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Chapter 6 · We Distribute, Yet Things Multiply

Fast mental multiplication, powered by distribution

यह वीडियो हिंदी में भी · Watch in Hindi

The distributive property10 min

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10 min.

Also recorded in Hindi.Englishहिन्दी

The one-line methods for multiplying by 11, 99 and 999 are not five tricks. They are one move, used five times.

The idea

The one-line methods for multiplying by 11, by 101, by 1001, by 99 and by 999 are not tricks and there is nothing to remember about them separately. Each is distributivity with the multiplier split as a power of ten give or take one. That particular split is what earns the speed: multiplying by the power of ten only shifts the number sideways, so the two copies you have to add are the same digits standing in different places, and each interior digit of the answer is a sum of two neighbouring digits of the original — before any carry, the answer's leading column holds just the original's leading digit, and its units column the original's units digit, because those two columns have nothing above or below them to pair with (a carry can still raise the leading digit: 3874 × 11 = 42614). What is left to think about is the carry — and that is why the chapter's method is a sequence of steps rather than a single sentence about adding neighbours.

What you should be able to do

  • Split a multiplier such as 11, 101 or 999 as a power of ten plus or minus one, and write the product as a sum or difference of two shifted copies
  • Set out the column addition for a general four-digit number times 11 and say which two digits meet in each column
  • Multiply a number of any length by 11 in one line, managing carries correctly
  • State the general rule for multiplication by 11 in words
  • Adapt the method to 101, and then to 1001 and 10001, saying how the gap between the two copies changes
  • Adapt the method to 99 and 999, where the second copy is subtracted
  • Explain why the neighbour-sum description is incomplete without the carry, using a case where a digit pair exceeds nine
  • Place these methods in their historical setting as iṣṭa-guṇana and name the works that discuss them

Words to know

TermDefinition in one lineFirst introduced
distributive propertythe rule that multiplying a sum is the same as multiplying each part and addingprinted in this chapter (Part I, §6.1, p.137)
thousands placethe position four from the right in a written numberprinted in this chapter (Part I, §6.1, p.143)
hundreds placethe position three from the right in a written numberprinted in this chapter (Part I, §6.1, p.143)
tens placethe position two from the right in a written numberprinted in this chapter (Part I, §6.1, p.143)
units placethe rightmost position in a written numberprinted in this chapter (Part I, §6.1, p.143)
ista-gunanaBrahmagupta's name for fast multiplication built on distributivity, transliterated iṣṭa-guṇanaprinted in this chapter (Part I, §6.1, p.144), set there without diacritics
carrythe amount moved into the next column when a column total reaches tenan added word; not printed in this chapter, which draws the carried digits as small ringed numerals and leaves them unnamed
neighbour sumthe total of two digits standing next to each other in the original numberan added phrasing; the chapter describes the effect and gives it no name
shifted copythe original number multiplied by a power of ten so its digits move leftan added phrasing

Where people slip up

  • "To multiply by 11, write the digit sums between the first and last digits." This is the rule students carry away, and it breaks on the chapter's own example: in 3874 the pair 8 and 7 totals 15, which cannot be one digit of the answer. The chapter's five steps exist to handle exactly that. Demonstrate the failure before giving the repair.
  • "Eleven is special." Nothing about 11 is doing the work; what does the work is that 11 is one past ten. That is why 101, 1001 and 10001 all behave the same way with a wider gap, and why 9 and 99 behave the same way in the other direction.
  • "The rule is for four-digit numbers." The chapter asks for the rule for a number of any length and then hands over a seven-digit input. Any statement of the rule that mentions four digits is not the rule.
  • "Multiplying by 99 needs a new method." It needs the same method with a minus. Splitting 99 as one hundred less one turns the second copy from an addition into a subtraction; the shift is unchanged.
  • "A shortcut is less trustworthy than long multiplication." The column layout is the justification: it shows every partial product and where it lands. Nothing is being skipped, only arranged better.
  • "The zero in the shifted row is a digit of the answer." It is the units place of the number multiplied by ten. In the printed layout it is set in the same style as the letters, and it is the single most likely thing to be misread.
  • "These methods are a recent invention for competitive exams." The chapter names three Indian mathematicians and two verses of one seventh-century work.
Transcript1,392 words

Here is a multiplication, and a condition attached to it. Three thousand eight hundred and seventy-four, times eleven. The condition is that you write the answer straight down, in one line, without setting out a column sum underneath. Most people meet this as a trick, learn the trick, and never find out why it works. It is not a trick, and there is nothing here to memorise. The answer, since you will want it, is forty-two thousand six hundred and fourteen.

By the end of this you will be able to write that down as fast as you can say it, and say why it is right. And the same single idea will handle a hundred and one, a thousand and one, ninety-nine and nine hundred and ninety-nine. Start by refusing to treat eleven as one thing. Eleven is ten plus one. So the product is the number, times ten plus one.

Multiplying by a sum means multiplying by each part and adding the results. Times ten gives thirty-eight thousand seven hundred and forty. Times one gives the number straight back. Add those two and you have the answer, and nothing has been skipped or approximated. That is the whole method. Everything that follows is about doing that addition without writing it out. You are always allowed to split the multiplier. Splitting it into ten and one is what earns the speed.

