PrepShorts · Study sheet · Class 8 Mathematics · Chapter 3, Proportional Reasoning-2PrepShorts

Chapter 3 · Proportional Reasoning-2

Dividing a quantity in a given ratio

यह वीडियो हिंदी में भी · Watch in Hindi

Dividing a whole, and picturing it9 min

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9 min.

Also recorded in Hindi.Englishहिन्दी

Make more of this keeping the recipe, and cut this up keeping the recipe, sound like opposites. One builds outward, the other divides inward.

The idea

Cutting a whole up in a given ratio and scaling a recipe up are the same operation run in opposite directions, and the hinge in both is one number: the size of a single part. The fraction rule the chapter states is not a new technique to memorise — each term over the sum of the terms is that share of the whole, and those fractions are built to add to exactly one, which is the reason nothing of the whole goes missing and nothing gets invented. And it is why a ratio settles a division only when there is a fixed total to divide: 1 : 3 : 5 determines a triangle's angles completely, while 3 : 4 : 5 leaves its sides undetermined in size.

What you should be able to do

  • Add the terms of a ratio and interpret the sum as a count of equal parts
  • Divide a stated whole by that sum to get one part, and multiply through to get every share
  • Write the same division in its fraction form, term over sum of terms, and use it directly
  • Show that the shares reconstruct the whole, and explain why they must
  • Divide a quantity given in decimals, or a quantity that is not a whole number of parts, without rounding prematurely
  • Distinguish a problem where the total is given from one where a single part is given, and choose the right first step for each
  • Apply the division to a total that is fixed by mathematics rather than by the question — the 180° of a triangle
  • Decide whether a ratio of sides determines a unique triangle, and whether a given ratio of sides can be a triangle at all

Words to know

TermDefinition in one lineFirst introduced
termsthe individual quantities listed inside a ratioprinted in this chapter, Part II §3.3 (Part II p.57)
quotientthe result of the division that gives the size of one partprinted in this chapter, Part II §3.4 (Part II p.58)
dividing a whole in a given ratiosplitting a stated quantity into shares that stand in a stated ratiothe printed title of §3.4 (Part II p.58)
units (of a mixture)the counting measure the concrete example works in, neither bags nor kilogramsprinted in this chapter, Part II §3.4, Example 3 (Part II p.59)
congruentsame shape and same size, so one figure could be laid exactly on the otherprinted in this chapter, in the fourth exercise item of §3.4 (Part II p.60)
size of one partthe whole divided by the sum of the termsan added term; the chapter computes this number in every worked example and never names it

Where people slip up

  • "Divide 12 in the ratio 2 : 1 means 12 ÷ 2 and 12 ÷ 1." That gives 6 and 12, which add to 18. The division is by the sum of the terms, and the check is that the shares add back to 12.
  • "The sum of the terms is the whole." In Example 3 the terms add to 5.5 and the whole is 110. The sum counts parts; the whole is measured in units. Keeping those two numbers visibly distinct is most of the battle.
  • "You can't divide by 5.5." You can, and the chapter does. Sums of ratio terms are not obliged to be whole numbers.
  • "288 Odiya books means 288 books in all." Item 2 hands you a part, not the whole. Diagnosing which of the two you have been given is the skill; the arithmetic afterwards is identical.
  • "Coins in the ratio 4 : 3 : 2 : 1 means money in the ratio 4 : 3 : 2 : 1." It does not. Ten coins of one rupee and ten of ten rupees are equal in count and a factor of ten apart in value.
  • "Same ratio of sides means the same triangle." Same shape, any size. The words similar and congruent do different jobs, and exercise item 4 is built to separate them.
  • "Any three numbers can be the sides of a triangle." 1 : 3 : 5 cannot, at any scale. Multiply all three by anything you like and the short two still fail to reach past the long one.
  • "A ratio always determines the answer." Only against a fixed total. Sections 8 to 10 are three variations on that one sentence.
Transcript1,352 words

Two questions that sound like opposites. Make more of this, keeping the recipe. And: cut this up, keeping the recipe. One builds a quantity outward from a part you were handed. The other carves a quantity you already have into shares. They feel like different jobs. They are the same operation, run in opposite directions. And the hinge in both is one number: the size of a single part. Find that, and everything else is multiplication.

Start small. Divide twelve in the ratio two to one. Two parts of one thing, one part of the other. So how many parts are there altogether? Three. Now hold on to that three, because it is the number people lose. Three is not a quantity. There are not three of anything here. Three is a COUNT of equal parts, and the twelve is what those parts have to share out.

The sum of the terms counts parts. The whole is measured in units. Keep those two numbers apart and this topic is easy. So: twelve units, three parts. One part is twelve divided by three, which is four. That is it. That is the whole calculation. Everything after it is multiplying. Two parts is eight. One part is four. And check: eight plus four is twelve. Nothing went missing and nothing got invented.

