PrepShorts · Study sheet · Class 8 Mathematics · Chapter 6, Algebra Play
Chapter 6 · Algebra Play
Why a "think of a number" trick always works, and how to invent one
This video could not be loaded. Reload the page to try again.
Sign in with Google10 min.
Keep your place in this chapter — sign in, it’s free.Sign in
Think of a number, double it, add four, halve it, take away the number. It always works, and testing it is not what makes it true.
The idea
A trick that "always works" is not lucky, and testing it is not what makes it true. Carry an unnamed number through the steps instead of a particular one, and the finished expression tells you everything: if the unknown ends up multiplied by nothing, the answer cannot depend on what you started with, and whatever constant survives is the prediction. The chapter's second trick turns the same tool the opposite way round — its steps are rigged so that two unknowns land on two separate decimal shelves, so the final number is not a collapse but a coded record of them. Once you can read the expression, you stop being the audience and become the person who designs the trick.
What you should be able to do
- Follow a stated chain of arithmetic instructions with a letter in place of the starting number, writing the expression after each instruction
- Explain why a predicted answer is forced, by pointing at the step where the unknown's multiplier becomes nothing
- Alter one step of a trick so that it lands on a stated answer instead, and say which step controls the answer and why
- Invent a longer chain of instructions that always ends on the same value, and state the condition such a chain has to satisfy
- Track two unknowns — a month and a day — through six instructions and write the final expression
- Explain why the reported total can be decoded, using the fact that one unknown has been multiplied by a hundred and the other is small enough to fit in the last two places
- Recover a date from a reported total by subtracting the accumulated constant
- Redesign the date trick with different steps and work out the new constant that has to be subtracted
Words to know
| Term | Definition in one line | First introduced |
|---|---|---|
| Think of a Number | the chapter's name for a trick in which someone follows arithmetic instructions on a secret number and the performer predicts or recovers something | printed as the section heading and in the text, Part II §6.2, pp.135–137 |
| letter-number | the book's word for a letter standing in for a number that is not known yet | printed in Part II §6.1, p.135, and again in §6.3, p.139 |
| unknown | a quantity whose value is not given and has to be carried or found | printed in Part II §6.1, p.135 |
| expression | what you get by combining letters and numbers with arithmetic, without an equals sign | printed in Part II §6.3, p.140 |
| equation | a statement that two expressions are equal, which can then be solved | printed in Part II §6.1, p.135 |
| place value | the weight a digit carries because of the position it sits in | standard NCERT terminology from earlier chapters; the phrase is not printed in this chapter, though §6.2 relies on it |
| coefficient | the number an unknown is multiplied by in an expression | not printed in this chapter; an added word for the thing the argument watches |
| accumulated constant | the single number the additions in a chain leave behind after all the later multiplications have acted on them | an added term; this chapter computes the number without giving it a name |
Where people slip up
- "It works because I tried it and it worked." Three successes are three successes. The expression covers every starting number at once, and that is a different kind of statement — this is the distinction the chapter's SUMMARY (Part II p.147) calls algebra's role in justification.
- "Halving undoes the doubling, so the +4 goes away too." It does not go away; it becomes +2. Students who treat division as an eraser get a prediction of 0 and then decide the trick is broken.
- "The prediction is 2 because the trick says so." The prediction is 2 because 4 was the number added before the halving. Change that one number and the prediction moves with it — which is exactly what the page asks for next.
- "The final subtraction is what makes the answer constant." The subtraction is the last of several moves; what matters is the total effect on the unknown. A chain that ends with the same subtraction but doubles without halving leaves the unknown standing, and predicts nothing.
- "The date trick works the same way as the first one." It works the opposite way. The first trick destroys the information; the date trick preserves it, in separate decimal slots. Both are read off the same kind of expression.
- "Any change to the steps keeps 165." 165 is built out of the particular additions and the multiplications that follow them. Move the 9 earlier and it gets multiplied twice; the number to subtract changes.
- "The trick would work whatever the day was." It needs the day to fit inside the last two places. A day of 31 is fine; a quantity of 150 would spill into the hundreds and the decode would name the wrong month.
- "The performer must be doing mental arithmetic very fast." The performer does one subtraction. Everything else was decided when the steps were designed.
Ask your teacher a person
Your teacher reads this and writes back, usually within a day. For an instant answer, use Ask the video in the sidebar.
Your class sees the question and the answer. Only your teacher sees that it was you.
No questions on this topic yet.
Worked answers to this chapter’s exercises
Transcript1,380 words
Think of a number. Do not tell me what it is. Double it. Add four. Halve what you now have. And take away the number you started with. You are looking at two. Try it again with a different number. Try it with seven, with thirteen, with a hundred. Seven gives two. Thirteen gives two. A hundred gives two. Three different numbers, three different journeys, and all three land on the same tile.
So the question is not whether it works. The question is why it cannot fail - and whether you could design one of your own. Here is the tempting answer: it works because I tried it and it worked. But three successes are three successes. They are not a statement about every number, and there are infinitely many numbers you did not try. You could run a thousand of them and still be describing a thousand cases.
What you want is a different KIND of statement - one sentence that covers every starting number at once. And there is a way to get one, which is the whole reason algebra is worth learning. Stop putting a particular number in. If you never commit to a value, you never have to check the values one at a time. Instead of seven, send a letter through the steps. Call the secret number n. Not a mystery to be solved - just a number whose value we are refusing to fix.
