a wrong answer. You do not get one.
A diameter cuts the circle into two half circles, and both of them sweep a straight angle, so both of them halve to ninety. Across every position tested there was one reading in the whole family, either side of the chord. So the number survives the mistake. What does not survive is the argument, because the relation you quoted required the point to be off the arc, and it was not.
Try that on an ordinary chord and the two sides never once agree. A step you can skip without being caught is the most dangerous kind there is. There is a second route, and it uses nothing but triangles. Join D to the centre. Now there are two triangles, and both are isosceles - two of their sides are radii, and radii are equal. So in the left one, the angle at A equals the angle it faces at D. Call it a.
In the right one, the angle at B equals the angle it faces at D. Call it b. The angle at D is those two pieces together: a plus b. And the three angles of the whole triangle add to a straight angle - so a, plus a plus b, plus b, makes a hundred and eighty. Which forces a plus b to be ninety. The angle at D again, with no circles quoted at all.
Now a connection that usually goes unmade. Here is a fact about right-angled triangles that looks unrelated: the point equidistant from all three corners sits at the middle of the longest side. That is the same statement as this one, read from the other end. If the centre is at the middle of that side, then that side is a diameter, and the angle facing it is the right angle we just derived.
Solving for that point directly, rather than assuming it, it landed on the diameter's midpoint in all two hundred and twenty cases. For an ordinary chord it landed there in none of them. Two figures that are one fact. Run it backwards and it becomes a way of finding things. Take a segment ten units long, and ask where you can stand to see it at a right angle. The answer is the circle that has that segment as its diameter - so every such point is exactly five from the segment's middle.
A hundred and ten such points were built and checked: all five from the middle, and all with their two distances squared adding to a hundred. That last part is the theorem about right-angled triangles falling out on its own. One member of that family has whole-number distances: six and eight. Thirty six plus sixty four is a hundred, which is ten squared. One warning, because this result is badly over-applied.
Take a four-cornered shape with all four corners on a circle, and let one of its sides be a diameter. The word diameter appears, so the reflex is to write ninety and move on. Sometimes that is right: two of the angles do stand on the diameter, and those are right angles in every one of two thousand and ninety arrangements tested. But the pair you are usually asked about stand on a different chord altogether.
Those two are merely equal to each other, and only when their corners are on the same side of that chord - which happened one thousand four hundred and thirty times, agreeing exactly when it should. Check which chord the angle actually stands on. Every time. One last use, and it is a pretty one. Put a rectangle inside a circle with all four corners on it. Each of its angles is a right angle, so each diagonal is seen at a right angle from the other two corners - which means each diagonal has to be a diameter.
So the diagonals cross at the centre. Out of seven thousand three hundred and fifteen ways of picking four points, exactly fifty five made a rectangle - every one of them two diameters wearing a hat. Four of those were squares - the cases where the two diameters happen to be perpendicular. And all of it came from halving a straight angle. That is what a corollary is for.
Where this fits
Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.
Builds on
- Major and minor arcs, and why an arc's central angle is double what it subtends on the circle (Theorem 9)Class 9 · Ch 5, I’m Up and Down, and Round and Round
- Equal angles in the same segment: the arc looks the same from every point beyond itClass 9 · Ch 5, I’m Up and Down, and Round and Round
- Three points not in a line: exactly one circle (Theorem 1)Class 9 · Ch 5, I’m Up and Down, and Round and Round
Either side of this one
- Off the circle the angle changes: points inside and outside compared (Fig. 5.25)Class 9 · Ch 5, I’m Up and Down, and Round and Round