PrepShorts · Study sheet · Class 6 Mathematics · Chapter 8, Playing with Constructions
Chapter 8 · Playing with Constructions
Which rectangles break into identical squares, and which do not
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A construction problem with no measurements in it at all, and that is exactly the point.
The idea
Whether a rectangle splits into identical squares has nothing to do with how big it is and everything to do with how its two sides compare. The problem therefore contains no measurement at all — which is why the chapter can solve it with a compass and never touch a ruler. You choose one side freely, and then you copy it, twice or three times; and copying a length is the one thing a compass does exactly while a ruler only does approximately.
What you should be able to do
- Simplify a hard construction to an easier one and then build the hard one back up
- Draw a rough diagram for a divided figure and mark the equalities on it
- Chase a chain of equal sides through such a figure
- Use the tick-mark convention to record which sides are equal
- Given one side of a rectangle that splits into two identical squares, state the other, and do the same for three
- Copy a length with a compass instead of measuring it, and say why that is enough here
- Name two side lengths that rule out any split into two matching squares, and another pair that rules out three, and justify each choice
Words to know
| Term | Definition in one line | First introduced |
|---|---|---|
| identical | the same in both size and shape | printed in §8.1, p.191; used throughout §8.4, p.199 |
| divided | cut into parts with nothing left over | printed in §8.4, p.199 |
| convention | an agreed way of marking something on a diagram | printed in §8.4, p.200 |
| equal sides | sides of the same length, marked alike on a rough diagram | printed in §8.4, p.200 |
| rough diagram | the unscaled plan drawn before constructing | printed in §8.4, p.200 |
| transfer | to carry a length from one place to another with the compass | printed in §8.4, p.200 |
| assign | to choose a value for a length the problem leaves open | printed in §8.4, p.200 |
| analysis | the reasoning done on the rough diagram before drawing | printed in §8.4, p.200 |
| ratio | how one length compares with another, size set aside | an added term; not printed in this chapter |
Where people slip up
- "You need to be told a measurement before you can construct anything." Not here. The problem asks only for a rectangle with the property, so the size is yours; only the proportion is fixed.
- "Two identical squares could also be stacked, or arranged some other way." Two squares of the same size joined into a rectangle can only sit side by side, which is why the long side comes out at exactly twice the short one.
- "A rectangle twice as long as it is wide might split into three squares if you cut it cleverly." For two squares and for three, the number fixes the proportion completely: two means 2 to 1, three means 3 to 1, and nothing clever is available. Two and three are the only cases the Breaking Rectangles task asks for, and the argument works because neither number can be laid out in more than one row — four identical squares, by contrast, make a 4-to-1 rectangle in a row and a square in a two-by-two block.
- "4 cm by 2.5 cm nearly works." Nearly is not a category here. Either the long side is exactly twice the short one or the squares are not identical.
- "Measuring AF with a ruler and then measuring 4 cm again for AB is the same as copying it." It is not: the second measurement can disagree with the first. The compass never has to read a scale twice.
- "The tick marks are decoration." They are how the rough diagram carries the result of the reasoning, so that the construction can be read off it.
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Worked answers to this chapter’s exercises
Transcript1,320 words
Draw a rectangle that breaks into three identical squares in a row. That is the whole task. Now notice what it does not give you. No length for the long side. No length for the short one. Not a single number anywhere. Which feels like far too little to start with. You cannot pick up a ruler if nobody has told you what to measure. But read it once more. It asks for a rectangle with that property. Not one particular rectangle. Any one at all.
So the size is yours to choose. Only the shape is fixed. And that turns out to be the easy half of this problem, not the hard half. Before doing three, do two. When a problem will not give way, make it smaller and see whether the smaller one does. So: a rectangle that breaks into two identical squares, sitting side by side. If you can build that, the three-square version is unlikely to need a new idea from you.
And if you cannot build it, you have saved yourself a great deal of wasted effort on the harder one. Two it is. So where do you start drawing? You cannot start with the long side, because you do not know how long it is. You cannot start with the short side either, for exactly the same reason. So do not start by drawing at all. Draw a plan instead. A rough diagram: not to scale, not measured, deliberately sloppy.
Its only job is to hold the labels still while you think about them. Everything difficult about this problem gets settled on that rough diagram, and the real construction afterwards takes about a minute. Here is the plan. A rectangle. Along the top, three points: A, B and C. Along the bottom, three more: F, E and D. One line straight down the middle, from B to E, cutting the whole thing into two pieces.
