PrepShorts · Study sheet · Class 7 Mathematics · Chapter 4, Another Peek Beyond the Point
Chapter 4 · Another Peek Beyond the Point
Dividing when the dividend has a decimal
This video could not be loaded. Reload the page to try again.
Sign in with Google10 min.
Keep your place in this chapter — sign in, it’s free.Sign in
Everybody can divide by ten. Almost nobody can say why moving the point one place left is the right thing to do.
The idea
A point in the dividend changes nothing about the procedure — it only changes where the procedure starts. Read 9.5 as nine Ones and five Tenths and the first regrouping is already happening below the Ones, so the quotient gets its point before anything unfamiliar has occurred. Seen that way the divide-by-ten shortcut stops being a separate trick to remember: every place-value unit drops one rank when it is shared among ten, and a whole column of digits dropping one rank at once is exactly what "move the point one place left" looks like from the outside.
What you should be able to do
- Divide a decimal by 10, 100 or 1000 and say where the point ends up
- Explain the point-shifting rule from what division does to each place value, rather than asserting it
- Work a division-by-powers-of-ten table backwards: given a result, recover the starting decimal
- Divide a decimal dividend by a whole number using long division, placing the point correctly
- Handle a dividend smaller than 1, where the quotient opens with zeros
- Say what a zero in the Tenths place of a quotient is recording
- Predict how a quotient changes when the dividend is divided by ten but the divisor is left alone
Words to know
| Term | Definition in one line | First introduced |
|---|---|---|
| dividend | the number being divided — the one carrying the point in this topic | printed in §4.3, Part II, p.86 |
| divisor | the number you divide by | printed in §4.3, Part II, pp.74–75 |
| quotient | the answer to a division | printed in §4.3, Part II, pp.74–83 |
| decimal dividend | the phrase heading this stretch of the chapter | printed in §4.3, Part II, p.82 |
| reciprocal | the fraction you turn a divisor upside down to get | printed in §4.3, Part II, p.74 |
| decimal point | the mark whose position the division rule moves | printed in §4.1, Part II, p.68 |
| regroup | to trade one unit of a place for ten of the place below | printed in §4.3, Part II, pp.82–83 |
| place value | the value a digit carries because of its column | printed in §4.3, Part II, pp.76–78 |
| Ones | the place immediately left of the point | printed in §4.3, Part II, pp.82–83 |
| Tenths | the first place right of the point | printed in §4.3, Part II, pp.82–83 |
| Hundredths | the second place right of the point | printed in §4.3, Part II, pp.82–83 |
| Thousandths | the third place right of the point | printed in §4.3, Part II, pp.82–83 |
| long division | the book's own name for the place-value procedure | printed in bold in §4.3, Part II, p.78 |
| equivalent fraction | the alternative route the chapter keeps offering as a check | printed in §4.3, Part II, pp.76, 80 |
| leading zero | the explanation's name for a zero that holds an empty place open in front of the first significant digit | an added term, not printed in this chapter |
Where people slip up
- "When the dividend has a point, put the point in the answer above it." That recipe happens to work for a whole-number divisor and gives no reason why. Ask instead which step regrouped Ones into Tenths — the answer is the same and it survives into the next topic, where the divisor has a point and the recipe breaks.
- "Dividing by 10 moves the digits, and dividing by 0.1 also moves the digits, so the direction does not matter." The chapter's rule is explicitly leftward for division by 10, 100 and 1000. Which way it goes is the whole content of the rule, and Q4 on Part II p.87 asks the student to fill in a divisor that produces a larger answer.
- "A zero in the quotient means nothing happened, so it can be left out." 0.06 divided by 5 has a zero in the Tenths place recording that no Tenths could be handed out. Delete it and the answer is ten times too big.
- "You need a new method once the dividend has a point." The subheading announcing a decimal dividend is followed by two examples worked in exactly the layout of the previous four pages. The novelty is in the dividend, not in the method.
- "3.9 divided by 100 has two decimal places, because 100 has two zeros." It has three. Counting zeros tells you how far the point moves, not how many places the answer ends up with — the dividend's own places are still there underneath.
- "Dividing always makes a number smaller, so 0.06 divided by 5 must be nearly nothing." It is smaller here, because 5 is bigger than 1. The general claim is taken apart in Dividing when the divisor has a decimal, and it should not be reinforced here.
Ask your teacher a person
Your teacher reads this and writes back, usually within a day. For an instant answer, use Ask the video in the sidebar.
Your class sees the question and the answer. Only your teacher sees that it was you.
No questions on this topic yet.
Worked answers to this chapter’s exercises · this video explains Figure it Out · 2 Q3, Figure it Out · 2 Q4, Figure it Out · 3 Q7, Figure it Out · 3 Q10, Figure it Out · 4 Q1
Transcript1,442 words
A ribbon three point nine metres long, to be cut into ten equal pieces. How long is each piece? You can feel the answer coming. Three point nine, shared among ten, is nought point three nine. Each piece is thirty-nine centimetres. And almost everybody gets that right by moving the point one place left, without ever being able to say why that works. So let us find out why — because the reason turns out to be the reason everything else here works too.
Take the point off first. Three point nine is thirty-nine tenths. Thirty-nine over ten. And dividing by ten is the same as multiplying by one tenth. So we have thirty-nine over ten, times one over ten. Tops together, bottoms together. Thirty-nine over a hundred. Watch what actually happened there. The top never changed. Thirty-nine went in and thirty-nine came out. The only thing that moved was the bottom, which picked up a zero.
Thirty-nine over a hundred is nought point three nine. Now cut the same ribbon into a hundred pieces instead. Same start. Thirty-nine over ten, times one over a hundred. Thirty-nine over a thousand. The top still has not changed. The bottom has picked up two zeros this time instead of one. Nought point nought three nine. Three point nine centimetres per piece. And here is a trap worth stopping on. A hundred has two zeros, so it is tempting to say the answer has two decimal places.
