PrepShorts · Study sheet · Class 7 Mathematics · Chapter 8, Working with FractionsPrepShorts

Chapter 8 · Working with Fractions

Fractional relations between two quantities

यह वीडियो हिंदी में भी · Watch in Hindi

Fractions inside a problem10 min

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10 min.

Also recorded in Hindi.Englishहिन्दी

Nobody measures the miser's gift against a whole coin. It is only ever worth something compared with what he could have given.

The idea

A chain of relative statements collapses into a single multiplication. Nobody ever measures the shaded sliver against the whole square, and nobody ever measures the miser's gift against a whole coin — each is only ever compared with the thing immediately containing it. Yet both can be pinned to the whole exactly, because "a fraction of a fraction of a fraction" is one product, and a product does not care which end of the chain you start from. That is what makes a picture of nested shapes and a twelfth-century riddle about a beggar the same computation, and it is why §8.3's problems are solved by setting up a chain rather than by any new arithmetic.

What you should be able to do

  • Turn a word problem into a division or a multiplication before computing anything
  • Express a part of a figure as a fraction of the whole by chaining the containment relations and multiplying along the chain
  • Compute the area of a region inside a square by successive fractions rather than by measuring
  • Evaluate a long product of fractions and reduce it to lowest form
  • Read a historical fraction problem, extract the chain, and interpret the answer in the units the problem uses
  • Convert between quantities linked by a ladder of exchange rates, by multiplying along the ladder
  • Say why the answer to a division can be a fraction even when the thing being counted is a whole object

Words to know

TermDefinition in one lineFirst introduced
areathe surface a region covers, here always measured against the whole squareprinted in §8.3, pp.191–193
square unitsthe unit the areas in these examples are counted inprinted in §8.3, pp.191–193
whole squarethe region every answer in "Fractional Relations" is expressed againstprinted in "Fractional Relations", pp.192–193
shaded regionthe part of the figure whose fraction is being asked forprinted in "Fractional Relations", p.192
non-unit fractionsfractions whose numerator is something other than 1printed in §8.3, p.190 and in "A Pinch of History", p.194
reciprocalthe number that multiplies a given number to give 1, used in every division hereprinted in §8.3, pp.190–191
dividendthe number being divided in these worked examplesprinted in §8.3, pp.190–191
divisorthe number being divided byprinted in §8.3, pp.190–191
lowest formthe form a long product is reduced to at the endprinted in "A Dramma-tic Donation", p.194
drammathe silver coin the Līlāvatī problem is denominated inprinted in "A Dramma-tic Donation", pp.193–194
cowrie shellthe smallest denomination in the chapter's coin ladderprinted in "A Dramma-tic Donation", pp.193–194
chain of relationsa run of "a fraction of a fraction of…" statements resolved by one productthe explanation's phrase; not printed in this chapter
nestedone region sitting entirely inside anotherthe explanation's word; not printed in this chapter

Where people slip up

  • "You add the fractions along the chain." Three-quarters of one-eighth is a product. Adding gives a number larger than either, which the picture immediately refutes — the shaded sliver is smaller than the triangle it sits inside.
  • "3/4 of the triangle means 3/4 of the square." Every fraction in the chain is measured against a different whole, and only the last multiplication brings it back to the square. Say out loud, at each link, what the current whole is.
  • "The final answer should be roughly a quarter, since we started with a quarter." Each link shrinks it further. Landing on 3/32 is the point.
  • "375/2 bricks is a mistake." It is the chapter's printed answer, and it is the honest result of the division. Whether you can lay half a brick is a different question from whether the arithmetic is right.
  • "Four fountains, so add the times." Adding a day, half a day, a quarter and a fifth would give a longer time than the slowest fountain alone, which is absurd for taps running together. What adds is how many cisterns each fills in a day.
  • "The miser gave 1/1280 of a coin, so almost nothing." He gave exactly one coin — the smallest one in circulation. The unit conversion is what turns a fraction into an object, and it is the punchline.
  • "The exchange rates on p.194 are historical fact." The chapter says they varied and introduces its own set as an assumption. Keep the hedge; the assumed ladder does not even reconcile with the 1280 cowries the tale gives.
  • "A word problem needs the right formula." Every one of these needs the right chain, and the arithmetic afterwards is §8.1 and §8.2 unchanged.
Transcript1,412 words

A quarter of a litre of milk, poured equally into five cups. How much is in one cup? That is a sharing, and every sharing is a division. A quarter, divided by five. Which means: five times what makes a quarter? Five turns into one fifth, and a quarter of a fifth is one twentieth. One twentieth of a litre in each cup. Check it. Twenty of those cups would be a whole litre, so five of them is a quarter. It fits.

Nothing new there. But notice the shape of that, because the shape is what this whole video is about. Second one. You have a floor of seven and a half square units to cover. The bricks are square, one fifth of a unit along each side. First question. How much area does one brick cover? One fifth by one fifth. One twenty-fifth of a square unit. Now, how many of those fit into seven and a half?

Seven and a half is fifteen over two. Fifteen over two, divided by one twenty-fifth. And dividing by a twenty-fifth is multiplying by twenty-five. Three hundred and seventy-five over two. Stop on that answer for a moment, because it is worth looking at. Three hundred and seventy-five over two is a hundred and eighty-seven and a half. A hundred and eighty-seven and a half bricks. You cannot lay half a brick, and nobody is pretending you can.

