PrepShorts · Study sheet · Class 8 Mathematics · Chapter 7, Area
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Every flat shape gives you two numbers: how far round the edge, and how much is inside. Neither one decides the other.
The idea
Boundary length and area are not two readings of one size. They are independent because a region has a free dimension nobody names — its thinness — and moving it drives one measure up while the other goes down. Stretch a fixed amount of material long and thin and the boundary grows without any limit at all; hold the boundary fixed and the material inside can be squeezed toward nothing. So no boundary length can predict an area, and no ordering of two perimeters forces the same ordering of their areas. That is the reason the chapter counts unit squares rather than measuring edges: only the count adds up correctly when a region is cut into pieces.
What you should be able to do
- State what a measure of area is required to do that boundary length fails to do
- Produce two rectangles with equal perimeters and unequal areas, and verify both claims by computation
- Produce two regions in which the larger perimeter belongs to the smaller area, and say which of the two comparisons each pair of numbers settles
- Hold a perimeter fixed and describe how the area varies as a rectangle is made thinner, including what it tends toward
- Hold an area fixed and show that the perimeter has no upper limit
- Construct a non-rectangular pair in which the comparison can be settled by looking rather than by arithmetic
- Recognise the same independence in three other figures of this chapter and say what stays fixed in each
- State the one genuine relation between the two measures, and why it is an inequality rather than a formula
Words to know
| Term | Definition in one line | First introduced |
|---|---|---|
| perimeter | the total length of the boundary of a region | printed in this chapter, Part II §7.1 (Part II p.150) |
| area | the number of unit squares whose material would exactly fill a region | printed in this chapter from its title onward (Part II p.148) |
| region | a piece of the plane with a boundary; the chapter labels two of them Region 1 and Region 2 | printed in this chapter, Part II §7.1 (Part II p.150) |
| unit square | the square whose side is one unit of length, used as the thing being counted | printed in this chapter, Part II §7.1 (Part II p.149) |
| grid paper | squared paper, which the chapter points the student to for constructing the counter-instances | printed in this chapter, Part II §7.1 (Part II p.150) |
| counter-instance | a single example that destroys a general claim | an added term; the chapter asks for two of them and does not name the move |
| thinness | the free choice left over once a region's area or perimeter has been fixed | an added term, and the organising idea of sections 5 to 7; not printed |
| isoperimetric comparison | that among all regions with one perimeter there is a largest area, and the square is the largest rectangle | an added phrasing; the chapter states no such result |
Where people slip up
- "Bigger boundary, bigger area." The 1 by 12 rectangle beats the 5 by 5 on boundary by 6 cm and loses on area by 13 cm². One pair kills the rule.
- "Same boundary, same area." The chapter's own two rectangles are 22 cm around apiece and differ by 4 cm². Students find this one the hardest to give up, because the boundary is what the eye follows.
- "Perimeter and area are the same thing measured in different units." They cannot be, because one of them can be changed while the other is held fixed.
- "Doubling the sides doubles both." The boundary doubles; the area quadruples. Part II p.152's fifth item is built on exactly this.
- "If they are independent then no comparison between them is possible." The square is extreme in both directions. Independence rules out a formula, not a bound.
- "The counter-instance needs strange shapes." Two rectangles are enough, which is precisely why the chapter asks for rectangles first and odd shapes second.
- **"A long thin shape only looks like it has less area."** Its unit-square count really is smaller. Overlay the grid and count.
- "Area cannot be squeezed to nothing while the boundary stays put." At 9.9 cm by 0.1 cm the boundary is still 20 cm and the area is under 1 cm². Push the example far enough that the trend is undeniable.
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Worked answers to this chapter’s exercises
Transcript1,284 words
Every flat shape gives you two numbers. One is how far it is round the edge. The other is how much material is inside - how many unit squares it would take to fill it. And there is an obvious shortcut sitting here. Measuring round the edge is easy. You can do it with a piece of string. Counting the inside is slow work. So why not just measure the edge and be done with it?
Before answering that, here is what a measure of material has to be able to do. Cut a shape into pieces. Whatever quantity we are measuring, the pieces have to total the whole. If they do not, the number is not measuring anything you could call an amount. The square count survives that. Cut the region anywhere and the counts of the parts add back up, because no material was created or destroyed.
The boundary does not survive it at all. Cut a shape in two and you have made new edge - the cut itself, counted twice, once on each piece. The two boundaries total more than the one you started with. So they are already different kinds of number. But that alone does not tell you how badly the shortcut fails. Take two rectangles. One is seven across and four down; the other is eight across and three down.
