PrepShorts · Study sheet · Class 9 Mathematics · Chapter 6, Measuring Space: Perimeter and AreaPrepShorts

Chapter 6 · Measuring Space: Perimeter and Area

Arc length as the central angle's share of the circumference

यह वीडियो हिंदी में भी · Watch in Hindi

Arcs, and problems built on them10 min

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10 min.

Also recorded in Hindi.Englishहिन्दी

The arc-length formula is a statement about sharing, and nobody had to guess it. Turning a circle about its centre changes nothing.

The idea

The arc-length formula is a statement about sharing. Spinning a circle about its centre slides it onto itself without stretching anything, so two arcs cutting off equal angles must have equal length; and lengths of neighbouring arcs add. Those two facts together force the arc to take exactly its angle's fraction of the circumference — no other rule is possible. The chapter establishes the half and the quarter by symmetry and then says it can guess the general formula; the guess is in fact compelled, and knowing why is what turns the formula from something remembered into something derived. The relay stagger then falls out with a twist: the extra distance per lap depends only on the lane width, not on the size of the track. Keep that per-lap scope — how much of a bend a single 100 m leg contains does change with the track, so a particular changeover mark is not similarly fixed.

What you should be able to do

  • Convert between the two forms of the circumference formula and say why both are in use
  • Prove that a semicircular arc has length πr, using reflection in the diameter, and again using a half-turn about the centre
  • Prove that a quarter arc has length πr/2 using a quarter-turn
  • Rewrite the half and the quarter as 2πr × 180/360 and 2πr × 90/360 and say what the rewriting is for
  • State the general arc-length formula for a central angle θ°
  • Justify the general formula from rotation-invariance and additivity, rather than by extending a pattern
  • Compute arc lengths from a radius and an angle, and the perimeter of a sector, which is an arc plus two radii
  • Compute one lap of a 400 m track from its printed dimensions and account for the 400
  • Compute the stagger between adjacent lanes and show it is the same between every adjacent pair
  • Decide whether a shorter track needs a different stagger, and justify the answer

Words to know

TermDefinition in one lineFirst introduced
arca connected piece of a circle's boundaryprinted in the §6.4 heading and throughout (pp. 125–126)
semicirclethe arc cut off by a diameter, or half the circleprinted in bold in §6.4 (p. 125)
quarter circleone of the four arcs cut off by two perpendicular diametersprinted in bold in §6.4 (p. 125)
subtendsmakes, at the centre, the angle in questionprinted, with its own gloss, in §6.4 (p. 126)
sectorthe region between an arc and the two radii at its endsprinted in Exercise Set 6.1 Q4 (p. 129) and defined at §6.10.1 (p. 146)
staggerthe offset between the starting points of neighbouring lanesprinted on the chapter's opening page (p. 118) and returned to on p. 127
central anglethe angle an arc subtends at the centre of its circleprinted in the Chapter Summary's arc-length bullet (p. 154)
quarter-turna rotation through 90°printed in §6.10.1's discussion of the quarter disc (p. 147)
additivity of lengththat two arcs joined end to end have the total of their lengthsan added term; the chapter uses the fact and does not name it
rotation-invariancethat turning a circle about its centre moves it onto itself and changes no lengthan added compound; the chapter appeals to rotational symmetry without this label

Where people slip up

  • "The arc formula is a rule to memorise." It is a fraction of a circumference, and the fraction is written on the page as θ/360. A student who sees the formula as a share will never invert it by accident.
  • "The general formula was guessed from two cases." The chapter's own word is guess (p. 126), and two cases would indeed be thin evidence. The formula is forced: equal angles cut equal arcs because rotating the circle about its centre changes nothing, and arcs joined end to end add. Give the argument; the explanation gains its whole spine from it.
  • "A sector's perimeter is its arc." It is the arc plus the two radii. The chapter spells this out inside the question (Q4, p. 129) because the mistake is so common.
  • "The outer lane runner is disadvantaged by the stagger." She starts further along precisely so that her longer bend is cancelled. The whole point of the computation is that after the stagger everyone runs the same distance.
  • "A smaller track needs a smaller stagger." The per-lap stagger is 2π times the lane width and contains no reference to the track's size. This is the single most valuable moment in the topic and it answers the question the chapter opened with on p. 118.
  • "The straights matter to the stagger." Every runner runs the same straight distance; the whole difference is on the bends. Setting the straights aside is what makes the arithmetic short.
  • "π is 22/7 throughout." The exercise sets instruct 22/7, but the p. 127 track computation uses 3.1416. Mixing them will make the lap fail to come out at 400.
Transcript1,441 words

There are two formulas for the distance round a circle, and it is not always clear which to reach for. One says it is pi times the width across. The other says it is two pi times the distance from the centre out. They are not two rules. The width across is two of those distances, so the second is the first with that substitution already made. The second is the one to keep, because everything that follows is about taking a share of it.

Draw a line straight through the centre. It cuts the circle into two curved halves; colour them differently. Fold the page along that line and the top arc lands exactly on the bottom one. Folding does not stretch anything, so the two arcs are the same length. Two equal pieces make the whole way round, so each is half of it: pi times the radius. That is a proof, not a measurement.

Now do it a second way. Instead of folding, spin the whole circle halfway round its centre. The top arc goes where the bottom one was, and turning does not stretch anything either. Same conclusion. It is worth having both: folding needs a line, so it handles halves and nothing else. Turning needs no line, and turning is what will keep going. Put in a second line through the centre, square to the first.

