PrepShorts · Study sheet · Class 8 Mathematics · Chapter 6, We Distribute, Yet Things Multiply
Chapter 6 · We Distribute, Yet Things Multiply
What happens to a product when you nudge one factor
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Move one factor by one and the product does not move by one. It moves by the other factor.
The idea
If you move one of the two numbers in a product by one, the product does not move by one — it moves by the other number, and you can see why without computing either product. Splitting a bracket is what exposes the answer: the shifted product contains the original product plus exactly the extra pieces the shift added. Push that far enough and the eight or nine separate cases students expect — one up, one down, both up, both down, by one, by any amount, with negatives — collapse into a single statement, because the shifts are allowed to be negative numbers. The chapter's real claim is not a list of rules for how products change; it is that one rule already covers all of them.
What you should be able to do
- Predict how a product changes when one factor rises by one, and justify the prediction from the distributive property rather than from two computations
- Expand
a(b + c)and(a + b)c, and say which step uses distributivity and which uses commutativity - Expand
(a + 1)(b + 1)by treating one bracket as a single term, and identify the increase asa + b + 1 - Expand
(a + 1)(b − 1)and decide, for given values, whether the product rose or fell - State what an identity is, and explain why substituting a few values supports an identity without establishing it
- Use Identity 1 with negative values of the shifts to recover every increase-and-decrease case from one statement
- Find the condition under which two opposite shifts leave a product unchanged
- Explain why the two diagonal products of a 2-by-2 block of calendar dates always differ by the same amount
Words to know
| Term | Definition in one line | First introduced |
|---|---|---|
| distributive property | the rule that multiplying a sum is the same as multiplying each part and adding | printed in this chapter (Part I, §6.1, p.137) |
| distributivity | the chapter's shorter name for the same property | printed in this chapter (Part I, chapter opening, p.136) |
| commutativity | the rule that the order of two factors does not change their product | printed in this chapter (Part I, §6.1, p.137) |
| identity | an equality of two expressions that holds for every substitution | printed in this chapter (Part I, §6.1, p.139) |
| Identity 1 | the chapter's label for the four-term expansion of two two-term brackets | printed in this chapter (Part I, §6.1, p.139) |
| letter-number | a letter used in place of a number | printed in this chapter (Part I, §6.1, p.138) |
| term | one of the pieces a sum or difference is built from | printed in this chapter (Part I, §6.1, p.139) |
| expand | to rewrite a product of brackets as a sum of terms | printed in this chapter (Part I, §6.1, p.140) |
| integer | a whole number, positive, negative or zero | printed in this chapter (Part I, §6.1, p.138) |
| nudge | a small change made to one factor of a product | an added word; the chapter speaks of a number being increased or decreased |
| balance point | the relation between the two factors at which opposite shifts cancel | an added phrasing; the chapter sets this as an exercise and names nothing |
Where people slip up
- "Add one to a factor, add one to the product." The commonest error in the chapter's opening question. Adding one more copy of
aaddsa. Ask the class for a prediction before revealing anything, then run 23 × 27 and 23 × 28. - "Up by one and down by one must cancel." They cancel only when
bis one more thana. Otherwise the change isb − a − 1, which the chapter shows can be either sign — and it explicitly asks for three cases where the product falls. - "
(a + 1)(b + 1)isab + 1." Distributing shows three extra pieces: a strip ofa, a strip ofb, and one loose unit. The four-block array is the cure; the loose corner is a single marker and students can point at it. - "Decreases need their own rule." They do not. The whole point of Identity 1 is that the shifts are integers, so a decrease is a negative shift, and the ordinary sign rules produce the right signs unaided. The chapter's owl box says so directly.
- "Distributivity is an arithmetic habit that letters make dubious." The letters stand for numbers, so nothing is being extended. The chapter checks negative substitutions precisely to make this visible.
- "Substituting three values proves an identity." It does not, and the chapter is careful: it defines an identity as an equality holding whenever the letters are replaced by numbers, and it derives every one of them. Substitution is how you catch a mistake, not how you finish an argument.
- "The increase depends on which bracket you open first." It cannot; the page invites the student to redo
(a + 1)(b + 1)the other way round and get the same four pieces in a different order.
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Worked answers to this chapter’s exercises · this video explains Figure it Out · 6.1 Q1, Figure it Out · 6.1 Q3, Figure it Out · 6.4 Q4
Transcript1,431 words
Two numbers. Twenty-three and twenty-seven. Their product is six hundred and twenty-one. Now three questions. Answer all three before reading on. If the twenty-three becomes twenty-four, how much does the product gain? If instead the twenty-seven becomes twenty-eight, how much does it gain? And if both of them go up by one, how much then? The first answer most people give to all three is one. All three of those are wrong, and wrong in different ways.
And you can see every real answer without multiplying anything a second time. Draw the product instead of computing it. Twenty-three rows of dots, twenty-seven in each row. Now add one more column to the right. How many dots did you just add? One for every row. Twenty-three of them. That is the whole idea. Multiplying a sum is the same as multiplying each part and adding the results. In letters, a times the quantity b plus c is a times b, plus a times c.
The picture is the proof. The rows never change. The columns split in two, and each group keeps its own rectangle. Everything here comes out of that one sentence. Take c to be one. Then a times the quantity b plus one is a times b, plus a. The increase is a. Not one. The entire extra column. So twenty-three twenty-eights is six hundred and forty-four, which is six hundred and twenty-one plus twenty-three.