Go round the first: seven, four, seven, four. Twenty-two. Round the second: eight, three, eight, three. Twenty-two as well. Identical boundaries. Now count the insides. Twenty-eight squares against twenty-four. So the same boundary is sitting round two different amounts of material. Equal edge does not mean equal inside, and one pair of ordinary rectangles is enough to settle it forever. And these are not freaks. Among rectangles with sides up to twelve there are a hundred and twenty-five pairs that do exactly this.
Fine, you might say. Equal does not force equal. But surely bigger forces bigger - a longer boundary must hold more. Here is one that is one across and twelve down. Round the edge: twenty-six. Inside: twelve squares. And here is one that is five by five. Round the edge: twenty. Inside: twenty-five squares. The first has the longer boundary, by six. And it holds less material, by thirteen. The two measurements are not merely failing to agree. They are pointing in opposite directions. Up to twelve by twelve there are two hundred and seventy-four pairs where that happens.
Two examples kill the shortcut, but they do not explain it. For that, notice what we changed when we went from the square to the long thin one. We did not change the boundary by much. We did not set out to change the area at all. What we changed was how THIN the shape is. And thinness is a free choice. Fix the boundary and you have not fixed the shape - there is still a whole family of rectangles left, and you get to pick how stretched out yours is.
That leftover choice is the whole story. Every one of the strange pairs comes from moving it, and neither of the two numbers has a name for it. So let us hold one measurement absolutely still and move the thinness on purpose. Twenty units of boundary. Five by five: twenty-five squares inside. Six by four: twenty-four. Eight by two: sixteen. Nine by one: nine. The boundary has not moved once. It was twenty at every step, because widening one side by exactly what you take off the other cannot change the total round the edge.
But the inside has gone from twenty-five to nine, and it is still falling. Nine point nine by nought point one is still twenty round the edge, and holds nought point nine nine. Which raises a question worth asking properly. How small can it go? Name any amount of material you like. However small it is, there is a rectangle with a boundary of exactly twenty that holds less than that.
You can always find one, because making the shape thinner shrinks the inside without ever touching the edge. There is no smallest member of this family. There is no floor. So a boundary of twenty tells you the area is at most twenty-five. It tells you nothing whatsoever about how much less. Now run it the other way. Fix the material and let the boundary do what it likes. Thirty-six squares. Six by six: twenty-four round the edge. Nine by four: twenty-six. Eighteen by two: forty. Thirty-six by one: seventy-four.
Every one of those holds exactly the same amount of material. Not a square more or less. And the last one has more than three times the boundary of the first. Seventy two by a half is still thirty-six squares, and it is a hundred and forty-five round the edge. This direction is the more startling of the two, because now there is no ceiling. Name any length. A thousand. A million. There is a rectangle holding exactly thirty-six squares whose boundary is longer than that - make it that many units wide, and it will be.
So for a fixed amount of material the boundary can be anything at all above a certain point, and for a fixed boundary the material can be anything at all below a certain point. That is what independent means. Knowing one of these numbers pins the other down on one side and leaves it completely free on the other. Here is a pair where you do not need any of that arithmetic.
A strip twelve long and one wide: twelve squares of material, twenty-six round the edge. Now cut nine narrow slits into it, almost all the way through, like the teeth of a comb. The material barely changes - it drops from twelve to eleven point one nine. But the boundary goes from twenty-six to forty-two point two, because every slit adds two long new edges and takes almost nothing away.
Twenty units of new boundary for every one unit of material given up. Slits are the cheapest way there is to buy edge. So put the comb beside a six by six square. The square holds more than three times the material and has little more than half the boundary - and you can see both of those without measuring anything. One more, and this one does not even change a sidelength.
Take the five by four rectangle and lean it over into a parallelogram. All four sides are exactly as long as they were, so the boundary is still eighteen. It cannot be anything else. But the height has dropped, and the area with it. Twenty squares becomes sixteen. Lean it further and it becomes twelve. Lean it further still and the material keeps falling, with the same four sidelengths and the same eighteen round the edge the whole way down.
Same four numbers on the sides. Any area you like. Now, independent does not mean unrelated. Look back at the family with a fixed boundary: the biggest inside belonged to the square. And the family with fixed material: the shortest boundary belonged to the square as well. That is a real relationship. But look at its shape. It says a boundary of twenty holds at most twenty-five squares, and thirty-six squares needs at least twenty-four of boundary.
At most. At least. It is a limit in one direction, and it names the extreme shape - not a formula, and never an answer. Which is why the material gets counted rather than measured round. The edge of a shape is a genuine thing to know. It is simply not a way of finding out what is inside.
Where this fits
Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.
Builds on
- Area as a count of unit squaresClass 8 · Ch 7, Area
Either side of this one
- Why the area of a triangle is half base times heightClass 8 · Ch 7, Area