Now there are four arcs. Spin the circle a quarter turn and every arc lands on the next one round. So all four are equal, and each is a quarter of the way round: pi times the radius, over two. Notice what did the work. It was not a fact about quarters. It was that turning a circle about its centre slides it onto itself and changes no length. Now rewrite both results in a way that looks like extra work.

The half arc is pi times the radius. Write it instead as the whole way round, times a hundred and eighty over three hundred and sixty. The quarter becomes the whole way round, times ninety over three hundred and sixty. The numbers have not changed. What has changed is that the angle is now visible - a hundred and eighty degrees out of the three hundred and sixty in a full turn, and ninety out of three hundred and sixty.

The arc is not computed from the angle by some rule. The arc is taking the angle's share. Once the fraction is on show, the general case writes itself. Take any angle at the centre and call it theta degrees. The two lines out to the edge cut off an arc, and that arc is the whole way round, times theta over three hundred and sixty. It is the same sentence with a letter where the number was.

And this is where a lot of teaching stops: formula written down, two cases behind it. Two cases is not much. How much is two cases worth? Here is a different rule for arc length. At ninety degrees it is exactly right. At a hundred and eighty degrees it is exactly right. It agrees at both cases just proved, and it is nonsense: it says a sixty-degree arc is as long as a ninety-degree one.

So two cases do not pin a formula down. Something else is doing the work, and it is this: arcs joined end to end add up. Lay a thirty-degree arc against another and you have the sixty-degree arc. The rogue rule breaks that at once - its two thirty-degree pieces come to twelve sevenths of the arc they are meant to make. Tested at every whole angle up to a hundred and seventy-nine, it fails a hundred and seventy-seven of them.

It survives at ninety, where it was built to agree, and at a hundred and fifty by accident. The real rule passes all one hundred and seventy-nine. Turning and adding are enough on their own. Cut the full turn into some number of equal angles. Turning says the arcs they cut are all equal; adding says those arcs come to the whole way round. So each is the whole distance divided by however many there are, and several added together give any angle that is a fraction of a turn.

Build the answer that way, from nothing but those two facts, and compare it with the formula at every whole angle in a turn: they agree three hundred and sixty times and disagree never. Angles that are not a fraction of a turn are caught between the fractions either side, and squeezing pins the arc to thirty decimal places. The formula was never a guess. It is the only rule that turning and adding leave available.

Two quick numbers, using twenty-two sevenths for pi. A sixty-degree arc on a radius of three point five centimetres is a sixth of a circle whose way round is twenty-two, so the arc is three point six seven - a decimal that never ends, cut short. A hundred-and-twenty-degree arc on a radius of six point three metres comes out at thirteen point two exactly. Same formula, one answer exact and the other not.

Now a trap. Ask for the perimeter of a slice - the pie-shaped piece between two radii. Radius fourteen centimetres, angle seventy-five degrees, and the arc is eighteen point three three. But the perimeter is the way round the outside, and two of its edges are straight. Add both radii, twenty-eight centimetres, and it is forty-six point three three - more than twice the curved part alone. Now the reason any of this matters on a Saturday morning.

A running track is two straight sections joined by two curved ends, and those two ends together make one whole circle. Here are the measurements. Each straight is eighty-four point three nine metres. The inside edge of the innermost lane curves at a radius of thirty-six point five. Each lane is one point two two metres wide. And a runner does not hug the paint - they run about three tenths of a metre outside it, so their curve has a radius of thirty-six point eight.

Add it up. Two straights come to a hundred and sixty-eight point seven eight metres. The two curved ends make one circle of radius thirty-six point eight: two hundred and thirty-one point two two metres. Together, four hundred point zero zero. That is where the four hundred comes from. But the lap is not exactly four hundred. It is four hundred metres and one point seven six millimetres. The straight and the radius were chosen to land it there.

And the value used for pi matters: swap in twenty-two sevenths and the same lap comes out at four hundred point zero nine instead. The runner in lane two is one lane width further out, so their curve has a radius of thirty-eight point zero two. Their straights are identical to lane one's, because every runner runs the same straight. Their circle is bigger, and their lap comes to four hundred and seven point six seven.

Seven point six seven metres longer. That is the stagger: lane two starts seven point six seven metres further along, and then both runners cover the same distance. The stagger is not a handicap. It is the cancellation of one. And between lanes two and three it is the same, and across every one of the seven gaps in eight lanes - identical, not merely close. Why identical? Subtract the two laps and watch what cancels.

The straights go, because they are the same. What is left is two pi times the outer radius minus two pi times the inner one - two pi times the difference between them, and that difference is one lane width. The radius is gone. Not simplified away; it was never there. Sweep it across three hundred and ninety-one different bends, from a five-metre radius up to two hundred: one answer, every time.

Do the same sweep on the area between the lanes and you get three hundred and ninety-one different answers - so it can see a dependence when there is one. So a two-hundred-metre track with the same lanes needs the same seven point six seven per lap. But there is a real difference, and it is not that one. On the four-hundred-metre track, fifty-eight parts in every hundred of a lap are bend; two-hundred-metre ovals with different straights give a hundred and sixty different answers.

How much curve falls inside one leg of a relay does change with the track. What a lane costs you per lap does not.

Where this fits

Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.

Builds on

Comes up again in

Either side of this one

The book

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