The left piece is A B E F. The right piece is B C D E. And now say out loud the two things you were promised about those pieces. They are identical to each other. And each one of them is a square. Nothing here is drawn accurately. B is nowhere near halfway along. Neither piece is remotely square. It does not matter in the slightest. The labels are right, and the labels are what you are about to reason with.
So follow it round. The two pieces are identical. So the top edge of the left one equals the top edge of the right one. A B equals B C. Now use the other promise. Each piece is a square, and a square has all four of its sides equal. In the left piece, that gives you A F equals A B, and B E equals A B, and F E equals A B. Four sides, one length.
In the right piece, the same again. B C and C D and D E and B E are all equal to one another. And look at B E. It belongs to both pieces at once. Which hooks the two chains together into one. Every short line in the entire figure — and there are seven of them — is the same length. That is worth writing onto the diagram itself, and there is an agreed way of doing it.
A short tick drawn across a line means this: any two lines carrying a tick are the same length. So put one on A F. One on B E. One on C D. And along the top and bottom: A B, B C, F E, E D. Seven ticks, and the diagram stops being a picture of the question. It is now carrying the answer. Someone who picks it up can read the reasoning off it without doing any of the reasoning again.
Now choose. Pick a length for A F. Anything you like — that is the thing the problem deliberately left open. Say four centimetres. Every ticked line in the figure is now four centimetres. So A B is four. And B C is four. And the long side, A C, is A B followed by B C. Eight. Eight by four. That is your rectangle, and you can go and draw it.
Notice how many decisions you actually made. One. After that, nothing was left open. And here is where the ruler becomes optional. You never have to measure A F at all. Draw it whatever length you like. Raise the two sides. Then open a compass to span A F exactly, lift it, and set that span down along the top to place B. Once more from B, and you have C.
Why go to the trouble, when the ruler is lying right there? Because a ruler has to be read, and a reading can be off — and the second reading can be off differently from the first. Then your two pieces are not identical, and everything you just proved stops applying. A compass reads nothing. It carries the length it is already holding. Set it slightly wrong at the start and you get a smaller figure than you intended. You still get two identical squares.
Now three. Same rough diagram, one more cut. Four points along the top, four along the bottom, three pieces between them. Run the identical chain. All three pieces the same as each other, each of them a square, so every short line in the figure is equal to every other. The long side is now three of those instead of two. Four centimetres across gives you twelve along. And with the compass: open it to the short side, and step it along the top three times instead of two.
One extra copy of a length you were already holding. That is the entire difference between the two problems. So which rectangles refuse to split? Take one that is four centimetres by two and a half. For two squares, the long side has to be exactly twice the short side. Twice two and a half is five. You have four. It fails. And it fails by half a centimetre, which sounds small and is not.
Nearly is not a category here. Either the two pieces are identical squares or they are two different rectangles. Try seven by two against the three-square test. Three twos are six. You have seven. Also out. And no amount of cleverness about where to cut will rescue either of them. Which raises a question about why that argument went so smoothly. It worked because of something about the numbers two and three that is easy to walk past.
Two identical squares can be joined into a rectangle in exactly one way. Side by side. There is no second arrangement to be clever with. Three is the same. One row of three, and nothing else is available. But four is a different animal. Four identical squares make a long rectangle, four times as long as it is wide — or they make a square, two by two. With four, the number stops deciding the shape.
So what you proved was not a general law about splitting rectangles into squares. It was a fact about two, and a fact about three. And step back to see what the answer actually was. Not a size. A comparison. Two identical squares means the long side is twice the short one. Three means three times. Which is why no measurement was ever required, and why the problem could hand you a compass and quietly take the ruler away.
Eight by four works. Two by one works. Twenty by ten works. So does a rectangle a mile long and half a mile wide. As far as this question is concerned they are all the same rectangle. The size was never part of the answer. It was only ever the shape.
Where this fits
Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.
Builds on
- Constructing a square or rectangle from its side lengthsClass 6 · Ch 8, Playing with Constructions
- The two properties that define a rectangle, and the one more a square needsClass 6 · Ch 8, Playing with Constructions
- Working out the order in which a figure has to be drawnClass 6 · Ch 8, Playing with Constructions
- Every curve in these figures is part of a circleClass 6 · Ch 8, Playing with Constructions
Either side of this one
- The shortest and longest crossing inside a rectangleClass 6 · Ch 8, Playing with Constructions
- Why a rectangle's diagonals are equal, and when they split the corners evenlyClass 6 · Ch 8, Playing with Constructions