Exercise 1.1 answers: Real Numbers

Class 10 Maths7 questions

Exercise 1.1

7 questions · page 5 of the book

Question 1

“Express each number as a product of its prime factors” · p. 5

Open NCERT p. 5Matches NCERT’s answer

(i) 140

  1. 140 is even, so divide by 2: 140 ÷ 2 = 70.
  2. 70 is even too: 70 ÷ 2 = 35.
  3. 35 is not even, but it ends in 5, so divide by 5: 35 ÷ 5 = 7.
  4. 7 is prime, so stop here.

Answer140 = 2² × 5 × 7

(ii) 156

  1. 156 is even: 156 ÷ 2 = 78.
  2. 78 is even too: 78 ÷ 2 = 39.
  3. 39 is not even. Its digits add to 12, which 3 divides: 39 ÷ 3 = 13.
  4. 13 is prime, so stop here.

Answer156 = 2² × 3 × 13

(iii) 3825

  1. 3825 is odd. Its digits add to 18, which 3 divides: 3825 ÷ 3 = 1275.
  2. 1275's digits add to 15, again divisible by 3: 1275 ÷ 3 = 425.
  3. 425 ends in 5: 425 ÷ 5 = 85.
  4. 85 ÷ 5 = 17, and 17 is prime, so stop here.

Answer3825 = 3² × 5² × 17

(iv) 5005

  1. 5005 ends in 5: 5005 ÷ 5 = 1001.
  2. 1001 ÷ 7 = 143.
  3. 143 ÷ 11 = 13.
  4. 13 is prime, so stop here.

Answer5005 = 5 × 7 × 11 × 13

(v) 7429

  1. 7429 is odd, its digits do not add to a multiple of 3, and it does not end in 0 or 5, so 2, 3 and 5 are ruled out.
  2. Divide by 17: 7429 ÷ 17 = 437.
  3. 437 ÷ 19 = 23.
  4. 23 is prime, so stop here.

Answer7429 = 17 × 19 × 23

Watch this explained “32760, taken apart”, 2:46 into Why a composite number has one prime factorisation and no other · हिंदी में देखें

Question 2

“Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF” · p. 5

Open NCERT p. 5Matches NCERT’s answer

(i) 26 and 91

  1. Write both as products of primes: 26 = 2 × 13, 91 = 7 × 13.
  2. HCF takes the lower power of every common prime: only 13 is common, so HCF = 13.
  3. LCM takes the higher power of every prime present: LCM = 2 × 7 × 13 = 182.
  4. Check: LCM × HCF = 182 × 13 = 2366, and 26 × 91 = 2366 too. They match.

AnswerHCF = 13, LCM = 182

(ii) 510 and 92

  1. 510 = 2 × 3 × 5 × 17, 92 = 2² × 23.
  2. Only 2 is common to both, at the lower power 2¹, so HCF = 2.
  3. LCM = 2² × 3 × 5 × 17 × 23 = 23460.
  4. Check: LCM × HCF = 23460 × 2 = 46920, and 510 × 92 = 46920 too. They match.

AnswerHCF = 2, LCM = 23460

(iii) 336 and 54

  1. 336 = 2⁴ × 3 × 7, 54 = 2 × 3³.
  2. Common primes are 2 and 3; take the lower power of each: 2¹ × 3¹ = 6, so HCF = 6.
  3. LCM takes the higher power of each prime present: 2⁴ × 3³ × 7 = 3024.
  4. Check: LCM × HCF = 3024 × 6 = 18144, and 336 × 54 = 18144 too. They match.

AnswerHCF = 6, LCM = 3024

Watch this explained “It is not decided per number”, 4:56 into Reading HCF and LCM straight off two factorisations · हिंदी में देखें

Question 3

“Find the LCM and HCF of the following integers by applying the prime factorisation method” · p. 5

Open NCERT p. 5Matches NCERT’s answer

(i) 12, 15 and 21

  1. 12 = 2² × 3, 15 = 3 × 5, 21 = 3 × 7.
  2. Only 3 is common to all three, so HCF = 3.
  3. LCM takes the highest power of every prime that appears: 2² × 3 × 5 × 7 = 420.