Double it, and you have two n. Add four, and you have two n plus four. Halve it. Two n plus four, halved, is n plus two. And take away the number you started with. n plus two, less n, is two. No n anywhere. The answer is two, and the letter has gone. Watch what happens to the letter, and only to the letter. It starts multiplied by one. Doubling makes it two. Halving brings it back to one. Taking away the start brings it to nothing.
That last step is where the trick is decided. Once n is multiplied by nothing, the answer CANNOT depend on what you started with. There is nowhere for your number to show up. And what is left over is the prediction. Now notice what the halving did to the four. People say the halving undoes the doubling, so the four goes away too. It does not go away. It becomes a two.
If you treat dividing as an eraser you predict nought, and then you decide the trick is broken. So where did the two actually come from? From the four. The four is added before the halving, so half of it survives. Change the four and the prediction moves with it. Suppose you want the trick to land on three. Then you need to add six, because six halved is three.
Want it to land on five? Add ten. The added number is always twice the answer you want, and nothing else in the chain has to change at all. One step controls the answer. That is not something you would ever notice by trying numbers. Now you can build your own, as long as you like. Think of a number. Treble it. Add twelve. Divide by three. Take away the number you started with.
Follow the letter: three n, three n plus twelve, n plus four, and then four. The prediction is four. And the twelve became a four for the same reason the four became a two - it was divided along with everything else. There is only one condition, and it is worth saying plainly. The letter's multiplier has to reach nothing by the last step. Whatever number is left standing when it does is your prediction.
Break that condition and there is no trick. Double, add four, take away the start, and you are left with n plus four. The answer still depends on the number, so nobody can predict it. Now the same tool, turned the other way round. This time the secret is a date - your birthday, say - and I am going to read it back to you off a single number.
Take the number of your month. Multiply by five. Add six. Multiply by four. Add nine. Multiply by five. And finally add the day of the month. Tell me the total. Suppose the date is the twenty-sixth of January. One times five is five. Plus six is eleven. Times four is forty-four. Plus nine is fifty-three. Times five is two hundred and sixty-five. Plus twenty-six is two hundred and ninety-one.
Two hundred and ninety-one. And from that, I can tell you the date. Send letters through it. Call the month m and the day d. Five m. Five m plus six. Twenty m plus twenty-four. Twenty m plus thirty-three. A hundred m plus a hundred and sixty-five. And then the day joins on: a hundred m plus a hundred and sixty-five plus d. Look at what did NOT happen. The month's multiplier never reached nothing. It reached a hundred.
The first trick destroyed the information. This one keeps it, and keeps the two secrets apart. That is the same expression doing the opposite job, and you read both of them the same way - by watching the multipliers. Why a hundred? Because the three multiplications are five, four and five, and five times four times five is a hundred. And a hundred is exactly what you want, because it lifts the month clear of the last two places.
The day is at most thirty-one, so it fits inside those two places with room to spare. The month sits above them. Nothing overlaps. Take two hundred and ninety-one and subtract a hundred and sixty-five. That leaves one hundred and twenty-six. The one in front is the month. The twenty-six behind it is the day. The twenty-sixth of January, written out in digits, and it was sitting there the whole time.
Where does the hundred and sixty-five come from? It is not a magic number and you do not have to memorise it. It is what the additions leave behind after everything that comes AFTER them has acted. The six is added early, so it gets multiplied by the four and then by the five. Six times four times five is a hundred and twenty. The nine is added later, so it is only multiplied by the last five. Nine times five is forty-five.
A hundred and twenty plus forty-five is a hundred and sixty-five. So the performer does one subtraction. That is the whole performance. Everything else was decided when the steps were written. Try three. Someone reports one thousand two hundred and sixty-nine. Subtract a hundred and sixty-five: eleven hundred and four. The fourth of November. Three hundred and ninety-four. Subtract: two hundred and twenty-nine. The twenty-ninth of February. Two hundred and ninety-six. Subtract: one hundred and thirty-one. The thirty-first of January.
Now, the twenty-ninth of February is not a day that exists in every year, and the trick has no idea. It decodes a month and a day. It was never told about years. It does not check anything else either. Report a quantity of a hundred and fifty instead of a day and it climbs onto the month's shelf, and the answer comes back confidently wrong. The trick needs the second number to fit in two places. It does not verify that it does, and neither does the person performing it.
That is worth knowing about any procedure that reads an answer out of a single number: it works inside conditions nobody stated aloud. So rebuild it your own way. Take the month. Multiply by ten. Add three. Multiply by ten again. Add the day. The month is still carried up by a hundred, so the two secrets still land on separate shelves. But the three is only multiplied by the second ten, so the additions accumulate to thirty, not a hundred and sixty-five.
Same date, different total, different subtraction. Thirty is what you take off. And that is the point of the whole thing. Once you can read the expression, you are not the audience any more. The trick was never in the numbers. It was in knowing what the letter was going to be multiplied by.
Where this fits
Either side of this one
- Telling a story with data, and letting it raise the next questionClass 8 · Ch 5, Tales by Dots and Lines
- Number pyramids: what the top cell is made ofClass 8 · Ch 6, Algebra Play