Multiplying by ten does not really multiply anything. It slides the digits one place to the left and puts a zero underneath. Three, eight, seven and four are still there, in the same order, standing one place further along. So the two things you have to add are the same digits, in different places. Split eleven as six plus five instead, and you have two genuine multiplications and a harder problem than you started with.

A power of ten is the only split that turns a multiplication into a slide. Nothing about eleven is special. What is special is being one place away from a power of ten. Write the two copies one above the other, the shifted one on top. Three, eight, seven, four, zero. And underneath, pushed one place to the right, three, eight, seven, four. That zero is not a digit of the answer. It is the units place of the number after it slid.

Now stop reading across the rows and read down the columns instead. The units column holds four, and nothing else, because there is nothing beneath it to pair with. The next column holds four and seven: the units digit and the tens digit of the original, side by side. Every column in the middle holds two digits of the original that were next-door neighbours. Do it once with letters and it stops being about this particular number.

Call the four digits, reading from the left, d, c, b and a. The top row is d, c, b, a, zero. The bottom row, pushed one place right, is d, c, b, a. Read the column totals from the left: d, then c plus d, then b plus c, then a plus b, then a. The two outer ones are copies. The leading digit of the answer is the leading digit of the number, and the units digit is the units digit.

They are copies because those two columns have nothing to pair with. Everything in between is the total of two neighbours. Which gives the rule everybody carries away: the first digit, then the neighbour totals, then the last digit. Try it here. Three and eight make eleven. Eleven is not a digit. It will not fit into one column of the answer. The other two pairs are no better. Eight and seven make fifteen, and seven and four make eleven again.

So that rule is not wrong about where the answer comes from. It is silent about what happens when a column overflows. Sometimes nothing overflows and it works perfectly. Three thousand two hundred and forty-one times eleven is thirty-five thousand six hundred and fifty-one, straight off the neighbours. Across every number from ten to nine hundred and ninety-nine it is right three hundred and seventy-five times out of nine hundred and ninety, and the smallest one it gets wrong is nineteen.

The repair is to do the addition column by column, from the right, and carry. Units column: four. Write four. Next: four and seven make eleven. Write the one and carry the one. Next: seven and eight make fifteen, and the carried one makes sixteen. Write six, carry one. Next: eight and three make eleven, and the carried one makes twelve. Write two, carry one. Last: three, and the carried one, is four. Three of the five columns handed something on.

The running answer goes four, fourteen, six hundred and fourteen, two thousand six hundred and fourteen, forty-two thousand six hundred and fourteen. Now state it for a number of any length, because a rule that mentions four digits is not the rule. Write the units digit of the number as the units digit of the answer. Then work leftwards, writing each neighbour total in turn, and carry whenever a total reaches ten.

When the pairs run out, write the leading digit plus whatever is still being carried. That is all of it, and it does not care how long the number is. Ninety-four times eleven is one thousand and thirty-four. Four hundred and ninety-five times eleven is five thousand four hundred and forty-five. A seven-digit number defeats anyone who memorised a four-digit shape, and this rule does not notice the difference. A hundred and one is one past a hundred, in exactly the way eleven is one past ten.

So the number times a hundred and one is the number slid two places, plus the number. Stack those, and the gap between the copies is two places instead of one. Now the column totals read d, then c, then b plus d, then a plus c, then b, then a. The pairs are no longer neighbours. They stand two apart, because the copies stand two apart. And four digits survive untouched at the ends instead of two.

Eighty-nine times a hundred and one is eight thousand nine hundred and eighty-nine, which is the number written twice. Push the gap out again and nothing changes except the gap. A thousand and one slides the copy three places, so the pairs stand three apart. Ten thousand and one slides it four. Every extra place leaves two more digits of the answer untouched at the ends. One thousand one hundred and eleven times a thousand and one is one million, one hundred and twelve thousand, one hundred and eleven.

Two hundred and sixty-five thousand eight hundred and thirty-one times a thousand and one is two hundred and sixty-six million, ninety-six thousand, eight hundred and thirty-one. Which you can very nearly read straight off: the number, then the number again, with the overlap tidied up in the middle. Now go the other way. Ninety-nine is a hundred, less one. So the second copy is taken away instead of added, and the slide is unchanged.

Nine thousand seven hundred and thirty-four times ninety-nine is nine hundred and seventy-three thousand four hundred, less nine thousand seven hundred and thirty-four. Nine hundred and sixty-three thousand six hundred and sixty-six. Nine hundred and ninety-nine is a thousand less one, and behaves the same way with a wider slide. Twenty-three thousand four hundred and seventy-eight times it is twenty-three million, four hundred and fifty-four thousand, five hundred and twenty-two.

So there are not five methods here. There is one move. Write the multiplier as a power of ten, give or take one. Nine, eleven, ninety-nine, a hundred and one, nine hundred and ninety-nine, a thousand and one: the same move each time, with a different slide and a different sign. Methods built this way were worked on at length by Brahmagupta, in six hundred and twenty-eight. By Sridharacharya, around seven hundred and fifty. And by Bhaskaracharya, around eleven fifty.

Brahmagupta's name for them was ishta-gunana, which means multiplication by a chosen amount. Chosen is the important word. You are picking the split that makes the work easy. Multiplying a sum is the same as multiplying each part and adding. Choosing the parts well is where the speed lives.

Where this fits

Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.

Builds on

Either side of this one

The book

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