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Chapter 2 · Introduction to Linear Polynomials

A constant difference is the signature of a linear pattern

यह वीडियो हिंदी में भी · Watch in Hindi

Linear patterns and linear models10 min

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10 min.

Also recorded in Hindi.Englishहिन्दी

1, 3, 5, 7, 9 — every gap is 2, and a constant gap is the fingerprint of a linear pattern. But knowing the gap is not yet knowing the rule.

The idea

A fixed gap between consecutive terms is not merely a symptom of degree 1 — it is the thing that lets you build the rule without guessing, because the gap is the coefficient and the starting value fixes the constant. The tile figure makes this visible rather than lucky: each stage adds exactly two tiles to the one before, so the count at stage n has to be the single tile you began with plus two more for each of the n – 1 steps taken since. But the chapter also supplies its own counterexample. The auto-rickshaw fare has a fixed gap only after the first two kilometres, and its rule is printed with the restriction n ≥ 2 attached — proof that "constant difference" is a claim about a stretch of the data, not about a whole table.

What you should be able to do

  • Extend a drawn growing pattern by two or three further stages and tabulate the counts
  • Compute the differences between consecutive terms of a sequence and decide whether they are all equal
  • Derive a rule for the nth term of a growing pattern from the size of its repeated step and its first value
  • Justify the rule geometrically by pointing at what gets added at each stage
  • Use a rule in both directions: find the term at a given stage, and find the stage that yields a given term
  • Recognise a decreasing linear pattern and write its rule with a negative step
  • Identify the stretch of a table over which a linear rule is valid, and say what happens outside it
  • Check a claimed nth-term rule by substituting a value the table already shows

Words to know

TermDefinition in one lineFirst introduced
linear patterna run of numbers in which each consecutive gap is the same sizeprinted on p. 20, defined on p. 23
linear relationshipthe pairing of a stage number with the count it produces, when that pairing is linearprinted on p. 22
stageone step of a growing pattern, numbered from 1printed on p. 21 in Fig. 2.4 and on p. 22 in the table
sequencethe list of values a pattern produces, taken in orderprinted on p. 22
consecutive termstwo values that sit next to each other in the sequenceprinted on p. 22
nth termthe value at an unspecified stage, written as a rule in nprinted on p. 23
linear expressionan expression of degree 1, here the rule for the nth termprinted on p. 23
constant first differencethe fixed gap between consecutive terms, taken as the pattern's signaturean added compound; not printed in this chapter, which says "constant" and "difference" separately
range of validitythe stretch of stage numbers over which a printed rule actually holdsan added phrasing; not printed in this chapter, which attaches n ≥ 2 to Example 8 without naming the idea

Standard Hindi vocabulary in the middle column.

Where people slip up

  • "Find the next term, and you have found the pattern." The next term is one number. The rule has to work at stage 26 as well, and it has to be checkable against stages you have already drawn. Substitute back into the table every time.
  • "The rule is 'add two', so the rule is 2n." 2n gives 2, 4, 6 — the right gaps and the wrong values. The step fixes the coefficient; the starting value still has to be paid for, and here it costs a – 1.
  • "A decreasing pattern is not linear." Bela's ₹5 a day is as linear as the tiles. What matters is that the gap never changes size, not which way it points.
  • "If the gaps are equal somewhere, the whole table is linear." The fare table is the counterexample the chapter itself supplies. Its first gap is zero. Draw the gaps as labelled arcs between cells so the odd one out is visible.
  • "n ≥ 2 is just the textbook being careful." Substitute n = 1 and the formula returns ₹10 against a printed ₹25. The restriction is load-bearing.
  • "The fare rises by ₹15 per km from the start." It rises by ₹15 for each kilometre after the second. Ten kilometres buys eight increments, not ten — which is exactly why the chapter's calculation reads 15 × 8.
  • "Stage 0 must be part of the pattern." The tile pattern is numbered from stage 1 and 2n – 1 would give –1 at n = 0, which is not a count of tiles. Bela's table does start at day 0 — so whether the count starts at 0 or 1 is a fact about each situation, not a rule.
  • "Any target number has a stage." 47 tiles happens at stage 24; 48 tiles happens at no stage at all, because 2n – 1 is always odd. Worth one slide.
  • "The area of a rectangle is not linear — it has two dimensions." With the length pinned at 13 cm, the area depends on one quantity and is linear in it. Item 3 fixes the length precisely so that this is true.
Transcript1,272 words

Here is a pattern of square tiles, growing one stage at a time. Stage one is a single square. Stage two: a row of two, with one square resting on top of the right-hand one. Three tiles. Stage three: two rows of two, and the same single square on top. Five tiles. Stage four: three rows of two, and the cap. Seven tiles. One, three, five, seven. The question is not what comes next. Almost anyone can say nine. The question is how many tiles stage fifty needs, without drawing forty-six more pictures.

Put the counts in a row and keep going. One, three, five, seven, nine, eleven, thirteen. Now look at what happens between them, rather than at them. The counts themselves are all different, so there is nothing to notice there. The steps might not be. One to three is two. Three to five is two. Five to seven is two. Every gap is two, and the gap never changes. That is the whole signal. A quantity whose gaps are all the same size is called linear, and a constant gap is the fingerprint you look for.

