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Chapter 7 · Area

Why the area of a triangle is half base times height

Triangles, and every polygon after them10 min

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10 min.

Draw a triangle inside a rectangle and slide its top corner along the top edge. The shape changes at every step and the area never does.

The idea

Any triangle can be shut inside a rectangle whose two sides are exactly the triangle's base and its height, and the perpendicular dropped from the apex cuts triangle and rectangle together so that each piece of the triangle is the half of its own little rectangle. So the ½ is not a fudge factor bolted onto a product — it is a rectangle bisected by its diagonal, applied twice. And because the construction only ever touches one side and the perpendicular distance to the opposite corner, no other measurement of the triangle is allowed to matter. That is the real content: the slant is irrelevant, the same triangle gives the same answer whichever of its three sides you nominate as the base, and the rule survives even the awkward triangle you cannot box on that base at all.

What you should be able to do

  • Show that a triangle on one side of a rectangle, with its apex anywhere on the opposite side, is half that rectangle
  • Construct the enclosing rectangle for a given triangle from a chosen base: two perpendiculars at the base's ends and a parallel through the apex
  • Justify that the figure so constructed is a rectangle, and that its shorter side equals the triangle's height
  • Compute a triangle's area from any one side and the height belonging to that side, and give the answer with a squared unit
  • Handle the case in which the foot of the perpendicular falls outside the chosen base, by writing the triangle as the difference of two others
  • Given a triangle's area and one side, recover the height belonging to that side
  • Use two different base-height pairs on one triangle to find an unknown altitude
  • Convert a given triangle into a rectangle of equal area and back again, and say which measurement each conversion preserves
  • Compare the areas of a triangle and a square built on the same sidelength, and justify the comparison without computing any square root

Words to know

TermDefinition in one lineFirst introduced
basethe side of a triangle chosen to measure from; any of the three may be chosenprinted in this chapter, Part II §7.1 (Part II p.153)
heightthe perpendicular distance from the chosen base to the opposite vertexprinted in this chapter, Part II §7.1 (Part II p.154)
altitudethe perpendicular segment itself, drawn from a vertex to the opposite sideprinted in this chapter, Part II §7.1 (Part II pp.153, 155, 158)
congruentable to be laid exactly on top of one another, so equal in every measurementprinted in this chapter, Part II §7.1 (Part II pp.150, 155)
Śulba-Sūtrasthe ancient Indian texts on altar construction from which this chapter takes several shape-transformation problemsprinted in this chapter, Part II §7.1 (Part II p.158)
sq. unitsthe unit the chapter writes when the lengths are given without a named unitprinted in this chapter, Part II §7.1 (Part II pp.155, 158)
isosceleshaving two sides of equal lengthprinted in this chapter, Part II §7.1 (Part II pp.158, 164)
equilateral trianglea triangle with all three sides equalprinted in this chapter, Part II §7.1 (Part II p.164)
enclosing rectanglethe rectangle built on a chosen base that just contains the trianglean added term; the chapter builds the figure and calls it only the outer rectangle
base-height pairone side of a triangle taken together with the height belonging to that sidean added term; the chapter changes pairs on Part II p.155 without naming the move

Where people slip up

  • "The height is the slanted side." It is the perpendicular distance from the base to the opposite vertex, and in items (ii) and (iii) of Part II p.157 those two things are visibly different. This is the single most common error on the topic.
  • "The height has to be inside the triangle." Part II p.154's lower figure and Part II p.158's second item both put the foot outside the base. The formula does not care; the picture does.
  • "½ base times height is a rule you memorise." It is a rectangle halved by its diagonal, twice over. If the explanation cannot show the two little rectangles, it has not taught the topic.
  • "A triangle has one base." It has three, each with its own height, and the three products all come to the same thing. Part II p.155 exists to prove it.
  • "Half of the rectangle means half the drawn unit squares are whole." The diagonal slices through squares. The halving comes from congruence, not from the grid being obliging.
  • "You need all three sides to find the area." You need one side and the height belonging to that side. Mixing a side with the wrong height is the second most common error, and Part II p.155 is where it shows up, because three numbers are given and only two of them pair.
  • "If the base cannot be boxed, the formula fails." Part II p.154 handles it by subtraction, and the subtraction works because the three points lie on one line in a known order.
  • "An equilateral triangle and a square on the same side must be close in area." The square is more than twice the triangle. The height-less-than-side argument settles it in one line.
  • "Remaking a shape means keeping its sides." The Śulba-Sūtras problems keep the area and change everything else. Say which quantity is being preserved each time, or the exercises look arbitrary.
Transcript1,449 words

Here is a rectangle, five across and four up. Draw a triangle inside it: the rectangle's bottom side is the triangle's bottom side, and its top corner sits somewhere along the top edge. Now slide that top corner along. The triangle changes shape completely. It leans left, it stands upright, it leans right. The area does not move. Ten, ten, ten, ten, ten. And ten is exactly half of twenty, which is what the rectangle holds.

So every one of those triangles is half the rectangle. Why should sliding that corner change nothing? Drop a perpendicular from the top corner straight down to the bottom side. Wherever the corner sits, that perpendicular is the same length, because the top edge and the bottom edge are a fixed distance apart. Sliding along the top does not get you any nearer the bottom. That distance has a name. It is the HEIGHT of the triangle, and it is measured straight down to the side you started from - never along a slanted side.

