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Chapter 4 · Exploring Some Geometric Themes

The Sierpinski carpet and gasket: what repeated removal leaves behind

यह वीडियो हिंदी में भी · Watch in Hindi

Fractals9 min

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9 min.

Also recorded in Hindi.Englishहिन्दी

Two constructions, and almost everything about them is the same. What differs is what gets thrown away — and how much is left at the end.

The idea

The two recursions the chapter writes down are not bookkeeping — they are read straight off the construction, and each one is justified by a single sentence about what happens to one piece. Every surviving square breeds eight survivors, so the count multiplies by 8; every survivor punches exactly one new hole and no old hole ever heals, so the holes accumulate. Once you see that, you can also see the thing the counts hide: the number of surviving pieces explodes while the area they cover collapses, because each generation keeps eight pieces that are each one-ninth the size. Growth in count and shrinkage in area are the same fact.

What you should be able to do

  • Prove that joining the midpoints of an equilateral triangle cuts it into four identical equilateral triangles, using the chapter's own hint about the corner triangles
  • State the carpet's construction rule and the gasket's construction rule, and say what plays the part of "one piece" in each
  • Justify Rₙ₊₁ = 8Rₙ by an argument about a single surviving square
  • Justify Hₙ₊₁ = Hₙ + Rₙ by two separate observations, one about new holes and one about old ones
  • Turn the recursion Rₙ₊₁ = 8Rₙ into the closed form Rₙ = 8ⁿ and say why the step from one to the other is legitimate
  • Compute the corresponding counts for the gasket and compare them with the carpet's
  • Compute the area remaining at step n for both fractals, taking the starting figure as 1 square unit
  • Explain how the piece count can grow without limit while the area shrinks towards zero

Words to know

TermDefinition in one lineFirst introduced
Sierpinski Carpetthe fractal reached from a square by repeatedly deleting the middle ninth of every surviving squareprinted in this chapter (Part II, §4.1, p.70)
Sierpinski Gasketthe fractal reached from an equilateral triangle by repeatedly deleting the middle quarter of every surviving triangleprinted in this chapter (Part II, §4.1, p.72)
Sierpinski Trianglethe chapter's alternative name for the same object, printed alongside the firstprinted in this chapter (Part II, §4.1, p.72, where the two names are set together as one term)
holea piece that has been removed and is no longer part of the figureprinted in this chapter (Part II, §4.1, p.71)
midpointthe point that divides a segment into two equal partsprinted in this chapter (Part II, §4.1, p.72; also on Part II p.76, outside §4.1)
equilateral trianglea triangle with all three sides equal, and so all three angles 60°printed in this chapter (Part II, §4.1, p.72)
isosceleshaving two equal sides — the property the chapter's hint points atprinted in this chapter (Part II, §4.1, p.72, inside the printed Hint)
identicalcongruent; the word the chapter uses for the four trianglesprinted in this chapter (Part II, §4.1, p.72)
recursiona rule that gives the next term in terms of the one before itan added term; the chapter writes two such rules and gives them no name
closed forma formula for the nth term that does not refer to earlier termsan added phrasing, not printed in this chapter
midsegmentthe segment joining the midpoints of two sides of a trianglean added term; the chapter draws these segments and does not name them

Where people slip up

  • "Rₙ₊₁ = 8Rₙ is just an observed pattern." It is not — it is proved by one sentence about one square. Each surviving square is subdivided into 9 and loses 1, so it contributes exactly 8, and this happens to every survivor independently. Show the argument on a single square, then multiply.
  • "Hₙ₊₁ = Hₙ + Rₙ because a hole appears in each hole." No. New holes appear in the surviving squares, one apiece — a hole is gone and does nothing further. The Rₙ in that formula is the survivor count, not the hole count, and students routinely substitute the wrong one.
  • "Rₙ = 8ⁿ because the pattern 1, 8, 64 looks like powers of 8." The reason is that multiplying by 8 exactly n times starting from 1 gives 8ⁿ. The chapter writes R₁ = 8 × 1 and R₂ = 8 × 8 precisely so the repeated multiplication is visible before the exponent is claimed.
  • "Joining midpoints obviously gives four identical triangles." It is not obvious and the chapter asks for a proof. The claim that needs work is that the middle triangle is equilateral and the same size as the corners; the hint about isosceles corner triangles is the route in.
  • "Removing pieces forever must leave nothing at all." The area does tend to zero, but the set of leftover points is not empty — every corner of every surviving piece survives every step. The chapter does not raise this and an explanation should not resolve it, but it should not assert emptiness either.
  • "More pieces means more area." The single sharpest error this topic can correct. Eight pieces at one-ninth each is less than one piece at full size. Put 8 × (1/9) beside 1.
  • "The gasket is a different kind of thing from the carpet." Same machine, different starting shape and different keep-fraction. Every formula in the gasket half is the carpet formula with 8 → 3 and 1/9 → 1/4.
Transcript1,307 words

Two constructions, side by side, and almost everything about them is the same. The carpet starts with a square. Cut it into nine, throw away the middle one, and do the same to each of the eight that survive. The gasket starts with an equilateral triangle. Join the midpoints of its three sides, throw away the middle piece, and do the same to each of the three that survive. Same machine. What changes is the shape you begin with, how many pieces the cut makes, and how many of them you keep.