Notice the shape of it. Divide once by the sum. Then multiply once per share. Two steps, whatever the ratio is. Now a harder one, and it is harder in an interesting way. A hundred and ten units of concrete are wanted, with cement, sand and gravel in the ratio one to one and a half to three. Add the terms. One plus one and a half plus three is five and a half.

There is a real instinct at this point that you cannot divide by five and a half. You can, and you must. A hundred and ten divided by five and a half is twenty. One part is twenty units. So cement is one part, twenty. Sand is one and a half parts, thirty. Gravel is three parts, sixty. And twenty plus thirty plus sixty is a hundred and ten. Why did that close up so neatly? It was not luck, and it is worth seeing why not.

Look at what each share really is: the whole, times that term, over the sum of the terms. For the concrete those fractions are two elevenths, three elevenths and six elevenths. And two plus three plus six is eleven. The fractions add to eleven elevenths, which is one. That is the whole argument. The fractions are built out of a sum that IS the sum of the terms, so they cannot add to anything but one.

So the shares cannot add to anything but the whole - whatever the whole is, and whatever the ratio is. The rule is not just usable. It is trustworthy. Which gives you the same step written a second way, and you will meet both. Instead of dividing and then multiplying, multiply the whole by this term over all the terms. Cement is a hundred and ten times one over five and a half. Sand is a hundred and ten times one and a half over five and a half.

Same twenty. Same thirty. It has to be, because it is the same two operations in the other order. Use whichever you like. But the dividing form has one advantage: it puts the size of one part on the table where you can see it. Here is the wrong move, and it is worth doing deliberately once. Divide twelve in the ratio two to one. Somebody divides twelve by two, and twelve by one.

Six and twelve. Which add to eighteen. Eighteen. Out of a whole of twelve. The method invented six units of something out of nothing. And that failure is not an accident of these numbers. Put that idea to nine different splittings and it closes on three of them and fails on the other six. The three it survives are all ratios whose terms are every one the same - which is no help on any real mixture. The division is by the SUM, and the check is that the shares add back.

Now a question that looks the same and is not. A library holds picture books, novels and reference books in the ratio three to two to one, and there are two hundred and eighty-eight picture books. Stop before you divide. Two hundred and eighty-eight is not the whole. It is one share. So do not divide by the sum. Divide by the term that names it: two hundred and eighty-eight over three is ninety-six books to the part.

Then multiply through: two hundred and eighty-eight, one hundred and ninety-two, ninety-six - five hundred and seventy-six books in all. Get that wrong and read the share as the whole, and you get a hundred and forty-four, ninety-six and forty-eight. Those add to two hundred and eighty-eight, so the check passes - and every single number is wrong. Put the two directions side by side on one example. A purple is fixed by red to blue to white in the ratio two to three to five.

First question: you have fifty millilitres of finished purple. The terms add to ten, one part is five millilitres, and the shares are ten, fifteen and twenty-five. Second question: you have ten litres of white and want to use it all. White is five parts, so one part is two litres, and you need four of red and six of blue - twenty litres of paint. Same ratio. Opposite directions. And in both, the first thing computed was the size of one part.

Every division so far had a whole that somebody chose. A hundred and ten units. Fifty millilitres. Here is one where the whole is not up for discussion. A triangle's angles are in the ratio one to three to five. What are they? You were never told a total. But you have one anyway, because a triangle's angles add to a hundred and eighty, and that was settled long before the question was asked.

So divide it. One plus three plus five is nine. A hundred and eighty over nine is twenty degrees to the part. Twenty, sixty and a hundred. And they add to a hundred and eighty, because of course they do. Now change one word and watch the whole thing collapse. A triangle whose SIDES are in the ratio one to three to five. What are they? There is no answer, and there are two separate reasons why.

The first: no such triangle exists. One and three together are four, and four cannot reach across five. Two sides have to beat the third. The second is deeper. Take a ratio that does work - three to four to five. Those are the sides of a triangle at any size at all: three, four, five; or six, eight, ten; or thirty, forty, fifty. One shape, three different perimeters. Nothing in the ratio picks one, because there was never a fixed total to divide.

That is the difference. The angle sum was handed to you. A perimeter never is. One last trap, and it catches careful people. A hundred coins, worth ten, five, two and one, in the ratio four to three to two to one. Ten parts, ten coins to the part. Forty, thirty, twenty and ten coins. That much is easy. Now: how much money? Four hundred, a hundred and fifty, forty and ten. Six hundred altogether.

But look at those four amounts as a ratio. Simplified, they are forty to fifteen to four to one - and that is not four to three to two to one. It is not even close. Dividing a quantity in a ratio divides exactly the thing you divided. The counts were in that ratio. Nothing else was promised, and nothing else came true. Find the size of one part. Multiply. Check it adds back. And be precise about what, exactly, you were splitting.

Where this fits

Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.

Builds on

Comes up again in

The book

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