And here is a stranger version of the same thing. Put the corner on the left-hand edge instead, and measure that triangle against the right-hand edge. Its area is ten as well. Two triangles that do not share a single side, in the same rectangle, coming out equal. So what does a triangle's area actually need you to measure? Not three sides. Just two numbers: one side, and the height belonging to that side.

In this figure they are marked. Five along the bottom, four up the left. Half of five times four is ten, and ten is what we counted. Two measurements, and the rest of the triangle is not consulted at all. That was easy: the triangle came ready-boxed. Now take one that arrived on its own. Choose one of its sides to work from. At each end of that side, draw a line straight up, at right angles to it. Then draw a line through the top corner, parallel to the side you chose.

Those three lines close the triangle inside a box. That box is a rectangle: two of its sides are perpendicular to the base by construction, and the fourth is parallel to it. One side of the box is the side you chose, five long. The other is the perpendicular distance up to the top corner, which is three. The box holds fifteen. The triangle holds seven and a half. Half again. But saying half again is not explaining it.

So let us explain it. Drop the perpendicular from the top corner. It lands inside the base, and it cuts the box into two smaller rectangles - one of six, one of nine. The same line cuts the triangle into two pieces at the same moment. Look at the left piece. It sits in the left rectangle, and the side slanting across it runs corner to opposite corner. It is that rectangle's diagonal.

A diagonal cuts a rectangle into two triangles you could lay exactly on top of each other. So the left piece is half of six, which is three. The right piece is the same story in its own rectangle. Half of nine is four and a half. Three and four and a half is seven and a half. That is where the half comes from. It is not a fudge factor bolted onto a product. It is one rectangle halved by its diagonal, used twice, and then added back up.

Notice what never came into that argument. The two slanting sides of the triangle were never measured. In this one, neither of them can be: their lengths are not numbers you can write down exactly at all. It does not matter. The area is seven and a half, exactly, and nothing that was needed to get there was a slant. One side, and the perpendicular distance from it to the opposite corner. That is the whole input.

One warning, because half a rectangle sounds like it should be visible in the squares. Take the rectangle five by four and its diagonal. Twenty unit squares in it. Count the squares lying wholly under the diagonal: six. Squares wholly above: six. And eight squares that the diagonal slices straight through. Six is not ten. The whole squares alone fall four short of the answer, and the eight cut ones supply exactly that four between them.

So the halving is not something you read off the grid. It comes from the two halves being the same triangle laid two ways up. Now the case that looks like it should break everything. Here is a triangle whose top corner leans right out past the end of the side we want to work from. Drop the perpendicular and it lands outside the base altogether - half a base-length before the near end, off the edge of the triangle.

There is no box to build: the rectangle on that side does not contain the triangle, and the perpendicular cuts nothing in two, because there is nothing on one side of it to cut. So can we still say half base times height? Run the perpendicular down and mark where it lands. Call that the foot. From the foot to the far end of the base is a distance we can box: that triangle has area eighteen.

From the foot to the near end is a smaller one we can box too: area six. Take the small one away from the big one and what is left is exactly the triangle we wanted. Eighteen take away six is twelve. And half of six times four is twelve as well. The subtraction works for one reason, and it is worth saying out loud: the foot, the near end and the far end lie on one straight line in that order, so nine minus three really is the six between the two ends. Change the order and the argument goes.

A triangle has three sides, so it has three of these pairs. Each side has its own height. Take this one. Side four with height three. Side three with height four. And the long side, five, whose height is two point four - not a whole number at all. Multiply each pair: twelve, twelve, twelve. Halve them: six, six, six. Which is the area - of course it is, because the triangle only has one.

You may nominate whichever side you like as the base. What you may NOT do is take one side and pair it with a height belonging to a different one. That turns straight into a way of finding a length nobody handed you. Here is a triangle with a height of three onto a side of five, and another side, four long, whose height is not marked. First pair: half of five times three is seven and a half.

Second pair: half of four times that unknown height is the same seven and a half. So the unknown height is fifteen over four. Three point seven five. Nobody measured it. It was forced: a triangle has one area and three ways to write it. The same trick handles the leaning triangle from before. Six times four halved is twelve, and twelve read against a side of eight gives a height of three.

One last thing this buys you. Old altar builders had a problem: a shape was prescribed, and so was its area, and the two did not always agree. So they had to remake one shape as another holding the same. A rectangle six by four holds twenty-four. As a triangle, keep the six and double the height to eight. Or keep the four and double the base to twelve. Both hold twenty-four.

Backwards, a triangle on six with height four holds twelve, and becomes a rectangle six by two, or three by four. Nothing keeps its sides. What is kept is the area, and the halving is what lets you trade one for the other. And finally, a comparison you can settle without a calculator. An equilateral triangle and a square, built on the same length. Which holds more? The triangle's height is one leg of a right angle whose longest side is the triangle's own side. A leg is always shorter than the longest side. So the height is less than the side.

The triangle is half the side times something smaller than the side. The square is the side times the side. So the square wins, and it wins by so much that two of those triangles together still come to less than it. No square roots. Just half base times height, and knowing which length is the height.

Where this fits

Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.

Builds on

Comes up again in

Either side of this one

The book

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