Count them. Nought point nought three nine has three. The two zeros tell you how far the point travels. They do not tell you where it ends up, because the one place three point nine already had is still there underneath. So look at what the shortcut is actually doing. Three point nine. Nought point three nine. Nought point nought three nine. Three, nine. Three, nine. Three, nine. The digits never move. They never even change.
What changes is what each one is worth. The three was three ones, then three tenths, then three hundredths. Every digit dropped one rank, and then another, because that is what sharing among ten does to a place-value unit. A whole column of digits dropping one rank at once — with the digits standing still, that is exactly a point moving one step left. It is not a separate trick. It is the same regrouping, applied to every column at once.
That was checked across eight thousand cases, and the digits came out identical every time. So we can fill in a whole table without doing any dividing at all. Start with eighteen point seven. Divided by ten, one point eight seven. By a hundred, nought point one eight seven. By a thousand, nought point nought one eight seven. By ten thousand, nought point nought nought one eight seven. One, eight, seven. All the way down. Only the point is walking left.
Twenty-one point one does the same thing. Two point one one, then nought point two one one, and on. And so does nought point one three, which starts below one already and just keeps going. Nought point nought one three. Nought point nought nought one three. The zeros in front are holding the empty places open. But two of the rows are not given a starting number at all. One of them says only this: divided by a hundred, the answer is two point one four six.
So what did it start as? Run the arrow the other way. If dividing by a hundred moved the point two places left, then getting back means moving it two places right. Two point one four six becomes two hundred and fourteen point six. Check it. Two hundred and fourteen point six, divided by a hundred, is two point one four six. It works. The last row gives even less. Divided by ten thousand, the answer is nought point nought nought five eight.
Four places right. Five, eight — and it lands as a whole number. Fifty-eight, with no point at all. Which raises a fair question. If fifty-eight has no point, where does the rule start? At the right-hand end. A whole number is a decimal whose point has nothing after it, so we do not write it. One hundred and twenty-three divided by ten. Put the point at the end, step it once left. Twelve point three.
Twelve divided by a thousand is more interesting. Three steps left, but only two digits. So zeros get written in front to hold the empty places open. Nought point nought one two. They are not padding. They are place holders, and leaving one out makes the answer wrong by a factor of ten. Same digits, same rule. It never mattered whether the number started with a point or not. Now the harder-looking case. Nine and a half kilograms of sugar, packed equally into four bags.
Nine point five, divided by four. And four is not ten, so no shortcut is available. This has to be done properly, by sharing out place by place. And notice something before we start. Nine point five has an ones column and a tenths column, and no tens column at all. Nine ones between four is two each, with one one left over. That one becomes ten tenths, and five tenths are already sitting there, so fifteen tenths.
Fifteen between four is three each, three tenths left. Those become thirty hundredths. Seven each, two hundredths left, which become twenty thousandths. Five each, and nothing left. Two point three seven five kilograms in every bag. Now, was any of that new? Look at where the point came from. It went in when one one became ten tenths — the same test as always. The only difference is when that happened.
Dividing a four-digit whole number, that crossing comes at the fifth step out of six. You work through thousands, hundreds, tens and ones first. Dividing nine point five, it comes at the second step out of four. Same event. Same method. It simply arrives sooner, because there are fewer columns above the point to get through. A point in the number you are dividing does not change the procedure at all. It changes where the procedure starts.
Push that as far as it goes. Nought point nought six, shared among five. The whole number is already under one, so the sharing starts below the ones before anything at all has happened. Read it out in places. Zero ones. Zero tenths. Six hundredths. Zero ones between five is zero each. Nothing to share and nothing left over. Zero tenths between five is zero each as well. Six hundredths between five is one each, with one hundredth left.
That becomes ten thousandths, which is two each, and nothing remains. Nought point nought one two. Look hard at that answer, because it contains something easy to throw away. There is a zero sitting in the tenths place. It is very tempting to read that as nothing happening, and to leave it out. But it is not nothing. It is a record. It says that when the tenths came round, there were none to hand out.
Take it away and you get nought point one two. Which is ten times too big. Nought point one two, times five, is nought point six — not nought point nought six. A zero inside a number is not a spacer. It is the statement that this place is empty, and every place left of it has been dealt with. It is the one digit in an answer that people delete, and it is load-bearing.
One last thing, and it is the payoff. Divide one hundred and thirty-two by four. Thirty-three. Now thirteen point two by four. Three point three. One point three two by four, nought point three three. Nought point one three two by four, nought point nought three three. Every answer is a tenth of the one above, and the digits never changed. One division, done once, and four answers out of it.
But do not let that look tidier than it is. Try it with a divisor of eight. One hundred and twenty-six over eight is fifteen point seven five — already two places, and each step down adds another. By nought point nought one two six over eight, the answer needs six decimal places. So shifting the number you divide does not keep the answer the same length. It keeps the answer's digits.
And that is the whole of it. The digits come from the division, the point comes from where the sharing crossed. Move one and you have not touched the other.
Where this fits
Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.
Builds on
- Long division continued past the ones placeClass 7 · Ch 4, Another Peek Beyond the Point
- Extending Indian place value to the right of the pointClass 7 · Ch 3, A Peek Beyond the Point
- Reciprocals, and Brahmagupta's rule for dividing fractionsClass 7 · Ch 8, Working with Fractions
Comes up again in
- Dividing when the divisor has a decimalClass 7 · Ch 4, Another Peek Beyond the Point
- Divisions that never endClass 7 · Ch 4, Another Peek Beyond the Point