And twenty-four twenty-sevens is six hundred and forty-eight, which is six hundred and twenty-one plus twenty-seven. Look at what just happened. Raising one factor by one adds the other factor. That is why the two answers differ, although the two nudges look identical. Neither line needed a second multiplication. Both factors up by one. This is where guessing goes wrong, because the two increases do not simply add. Treat the quantity a plus one as a single thing, and split the other bracket.
That gives a plus one, times b, plus a plus one, times one. Multiply out and it is a times b, plus b, plus a, plus one. Three extra pieces. A strip of b along one edge, a strip of a along the other, and one loose corner where they would meet. That corner is a single dot, and it is the piece everybody forgets. Here the gain is twenty-seven plus twenty-three plus one, which is fifty-one.
Twenty-four twenty-eights is six hundred and seventy-two. Six hundred and twenty-one plus fifty-one. Exactly. Now one factor up by one and the other down by one. Surely those cancel. Split it the same way. A plus one, times b minus one, is a times b, plus b, minus a, minus one. So the change is b minus a minus one. Here that is three, and the product goes up, to six hundred and twenty-four.
Up. Not unchanged. And the sign of that expression depends on which factor is which. Sweeping every pair between minus six and six, one hundred and sixty-nine of them, the product falls in ninety-one cases. It falls exactly when the second factor is not past the first, and it stays put only when the second is exactly one more than the first. A fair objection. All of this was drawn with dots, and you cannot draw minus five rows.
So does any of it survive negative numbers? Take a as minus five and b as eight. Both up by one gives a plus b plus one, which is four. Check it. Minus five eights is minus forty. Minus four nines is minus thirty-six. The gain is four. Take a as minus four and b as minus five. The formula says minus eight, and multiplying out gives minus eight. Nothing new was needed, and nothing was extended.
The letters stood for numbers all along, and splitting holds for whole numbers of either sign. It is worth being exact about what has been established. An identity is an equality between two expressions that holds whenever you replace the letters by numbers. Any numbers. Every time. That is far stronger than an equation true for one value. And here is the part that matters. Substituting three values into an identity does not establish it.
Checking values can only catch a mistake. It never finishes the argument, because there is always another value you did not try. What finishes it is deriving it, and every line so far was derived from the splitting rule. The checks are how you notice you slipped, not why you believe it. So far there have been four separate cases, and that is three too many. Let one factor move by m and the other by n. Both are just numbers, so either can be negative.
Split it twice. A plus m, times b plus n, is a times b, plus a times n, plus b times m, plus m times n. Four pieces, four blocks. The original rectangle, a strip a tall and n wide, a strip m tall and b wide, and a small block m by n in the corner. The increase is everything but the first block. A times n, plus b times m, plus m times n.
Swept across two thousand and twenty-five combinations of factors and shifts, that matched the multiplied-out answer every time. And drop any one of those four pieces and it stops matching, which is how you know none of them is decoration. Now watch the earlier cases fall out of that one line. A plus one, times b minus one, is really a plus one, times b plus minus one. So m is one and n is minus one. The increase is a times minus one, plus b times one, plus one times minus one.
Which is minus a, plus b, minus one. The same three terms as before. There is no separate rule for a decrease. A decrease is a negative shift, and the ordinary sign rules do the rest. Try all four sign combinations here, shifting by one and by two. Up and up gives seventy-five. Up and down gives minus twenty-one. Down and up gives seventeen. Down and down gives minus seventy-one. One statement, four answers.
Here is a question that one statement now makes easy. Push one factor up by two and pull the other down by four. When does the product come back unchanged? Set the increase to zero. A times minus four, plus b times two, plus two times minus four, equals zero. Tidy it and b is two a plus four. That is not one answer but a family, and in the range swept here there are seven.
One and six give six, and three twos give six. Two and eight give sixteen, and four fours give sixteen. The same machinery answers any such question. Down two and up three moves our product by nine. Down three and down four moves it by minus one hundred and sixty-one. One last place this turns up, and it is not where you would expect. Take any calendar month and outline any two by two square of dates.
Say four, five, eleven and twelve. Multiply one pair of corners, four twelves, and you get forty-eight. Multiply the other pair, five elevens, and you get fifty-five. A gap of seven. Try another square anywhere in the month. Across twenty-one squares, every single gap is seven. The reason is the block itself. Its corners are a, a plus one, a plus seven and a plus eight, and multiplying those out cancels the a completely.
What is left is the seven. Change the row width and the gap changes with it. Across nine widths, the gap was the width every time. Count what has been replaced. One factor up. The other up. Both up. One up and one down. Both down. Up by two. Down by four. Every one was a separate rule to remember. They are now one line, with the shifts allowed to be negative.
And each of the four pieces has a picture attached. Two strips and a corner is not a formula to memorise. It is a shape. The corner is the piece worth watching. It vanishes when a shift is zero, and it carries the sign when both shifts are negative. So when someone asks what a nudge does to a product, the honest answer is not a number. It is a question back. By how much, and which factor is the other one?
Because the answer was never about the factor you moved. It was always about the one you left alone.
Where this fits
Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.
Builds on
- The carpenter's problem: how to be sure a frame really is rectangularClass 8 · Ch 4, Quadrilaterals
- Body parts and tally marks: counting before numeralsClass 8 · Ch 3, A Story of Numbers
Comes up again in
- Multiplying two two-term expressions, and where the four terms come fromClass 8 · Ch 6, We Distribute, Yet Things Multiply
- Fast mental multiplication, powered by distributionClass 8 · Ch 6, We Distribute, Yet Things Multiply
- Which added values move the mean, and in which directionClass 8 · Ch 5, Tales by Dots and Lines
Either side of this one
- Cracking a cryptarithm by reasoning about digits, not guessingClass 8 · Ch 5, Number Play