PrepShorts · Study sheet · Class 8 Mathematics · Chapter 4, Exploring Some Geometric Themes
Chapter 4 · Exploring Some Geometric Themes
Nets: which flat shapes fold into which solid
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A net is not a picture of a solid. It is the solid's surface, cut along enough edges to lie flat.
The idea
A net is not a picture of a solid. It is the solid's surface, cut along enough edges to lie flat — which means folding it back is an operation that moves the material without stretching it. That single fact turns "is this a net?" from a guess into a test: the piece must have the right faces in the right numbers, and folding must send every cut edge onto exactly one partner with no two faces landing in the same place. Overlap, not the number of squares, is what disqualifies a candidate. And the same fact explains why some solids have many nets, why a sphere has none, and why the count of a cube's nets is a finite number worth arguing about.
What you should be able to do
- Define a net as the surface of a solid unfolded onto a plane, and say what the definition excludes
- Identify faces, edges and vertices of a given solid and count each
- State the general definition of a prism and of a pyramid, and derive the face, edge and vertex counts for an n-sided base
- Decide whether a given flat arrangement of squares folds into a cube, and give a reason for each rejection
- Explain what "two nets are the same" means when rotation and reflection are allowed, and why the count 11 depends on that convention
- Construct the net of a cylinder and state the dimensions of its rectangle
- Explain why unrolling a cone gives part of a circle, using the fact that the apex is equidistant from every point of the base circle
- Explain why a sphere has no net, in terms of what folding can and cannot do
- Distinguish the net proper from the flaps added to make a physical model
Words to know
| Term | Definition in one line | First introduced |
|---|---|---|
| net | the flat shape got by unfolding a solid's surface onto a plane, which folds back into the solid | printed in this chapter (Part II, §4.2, p.79, set in bold) |
| face | a flat surface forming part of a solid's boundary | printed in this chapter (Part II, §4.2, p.78, set in bold) |
| edge | a line segment forming a side of a face | printed in this chapter (Part II, §4.2, p.78, set in bold) |
| vertex | a point where edges meet | printed in this chapter (Part II, §4.2, p.78, set in bold as vertices) |
| prism | a solid with two congruent polygons as opposite faces and parallelograms for all its other faces | printed in this chapter (Part II, §4.2, p.79, set in bold) |
| pyramid | a solid built from a polygon and one extra point off that polygon's plane, with edges running from the point to each corner of the polygon | printed in this chapter (Part II, §4.2, p.79, set in bold) |
| tetrahedron | another name for a triangular pyramid | printed in this chapter (Part II, §4.2, p.79, set in bold) |
| regular tetrahedron | a tetrahedron all of whose faces are equilateral triangles | printed in this chapter (Part II, §4.2, p.81, set in bold) |
| octahedron | the eight-faced solid made by joining two square pyramids base to base | printed in this chapter (Part II, §4.2, p.83, set in bold) |
| dodecahedron | the solid all of whose faces are pentagons | printed in this chapter (Part II, §4.2, p.83, set in bold) |
| parallelopiped | the chapter's spelling for a solid bounded by six parallelograms | printed in this chapter (Part II, §4.2, pp.77–78; the chapter also prints the more usual parallelepiped on Part II p.92) |
| congruent | identical in shape and size | printed in this chapter (Part II, §4.2, p.79) |
| flaps | the extra tabs added to a cut-out so faces can be stuck together | printed in this chapter (Part II, §4.2, p.80, set in single quotes) |
| slant height | the distance from a cone's apex to a point on its base circle, the chapter's l | an added term; the chapter labels the length l on the figure and does not name it |
| developable | able to be flattened without stretching or tearing | an added term, not printed in this chapter |
Where people slip up
- "Six squares joined edge to edge always fold into a cube." Candidates (i) and (v) on Part II pp.80–81 have exactly six squares each and neither folds. The count is necessary and nowhere near sufficient.
- "A candidate fails because a face is missing." It fails because two faces land in the same place, which leaves a different face missing as a consequence. Name the overlap, not the gap — that is the diagnostic that generalises.