But the arithmetic is not wrong. Whether an answer is a usable instruction is a different question from whether it is correct. A hundred and eighty-seven whole bricks leaves a gap. A hundred and eighty-eight overshoots. So the honest answer is the one with the half in it, and the practical answer is that you cut one brick. Do not round a result just because it looks untidy. Say what it means instead.

Third one, and this is the one people get wrong. Four fountains fill the same tank. On its own, the first takes a day, the second half a day, the third a quarter of a day, the fourth a fifth of a day. All four run together. How long? The tempting move is to add the times. A day, plus a half, plus a quarter, plus a fifth. That comes to nearly two days. Which is longer than the slowest fountain takes by itself, with four taps running. Obviously wrong.

Here is what actually adds. How many tanks each one fills in a day. One. Two. Four. Five. Together, twelve tanks a day. So one tank takes a twelfth of a day. Two hours. Faster than any of them alone, which is what you would expect. Now the real subject of this video. Here is a square. I am going to draw some lines inside it. Both diagonals. Both mid-lines. And then the top right quarter gets cut up further still.

Somewhere inside all of that there is a small shaded sliver. The question is: what fraction of the whole square is that sliver? And here is the difficulty. Nobody is going to measure it against the whole square. It is far too small and far too awkwardly placed. So we will not. We will compare it with the thing immediately around it, then compare that with the thing around it, and keep going outward.

A chain of relations. Then one multiplication at the end. First link. The top right quarter. The two mid-lines cut the square into four equal squares. So the top right one is a quarter of the whole square. Call the whole square one square unit. Then that corner square is a quarter of a square unit. Now forget the big square for a moment. Genuinely forget it. From here on, the corner square is our whole.

Everything in the next step is measured against that, and not against the original. This is the most important habit in the whole topic. Always know what your current whole is. Second link. Enlarge the corner square so we can see inside it. It has a diagonal drawn across it. And a diagonal cuts any square into two identical triangles. So the triangle is one half of the corner square.

Not one half of the big square. One half of the corner square. The whole has changed. Although we can already say what the triangle is against the original, if we want to. Half of a quarter. One eighth of the big square. And now the whole changes again, because the shaded part sits inside that triangle. Third link. Enlarge the triangle. The shaded region is three quarters of it. Let me show you why, rather than just telling you.

The triangle is itself cut into four equal pieces, by lines that are already in the figure. Three of those four are shaded. One is not. Three quarters of the triangle. And that is the last link, because there is nothing smaller sitting inside it. So we have three statements, and every one of them uses a different whole. A quarter of the square. A half of that. Three quarters of that.

Now put them together, and this is the step that does all the work. Three quarters, of one half, of one quarter. The word of is multiplication. So it is three quarters, times one half, times one quarter. Multiply the tops. One times one times three is three. Multiply the bottoms. Four times two times four is thirty-two. Three over thirty-two. Already in lowest form. And now it is measured against the big square again, because the chain reached all the way back out to it.

Notice what you must not do. Adding those three fractions gives three halves, which is bigger than the whole square. The picture refuses that instantly. And notice this as well. I could have multiplied them in any order. All six orders give three over thirty-two. A product does not care which end you start from. Here is a problem from a mathematician called Bhaskara, written around eleven fifty. A traveller asks a miser for money.

The miser gives him one fifth, of one sixteenth, of one quarter, of one half, of two thirds, of three quarters of a coin. That is deliberately exhausting, and it is meant to be. It sounds enormous. But it is exactly what we have just done. Six links instead of three. Multiply the tops. One, one, one, one, two, three. Six. Multiply the bottoms. Five, sixteen, four, two, three, four. Seven thousand six hundred and eighty.

Six over seven thousand six hundred and eighty, which reduces to one over one thousand two hundred and eighty. One one-thousand-two-hundred-and-eightieth of a coin. That is the gift. And that sounds like almost nothing, which is where most people stop reading. But there is one more step, and it is the punchline. The coin in the story is a silver dramma. And in that story, one dramma is worth one thousand two hundred and eighty cowrie shells.

A cowrie shell was a real unit of currency, and the smallest one there was. So one twelve-hundred-and-eightieth of a dramma, times one thousand two hundred and eighty shells to the dramma, is exactly one shell. He did not give a fraction of anything. He gave one cowrie shell. The most elaborate-sounding gift in the problem turns out to be the smallest coin in circulation. That is the joke, and it needed a chain of six fractions to land it.

One last thing, about those coins, and it comes with a warning attached. There were gold coins, silver coins, copper coins and cowrie shells, and you can lay them out as a ladder. But the rates between them were never fixed. They changed with the region, with the century, with the economy, and with the weight and purity of the actual metal. So take what follows as an assumption, not as a fact.

Assume one gold dinar is twelve silver drammas, and one dramma is four copper panas. Then one pana, as a fraction of a gold dinar, is one twelfth of one quarter. One forty-eighth. The same chaining, on money instead of shapes. And here is the honest part. That ladder gives a hundred and twenty cowries to a dramma, but the story used one thousand two hundred and eighty. They do not agree. Which is exactly why you hedge. Chain the relations, multiply along them, and be clear about which links you assumed.

Where this fits

Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.

Builds on

Either side of this one

The book

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