But knowing the gap is not the same as knowing the rule. Watch how easy it is to get that step wrong. It goes up by two each time. So the rule is two n. That is the most natural guess in the topic, and it is wrong. Try it. Two times one is two. Two times two is four. Two times three is six. Two, four, six. Compare with one, three, five.

The gaps are right. Every gap is two, exactly as it should be. The values are wrong, every single one of them. And they are wrong by the same amount every time: one too many. The gap tells you what multiplies the stage number. It tells you nothing at all about where the pattern starts. So stop reading the numbers and look at the picture again. Every stage is the same two shapes. A block that is two tiles wide, and one lone square capping the right-hand column.

At stage one the block has no rows at all. Only the cap. At stage two the block has one row. At stage three, two rows. At stage four, three rows. So at stage n the block has n minus one rows. And each row holds two tiles. Which gives the count directly. Two times n minus one, for the block, plus one for the cap. Check it at stage four. Two times three is six, plus one is seven. Seven tiles, which is what we counted.

Now open the bracket. Two n minus two, plus one, is two n minus one. There is the rule, and every piece of it came off the drawing. The two is the width of the block. The n minus one counts the rows added since stage one. The minus one that survives is the price of starting late. Compare that with the guess. Two n was right about the growth and silent about the start. This one knows both.

A rule earns its keep by answering questions the drawing cannot. Stage fifteen. Two times fifteen is thirty, minus one, twenty-nine tiles. Stage twenty-six. Fifty-two minus one. Fifty-one tiles. Now run it the other way. Somebody hands you twenty-one tiles and asks which stage that is. Two n minus one is twenty-one. So two n is twenty-two, and n is eleven. Forty-seven tiles the same way. Forty-eight, halved, is stage twenty-four.

And you can always check a backwards answer forwards. Two times twenty-four is forty-eight, minus one, forty-seven. It holds. Now try forty-eight tiles. Two n minus one is forty-eight. Two n is forty-nine. And n is twenty-four and a half. There is no stage twenty-four and a half. So no stage has forty-eight tiles. That is not a failure of the arithmetic. It is the rule telling you something true.

Two n is even, and one less than an even number is odd. Every count this pattern can produce is odd. So half of all the numbers you could name are unreachable, and the rule knows which half. Nothing so far required the pattern to grow. Someone starts with a hundred put aside and spends five of it every day. Day zero, a hundred. Day one, ninety-five. Day two, ninety. Day three, eighty-five. Day four, eighty.

The gaps are minus five, minus five, minus five, minus five. Constant. Negative, but constant, and that is all the definition asks for. A hundred to start, minus five for each day. Day twelve leaves forty. Day fifteen leaves twenty-five. And on day twenty there is nothing left. Notice this record begins at day zero, so the starting amount is sitting right there in the data. The tile pattern had no stage zero. Where the counting starts is a fact about the situation, not about linearity.

Now a case that does not behave. A ride opens at twenty-five, and that covers the first two kilometres. After that, each further kilometre adds fifteen. So the first two kilometres cost the same as each other, because they are both covered by the opening charge. One kilometre, twenty-five. Two kilometres, still twenty-five. Three kilometres, forty. Four, fifty-five. Five, seventy. Six, eighty-five. Look at that table for a moment before we do anything to it.

Take the gaps. Twenty-five to twenty-five is zero. Then fifteen. Then fifteen, fifteen, fifteen. Zero, fifteen, fifteen, fifteen, fifteen. Those are not all the same. This is not a constant-difference run. But it very nearly is. Cover the first entry, and everything left is perfectly regular. The pattern is linear from the second kilometre onward, and not before. Which means the honest description is not a rule by itself. It is a rule together with the stretch it covers.

Build the rule on the part that behaves. Twenty-five to begin, plus fifteen for every kilometre past the second. Twenty-five plus fifteen times n minus two. Ten kilometres. Ten minus two is eight, and eight is the number of increments you pay for. Not ten. Fifteen eights are a hundred and twenty. Plus twenty-five is a hundred and forty-five. Open the bracket and it tidies to fifteen n minus five.

Now feed that tidy rule one kilometre. Fifteen minus five is ten. The actual fare is twenty-five. So the restriction is not caution and it is not decoration. Outside its range the rule does not go quiet. It gives a confident answer that is simply false. One last thing, because the gap being two hid it. Take a rectangle whose length is pinned at thirteen, and let the breadth run twelve, ten, eight.

The areas are a hundred and fifty-six, a hundred and thirty, a hundred and four. The gap is minus twenty-six. But the breadths did not step by one. They stepped by minus two. And thirteen times minus two is minus twenty-six. The gap in the output is the multiplier times the step you chose in the input. Once more, going up. A box with a seven by eleven base, and heights five, nine, thirteen.

The volumes are three hundred and eighty-five, six hundred and ninety-three, a thousand and one. The heights step by four. The base area is seventy-seven. And seventy-seven fours are three hundred and eight, which is exactly the gap. So a constant gap is a fingerprint, and the size of that gap is the multiplier scaled by your own step size. Find the gap, then ask what the start costs you, and then ask where it stops being true. All three, every time.

Where this fits

Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.

Builds on

Comes up again in

The book

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