- "There is one net per solid." A cube has 11, an octahedron 11, a dodecahedron 43,380, a regular tetrahedron 2. The chapter prints all four numbers.
- "A net includes the flaps." The chapter says explicitly that it does not. The flaps are a manufacturing aid; the net is the unfolded surface.
- "11 is just a fact to memorise." It is a fact relative to a convention: two arrangements are counted as one if a rotation or a flip relates them. Change the convention and the number changes. The chapter prints three arrangements side by side precisely to fix the convention before stating the number.
- "The cylinder's rectangle has the diameter as its long side." It has the circumference, 2πr, which is over three times the diameter. This is the single most common numerical error in cylinder nets.
- "Unrolling a cone gives a triangle." It gives a sector — a piece of a disc. The curved edge is forced: every point of the base circle is at distance l from the apex, so in the flattened piece they all sit on a circle of radius l.
- "A sphere has a net, we just haven't found it." It has none, and the reason is structural rather than a failure of ingenuity. Say the reason: folding does not stretch.
- "Prism and pyramid are just names for particular shapes." They are general definitions with a parameter. Once you can count faces, edges and vertices for the n-sided case, the 10-sided case needs no picture — which is the point of the chapter's two questions on Part II p.79.
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Worked answers to this chapter’s exercises · this video explains Figure it Out · 3 Q1, Figure it Out · 3 Q2, Figure it Out · 3 Q3
Transcript1,449 words
Here is a cube. Cut along enough of its edges and the whole surface opens out and lies flat. That flat piece is called a net. A net is not a drawing of the solid. It is the solid's surface, moved. Nothing was stretched and nothing was torn, so every distance along the surface is still what it was. Which means folding it back up is not a guess. It is an operation.
It either works, or it fails for a reason you can point at. We need three words first, and they are the obvious three. A face is one of the flat surfaces the solid is made of. An edge is where two faces meet. A vertex is a point where edges meet. Count them on a cube. Six faces. Twelve edges: four round the top, four round the bottom, four uprights. Eight vertices.
Six, twelve, eight, counted off the solid rather than remembered. A tetrahedron gives four, six and four. An octahedron gives eight, twelve and six. And for all three, faces plus vertices, less edges, comes to two. Two families are worth defining properly. A prism has two identical polygons facing each other, and flat pieces joining them all the way round. A pyramid has one polygon and one extra point off it, with an edge from that point to every corner.
Now count without drawing. Take a prism whose ends have n sides. Faces: the two ends, plus one for each side of an end. That is n plus two. Edges: n round each end, and n uprights. Three n. Vertices: n at each end. Two n. So a prism on ten-sided ends has twelve faces, thirty edges and twenty vertices. A pyramid on n sides has n plus one faces, two n edges and n plus one vertices. On ten sides, eleven, twenty and eleven.
And the check: put n equal to four into the prism and you get six, twelve and eight. The cube. Back to the flat piece. Six squares, joined edge to edge. Watch one square at a time as it folds up. Front. Right. Back. Left. The row of four has wrapped into a band, and the two squares left over drop onto the top and the bottom. Six squares, six faces, one each. That is the whole test.
The little tabs on a cardboard box are for the glue. The net is the surface, and the surface has no tabs. When you draw one, the arithmetic checks it before you cut, because the faces come in three matching pairs. A box five by three by one has a surface of forty-six. One six by three by two has seventy-two. Now six flat pieces. Every one of them is six squares joined edge to edge.
Which of them fold into a cube? Four of them work. Two rows of three, overlapping in a single column, folds. A staircase of three dominoes, each stepped one across from the one before, folds. A row of four with one square above the third and one below the third folds. And a row of four with one above the third and one below the second folds too. The other two do not. All six had exactly six squares, so the count is not what tells them apart.
So what actually goes wrong? Take the first failure. A row of four with two squares sitting above its left end. The row wraps into a band, and the first of the two lands on the top. The second comes down onto a face of the band that already has a square on it. Two squares, one face. And the arithmetic agrees: five faces get covered, and one is left bare.