Nine and eight for one. Four and three for the other. Everything in this video follows from those two pairs of numbers. But the gasket's rule has something hidden in it that the carpet's does not. Cut a square into a three by three grid and you can see the nine pieces are equal. Join three midpoints of a triangle and you have to argue it. The claim is that those three segments cut the triangle into four identical equilateral triangles.

Not four triangles. Four identical ones, and every one of them equilateral. And the piece that takes work is the middle one, because it is the only one that does not inherit a corner from the triangle it came out of. Here is the argument, and the way in is the corners. Take one corner triangle. Two of its sides are half-sides of the parent, so they are equal to each other, and the angle between them is the parent's own sixty degrees.

Two equal sides means the two base angles are equal. They have a hundred and twenty degrees to share between them, so each one is sixty. All three angles sixty. So the corner triangle is equilateral, with side half the parent's. Now the middle one. Every joining segment is a side of some corner triangle, so all three of them are half the parent's side. Three equal sides. The middle triangle is equilateral too, and exactly the same size. Four identical pieces, each a quarter of the area.

And one thing worth noticing: the four-identical-pieces part is true of any triangle at all. It is the equilateral part that needs the parent to be equilateral. Now count. Write R for the number of surviving squares, and R at step n for how many there are after n steps. One square at step zero. Take any single survivor and apply the rule to just that one. It is cut into nine, it loses one, and it leaves eight.

And that happens to every survivor, independently of what any other one is doing. So the count at the next step is eight times the count at this one. That is not a pattern spotted in a table. It is one sentence about one square. From that rule to a formula. R at step zero is one. R at step one is eight times one, which is eight. R at step two is eight times eight. R at step three is eight times that again.

Multiplying by eight exactly n times, starting from one, is eight to the n. So R at step n is eight to the n - and the reason is the repeated multiplication, not the fact that one, eight and sixty-four happen to look like powers of eight. Holes next, and this one needs two observations rather than one. The first: each surviving square gets one new hole punched in it at the next step. One apiece, no more and no fewer.

The second: a hole that is already there stays there. Nothing ever heals. So the holes at the next step are the holes you already had, plus one for every survivor. Not plus one for every hole. The number you add is the survivor count, and confusing those two is the commonest slip in the whole topic. Run it out. No holes at all at step zero. At step one, one hole. At step two, one plus eight, which is nine.

At step three, one plus eight plus sixty-four. Seventy-three. Every term added is a power of eight, and the running totals are one, nine, seventy-three, five hundred and eighty-five. That sum has a formula of its own: eight to the n, less one, over seven. At step three that is five hundred and eleven over seven, which is seventy-three. It agrees. The two wrong readings are worth taking seriously, because both of them can be answered rather than just warned against.

Read it as a new hole inside every hole. You start with no holes, so you add no holes, and the figure never gets a single one at any step. Nothing at all happens. Read it as though old holes healed, and count only what this step made: one, then eight, then sixty-four. That is right at step one and wrong at every step after it. Against six steps it agrees twice and disagrees four times.

The recursion adds survivors. Every other plausible thing it could add gives you a different figure. Now the gasket, and there is almost nothing new to say, which is the point. One triangle becomes three, so the survivor count multiplies by three each step: one, three, nine, twenty-seven. Each survivor punches one hole and no hole heals, so the holes go one, then one plus three, then one plus three plus nine. One, four, thirteen.

And the formula is three to the n, less one, over two. At step three that is twenty-six over two, which is thirteen. The same two sentences did all of that. Eight becomes three, and everything else follows unchanged. Area now. Take the shape you start with as one unit of area. Each step keeps eight of the nine equal pieces of every surviving square, so whatever area is left gets multiplied by eight ninths.

After n steps that is eight ninths to the n. One, then eight ninths, then sixty-four eighty-firsts, then five hundred and twelve seven hundred and twenty-ninths. For the gasket the multiplier is three quarters: one, three quarters, nine sixteenths, twenty-seven sixty-fourths. And this is not a second result. Eight to the n pieces, each one a ninth of a ninth of a ninth, is eight ninths to the n. The area was already inside the count. It was never a separate question.

Which brings the two halves of this together. At step three the carpet has five hundred and twelve surviving squares and seventy-three holes, and it still covers over seventy per cent of where it started. At step ten it has over a billion surviving squares - and it covers just over thirty per cent. The gasket at step ten has fifty-nine thousand and forty-nine triangles, and is down to between five and six per cent.

Eight pieces at a ninth each is less than the one piece they came from. More pieces and less area are not two facts fighting each other. They are the same fact said twice. Although growing and shrinking are not automatically the same thing, and it is worth knowing why they travel together here. A rule that cut into nine and kept all nine would multiply the count every step and never lose a scrap of area.

A rule that kept one piece out of nine would shrink away to nothing without the count ever growing at all. Of five rules put side by side, three grow and three shrink - and they are not the same three. Only these two do both. Which leaves one last question, and it is harder than it looks. The area goes to zero. Does that mean nothing is left? Not obviously. Removing pieces forever is not the same thing as removing everything, and settling which of those has happened is a longer story than this one.

Where this fits

Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.

Builds on

Comes up again in

The book

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