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Chapter 6 · Algebra Play

Algebra grids: every row is an equation, and the shapes are the unknowns

Patterns you can prove9 min

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9 min.

A grid of drawn shapes with a number at the end of each row is a system of equations wearing a picture.

The idea

A grid of coloured shapes with a number at the end of each row is a system of equations in disguise, and every move you make on it is an algebraic move wearing a picture. A row made entirely of one shape hands you that shape's value outright, because division is what "several copies of the same thing total this" means. Once one value is known, every other row has a single unknown left, and the puzzle unwinds. The deeper point is why any of this is legitimate: the shapes stand for fixed numbers across the whole grid, so the rows are separate statements about the same quantities — and that is also why a row can be printed with its total missing and still not be a new unknown.

What you should be able to do

  • Read a row of an algebra grid as an equation and write it out in letters
  • Identify the row that can be solved on its own, and say what makes it solvable
  • Solve for one shape's value by division, and justify the division
  • Substitute a known shape into another row and solve for the remaining shape
  • Check a proposed pair of values against every row of the grid
  • Complete a row whose total is left blank, and explain why that blank is not an extra unknown
  • Recognise two rows that carry the same information despite being drawn differently, and say why no work is needed on the second
  • Recognise a row that pins nothing down, and say what it would need in order to

Words to know

TermDefinition in one lineFirst introduced
grida rectangular arrangement of cells in rows and columnsprinted in Part II §6.4, p.141, and used for these puzzles on p.142
shapea drawn symbol standing for a number that is the same wherever that symbol appearsprinted in Part II §6.4, p.142, in the Algebra Grids passage
rowone horizontal line of the grid, which here carries one statementprinted in Part II §6.4, p.142
columnone vertical line of the grid; the last one carries the totalsprinted in Part II §6.4, p.142
sumthe total of the values standing to the left in the same rowprinted in Part II §6.4, p.142
equationa statement that two expressions are equal, which can then be solvedprinted in Part II §6.1, p.135
letter-numberthe book's word for a letter standing in for a number that is not known yetprinted in Part II §6.1, p.135, and in §6.3, p.139
unknowna value not given, which the grid is arranged to let you findprinted in Part II §6.1, p.135
simultaneous equationstwo or more equations about the same unknowns, to be satisfied togetheran added term; the phrase is not printed in this chapter, which does the thing without naming it
independent rowsrows that carry genuinely different information about the same shapesan added term, and not printed in this chapter
determined valuea value with nothing left to choose, because the rows already fix itan added term, and not printed in this chapter

Where people slip up

  • "The shapes and colours mean something." They are names. A blue square is an unknown called "blue square"; nothing about squareness or blueness enters the arithmetic. Replacing every shape with a letter, once, settles this permanently.
  • "A shape might mean different things in different rows." Then no row would constrain any other and the puzzle would be unsolvable. That the same shape holds the same value throughout is the assumption doing all the work, and it deserves to be said aloud.
  • "Two rows cannot settle two unknowns." They can, provided they say different things. The reader's grids do exactly this, and the third row in each is a check rather than a necessity.
  • "The blank total is a third thing to find." It is fixed the moment the shapes are known. Students treat it as an unknown and then complain there are too many.
  • "You must work the rows in the order they are printed." Start wherever the arithmetic is easiest. In the chapter's worked grid that happens to be row 1; in the reader's first grid there is no such row and you must combine two.
  • "Row 3 is more work because the shapes are in a different order." It is no work at all. Recognising this is a genuine algebraic insight, not laziness.
  • "Every grid has one answer." The empty fourth row of the second grid does not, and could not. A row constrains its shapes only if it has shapes in it.
  • "Guess-and-check is as good as solving." It finds these two answers quickly and teaches nothing transferable. The point of the section is that the picture is a system of equations, and the method scales to grids guessing cannot reach.
Transcript1,311 words

Here is a puzzle that looks like a game and is not. A grid. Each row holds some drawn shapes, and at the end of the row there is a number. The rule is that the number is the total of the shapes beside it. Three squares, and twenty-seven. Two circles and a square, and nineteen. That is all you are told. And it is enough to work out exactly what a square is worth, and exactly what a circle is worth.

The interesting question is not what the answer is. It is why a picture can settle anything at all. Because on the face of it you have two facts and two things you do not know, and that ought to be nowhere near enough. Start by taking the pictures away. Write a letter inside every square and a different letter inside every circle. Now the first row says s plus s plus s is twenty-seven, and the second says c plus c plus s is nineteen.

Nothing was lost doing that. Which tells you something: the shapes were never doing any mathematical work. Nothing about squareness, nothing about the colour. They are names. But there is an assumption hiding in there, and it is the assumption the whole puzzle rests on. A square means the same number in every row. Every square, everywhere on the grid, is the same number. Drop that, and no row would tell you anything about any other row, and there would be nothing to solve.

Now, where do you begin? Look at the first row. Every cell in it holds the same shape. That is the row that gives itself away, because it has only one unknown in it. Three of one thing, adding to twenty-seven. The second row cannot do that. It has two unknowns in it, and one statement about two unknowns pins down neither. So if a grid has a row made entirely of one shape, that is where you start. Always.

And you do not have to work the rows in the order they are drawn. Start wherever the arithmetic is easiest. Three squares make twenty-seven. So a square is nine. Take a second on why that step is allowed, because it goes past very fast. Twenty-seven has been split into three equal parts, and each part is one square. That IS what dividing means. Not a rule you apply - the thing the row is already saying.

And now write nine into every square on the grid at once. Not just the row it came from. Every one. That is the assumption from a minute ago finally earning its keep. So look at the second row again. It was two circles and a square, totalling nineteen. The square is not unknown any more. It is nine. Two circles and nine make nineteen. And notice what just happened to that row. It had two unknowns in it and now it has one. It has become the kind of row we already know how to finish.

That is the whole engine of this thing. Find a row with one unknown, solve it, and watch another row lose an unknown. Two circles and nine make nineteen. Collect the circles first. There are two of them, so that is twice the circle, plus nine, equal to nineteen. That collecting step is the one most people skip, and it is the one that turns a picture into something you can operate on.

Take nine off both sides: twice the circle is ten. Share both sides by two: the circle is five. Nine and five. Two shapes, two rows, and no guessing anywhere. Now check it, and check it against both rows, not just the one you finished on. First row: nine and nine and nine. Twenty-seven. Right. Second row: five and five and nine. