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Chapter 1 · A Square and A Cube

Square roots, and the prime-factor test for a perfect square

यह वीडियो हिंदी में भी · Watch in Hindi

Square numbers10 min

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10 min.

Also recorded in Hindi.Englishहिन्दी

A square root is not a strange operation — it is a length. Give a square an area of 49 and its side is 7.

The idea

Whether a number is a square is a question about its prime factorisation, and it is answerable because that factorisation is unique. If a number is m × m then every prime m owns has been contributed twice over, so each prime turns up an even number of times; deal those primes into two matching piles and one pile, multiplied out, is m. All three of the chapter's tests hand you the root — the list stops at 24² = 576, and the odd numbers run out at the ninth step, which is the root of 81. What separates them is cost and reach: the first two are searches about as long as the root is big, which is why the chapter calls 729 tedious, while factorisation does not search at all and answers a question the other two cannot even pose — what is the smallest number you could multiply by to complete the pairs. And when the answer is no, estimation still pins the number between two squares you know — which is all Akhil needs to cut his handkerchief.

What you should be able to do

  • Recover the sidelength of a square from its area
  • State the definition of a square root and identify both integer roots of a perfect square
  • Read and write the radical symbol, and state the chapter's convention of keeping only the positive root
  • Decide whether a given number is a perfect square by prime factorisation, and produce its root from the same working
  • Explain why the pairing of primes is decisive — that is, why unique factorisation is what makes the test valid
  • Compare the three tests the chapter gives and say what each does and costs
  • Estimate the square root of a number that is not a perfect square by bracketing it between known squares
  • Use the units digit and a midpoint square to narrow a bracket
  • Apply an estimated root to a practical cutting or fitting problem

Words to know

TermDefinition in one lineFirst introduced
square rootthe number whose square is the given numberprinted in this chapter (Part I p.8)
radical symbolthe sign √ written before a number to mean its square rootan added name for the sign; the chapter prints the sign itself and calls it a symbol (Part I p.8)
integer square rootsthe two whole-number roots of a perfect square, one of each signprinted in this chapter (Part I p.8)
prime factorisationa number written as a product of primesprinted in this chapter (Part I p.9)
perfect squarea square of a natural numberprinted in this chapter (Part I p.4)
estimateto find a value close enough to a root without computing it exactlyprinted in this chapter (Part I p.9)
unique factorisationthat a number's prime factorisation is the only one it hasan added term; the chapter relies on the fact and never states it
even exponenta prime occurring an even number of times in a factorisationan added phrasing; this chapter argues with pairs and groups, not exponents

Where people slip up

  • "√64 has one value." A perfect square has two integer roots. The chapter keeps the positive one by an announced convention, and a student who has not heard the announcement will later be confused by −8.
  • "The radical symbol means the positive root by definition." In this chapter it is a working agreement stated on Part I p.8, and a few lines earlier on the same page it writes √64 = ±8.
  • "It ends in 6, so it is a square and its root ends in 6." Two errors in one: the ending never confirms squareness, and even when the number is a square the root could end in 4 or in 6.
  • "Prime factorisation is just a third way of checking." All three produce the root, so that is not what separates them. Factorisation is the one that does not have to search — the other two take roughly as many steps as the root is large, which is why the chapter calls 729 tedious by subtraction — and it is the only one that also tells you the smallest multiplier that would complete the pairs, which is exactly what item 6 asks for. Make that comparison explicit; it is the point of sections 5 to 9.
  • "An unpaired prime can be removed." Item 6 asks you to multiply by the missing factor. Taking a prime out changes the number; supplying its partner is what completes the pairs.
  • "156 fails because 13 is large." It fails because 13 appears once. Size has nothing to do with it.
  • "45² = 40² + 5²." The cross term 2 × 40 × 5 is exactly what the chapter spells out, and it is the term students drop.
  • "If a number is not a perfect square, its root is useless." Akhil's problem is answered entirely by a bracket, with no exact root anywhere in it.
  • "Estimating means guessing." Each of the chapter's five steps narrows a stated interval. Show the interval shrinking.
Transcript1,397 words

Here is a square, and its area is forty-nine. Not its side. Its area. So what is the side? Seven, because seven sevens are forty-nine. That is all a square root is. You are running a squaring backwards. Squaring takes a side and hands you an area. A square root takes the area and hands you back the side. So a root is not a strange operation. It is a length.

There is a catch, and it turns up straight away. Eight times eight is sixty-four. But minus eight times minus eight is also sixty-four, because a negative times a negative comes out positive. So sixty-four has two square roots. Eight, and minus eight. Every square number does, one of each sign. Nought is the only one with a single root. There is a sign for a square root, and from here on we will let it mean the positive one.

That is a decision, not a discovery. The minus eight has not gone anywhere. We are agreeing not to write it. Now two numbers. Five hundred and seventy-six, and three hundred and twenty-seven. One of them is settled with no work at all. A square can only end in six of the ten digits. Nought, one, four, five, six, nine. Three hundred and twenty-seven ends in seven. So it is not a square, and we are finished with it.

Five hundred and seventy-six ends in six, which is allowed. But allowed is not the same as yes. One hundred and fifty-six ends in six too, and that is not a square either. A last digit can throw a number out. It can never let one in. So how do we settle five hundred and seventy-six? The obvious way. Write squares out until you get there. Twenty squared is four hundred. Twenty-one squared, four hundred and forty-one. Twenty-two, four hundred and eighty-four.

Twenty-three, five hundred and twenty-nine. Twenty-four. Five hundred and seventy-six. There it is, so the root is twenty-four. That worked. But notice the cost. We walked all the way up to twenty-four, and the bigger the number, the longer the walk. There is a second way, and it is prettier. Take eighty-one and subtract the odd numbers from it, in order. Eighty-one take one is eighty. Take three, seventy-seven. Take five, seventy-two.

Seven, sixty-five. Nine, fifty-six. Eleven, forty-five. Thirteen, thirty-two. Fifteen, seventeen. Seventeen, nothing. It landed exactly on nought, so eighty-one is a square. And count the subtractions. Nine of them, and nine is the root. That is a lovely test. But it is the same bargain: seven hundred and twenty-nine takes twenty-seven steps. So we have two tests, and they have the same shape. Each one walks, and the walk is about as long as the root.

For a three-digit number that is nothing. For a six-digit one you are counting for a very long time. So stop asking what the number is near. Ask what it is made of. Every whole number breaks into primes. Three hundred and twenty-four breaks into two, two, three, three, three, three. Six primes. Now deal them out like cards into two piles, one at a time, turn and turn about.

Two, left. Two, right. Three, left. Three, right. Three, left. Three, right. Now look at the piles. Two, three, three. And two, three, three. They are identical. Multiply one of them out. Two threes are six, and six threes are eighteen. Eighteen. And eighteen eighteens are three hundred and twenty-four. The root came out of the pile. We never went looking for it. So why does that work? Not why did it work here. Why it has to.

Suppose a number is something times itself. Then whatever primes that something is built from, the number has every one of them twice, once from each copy. So every prime turns up an even number of times, and that is exactly what lets you split them into two matching piles. It runs the other way too. If every prime turns up an even number of times, the piles have to come out the same, and one pile times the other gives you the number back.

But something is holding all of that up, and it is easy to walk straight past. A number has only one set of primes. Only one. Break it apart however you like, in any order, and you land on the same primes every time. That is what makes this a test instead of a lucky arrangement. If a number had two different sets of primes, it could pass the pairing in one of them and fail in the other, and the answer would depend on how you did the breaking.

It does not. So the piles decide it. Now one that fails. One hundred and fifty-six. Two, two, three, thirteen. Deal them out. Two and three on the left, two and thirteen on the right. The piles are different, so it is not a square. And look at which primes are stranded. Not only the thirteen. The three as well. Both of them turn up once. It is tempting to say it failed because thirteen is big. It did not.

Thirteen twice over is one hundred and sixty-nine, and that is a perfect square. Twelve is two, two, three, and it fails on the three. Size has nothing to do with it. Odd tallies do. Here is what the walking tests cannot even ask. Nine thousand four hundred and eight. Not a square, and either walk would tell you so, eventually. But break it up. Six twos, one three, two sevens.

The twos pair off. The sevens pair off. The three is on its own. So we know precisely what is missing. It wants another three. Multiply by three and you get twenty-eight thousand two hundred and twenty-four, which is a square, with a root of one hundred and sixty-eight. Multiply, mind. Not remove. Taking the three out lands on a square as well, but on a different number, and nobody asked for a different number.

And when the answer really is no, you can still pin the number down. One thousand nine hundred and thirty-six. Forty squared is one thousand six hundred. Fifty squared is two thousand five hundred. So the root is somewhere between forty and fifty. It ends in six, and a square only ends in six when its root ends in four or in six. So it is forty-four, or forty-six. Try the one in between. Forty-five squared.

Careful here. It is not one thousand six hundred plus twenty-five. Forty and five, squared, gives one thousand six hundred, plus twenty-five, plus two lots of forty fives. Four hundred more. Two thousand and twenty-five. That has overshot, so the root is below forty-five, and forty-six is out. Forty-four. And forty-four squared is one thousand nine hundred and thirty-six. When there is no root at all, the bracket is the answer.

Two hundred and fifty. Fifteen squared is two hundred and twenty-five, sixteen squared is two hundred and fifty-six. So it lies between fifteen and sixteen, and much nearer sixteen. Six above it, twenty-five below. Here is what that is good for. Someone has a square of cloth with an area of one hundred and twenty-five, and wants to cut a fifteen by fifteen square out of it. One hundred and twenty-five sits between eleven squared, one hundred and twenty-one, and twelve squared, one hundred and forty-four.

So the biggest whole square that fits has a side of eleven. Not fifteen. Fifteen would need two hundred and twenty-five. That question is now completely answered, and no exact root appeared anywhere in it. One last picture. A panel of motifs, nine across and nine down. Every motif is a block of tiny squares, five by five. So how many tiny squares are there altogether? Eighty-one motifs, twenty-five in each.

Two thousand and twenty-five. Which we have already met. It is forty-five squared, the number that turned up while we were bracketing. And it had to be a square. Eighty-one is a square, twenty-five is a square, and a square times a square is always a square. But take the total apart and you never need to notice that. Three, three, three, three, five, five. Deal them out. Three, three, five. And three, three, five.

Forty-five. Two matching piles, and the root falls out.

Where this fits

Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.

Builds on

Comes up again in

Either side of this one

The book

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