AnswerHCF = 3, LCM = 420

(ii) 17, 23 and 29

  1. 17, 23 and 29 are all prime, and all different from each other.
  2. No prime is common to all three, so HCF = 1.
  3. Since nothing is shared, LCM is just their product: 17 × 23 × 29 = 11339.

AnswerHCF = 1, LCM = 11339

(iii) 8, 9 and 25

  1. 8 = 2³, 9 = 3², 25 = 5² — each number is built from a different prime.
  2. No prime is common to all three, so HCF = 1.
  3. LCM is the product of the highest powers seen: 2³ × 3² × 5² = 1800.

AnswerHCF = 1, LCM = 1800

Watch this explained “A third number costs nothing”, 8:03 into Reading HCF and LCM straight off two factorisations · हिंदी में देखें

Question 4

“Given that HCF (306, 657) = 9, find LCM (306, 657)” · p. 5

Open NCERT p. 5Matches NCERT’s answer

  1. For any two numbers, HCF × LCM = product of the two numbers.
  2. 306 × 657 = 201042.
  3. LCM = 201042 ÷ 9 = 22338.

Answer22338

Watch this explained “Running it backwards”, 3:05 into Why the HCF-times-LCM shortcut works for two numbers but breaks for three · हिंदी में देखें

Question 5

“Check whether 6n can end with the digit 0 for any natural number n” · p. 5

Open NCERT p. 5Checked by computer

  1. A number ends in the digit 0 exactly when it is divisible by 10, and 10 = 2 × 5.
  2. So 6ⁿ could end in 0 only if 5 divides 6ⁿ.
  3. 6 = 2 × 3, so 6ⁿ = 2ⁿ × 3ⁿ — its only prime factors are 2 and 3.
  4. By the uniqueness of prime factorisation, 5 is never a factor of 6ⁿ, for any n.
  5. So 6ⁿ can never end in the digit 0.

AnswerNo, 6ⁿ can never end with the digit 0.

Watch this explained “The prime that is not there”, 11:30 into Why a composite number has one prime factorisation and no other · हिंदी में देखें

Question 6

“Explain why 7 × 11 × 13 + 13 and 7 × 6 × 5 × 4 × 3 × 2 × 1 + 5 are composite numbers” · p. 5

Open NCERT p. 5One way to think about it

  1. 7 × 11 × 13 + 13 = 13 × (7 × 11 + 1) = 13 × 78, since 13 is a common factor of both terms.
  2. 13 × 78 is a product of two whole numbers, each bigger than 1, so it is composite.
  3. 7 × 6 × 5 × 4 × 3 × 2 × 1 = 5040, and every factor from 1 to 7 is included, so 5 is a common factor of 5040 and of the 5 being added: 5040 + 5 = 5 × (1008 + 1) = 5 × 1009.
  4. 5 × 1009 is also a product of two whole numbers, each bigger than 1, so it too is composite.

In shortBoth numbers have a common factor that can be taken out (13 in the first, 5 in the second), leaving a product of two numbers greater than 1 — so both are composite.

Watch this explained “Reading off what is not there”, 12:38 into Why a composite number has one prime factorisation and no other · हिंदी में देखें

Question 7

“Sonia takes 18 minutes to drive one round of the field, while Ravi takes 12 minutes for the same” · p. 5

Open NCERT p. 5Matches NCERT’s answer

  1. Sonia is back at the starting point after every multiple of 18 minutes; Ravi is back after every multiple of 12 minutes.
  2. They are both at the start together for the first time after the smallest common multiple of 18 and 12 — that is their LCM.
  3. 18 = 2 × 3², 12 = 2² × 3, so LCM = 2² × 3² = 36.

Answer36 minutes

Watch this explained “Two riders on a track”, 11:07 into Reading HCF and LCM straight off two factorisations · हिंदी में देखें

Every question here was solved twice, separately, by two different AI models, and each answer was put back into the question by a computer program to check it. Where the two disagreed, a stronger model solved it again and the computer check had to pass on its answer. A question about reasoning rather than a number is shown as “one way to think about it”, and anything not yet proven says so instead of guessing. Each answer links to the moment in the video that teaches it.

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