It is tempting to call that a missing face. Do not. The bare face is the consequence. The fault is the overlap. The other failure does the same thing, with two squares stacked below the second column. A row of four always wraps into a band of four side faces. That part never fails. So take a row of four, put one square anywhere above it, and one square anywhere below it.
The one above becomes the top. The one below becomes the bottom. It folds. Every time. Six of a cube's eleven nets are of exactly that shape. Which leaves the harder question. Why eleven? Eleven is not a fact standing on its own. It is a fact about a convention. Two flat pieces count as the same net if you can turn one round, or flip it over, and land on the other.
Change the convention and the number changes with it. With it fixed, the count is done properly by listing. There are thirty-five different shapes you can build from six squares joined edge to edge, once turns and flips are not counted as different. Then fold every one of them. Eleven close up into a cube. The other twenty-four do not. Not eleven because somebody said so. Eleven because thirty-five were tried.
Here is that number again, from an argument that never lays anything flat. Cutting a cube open is choosing which of its edges to cut. Its faces meet along twelve joins. What stays joined has to reach every face and must not run round in a circle, so you keep five of the twelve. There are three hundred and eighty-four ways to do that. But a cube has forty-eight turns and flips of its own, and two cuts related by one of those give the same net.
Sort the three hundred and eighty-four into groups on that basis, and eleven groups remain. Two arguments, no machinery in common, the same eleven. Run it on a regular tetrahedron and you get two. Run it on an octahedron and you get eleven again. Not a coincidence. An octahedron's eight faces meet in exactly the pattern a cube's eight corners do. Now the tetrahedron. Four equilateral triangles, and four candidates.
The first is a big triangle cut into four by joining the midpoints of its sides. Fold the outer three up and they meet at a point. A net. The third is four triangles in a straight strip. Roll it round and it closes. That is the other one. The second is a strip of three with a fourth bent back off the end. Four triangles, the right number. And two of them land on the same face. Same fault as the squares.
The fourth candidate has five triangles for a four-faced solid, which no amount of folding will fix. Two nets out of four, and the two failures fail for completely different reasons. Two of these surfaces have no flat faces at all, and they still have nets, because they were rolled up rather than folded. Slit a tin down its side and the curved part unrolls into a rectangle. One side of that rectangle is the height. The other is not the diameter, and it is not the radius.
It is the whole way round the base. Two pi r. So the surface of a tin is that rectangle and two circles. Radius three and height five gives forty-eight pi. Now the cone. Slit it up its slant and unroll it. Every point of the base circle is the same distance from the apex, so once it lies flat they all sit on a circle of that radius. You get a piece of a disc. Not a triangle.
How much of the disc? The radius divided by the slant. The slant is always longer, so it is never the whole of it. Last, a ball. Try to wrap one in paper with no wrinkle, no gap and no overlap. You cannot, and the reason is the one we started with. Folding moves paper without stretching it, so it cannot change how much angle sits at a point. Flat paper has a full turn, three hundred and sixty degrees, at every point inside it.
At a cube's corner, three squares meet. Two hundred and seventy degrees arrive where three hundred and sixty would lie flat. The corner is ninety degrees short, and that shortfall is what the fold used up. A tetrahedron's corner is short by a hundred and eighty. An octahedron's by a hundred and twenty. Add the shortfalls over a whole solid and you get seven hundred and twenty degrees. Cube, tetrahedron, octahedron, every prism, every pyramid.
A ball has no corners. It is smooth everywhere, so there is nothing for the fold to take up. A net is not a picture of a surface. It is the surface, and a surface either goes flat or it does not.
Where this fits
Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.
Builds on
- Constructing a solid in your head from a descriptionClass 8 · Ch 4, Exploring Some Geometric Themes
Comes up again in
- The shortest path across a cube, found by flattening itClass 8 · Ch 4, Exploring Some Geometric Themes
- Front, top and side views, and what each one losesClass 8 · Ch 4, Exploring Some Geometric Themes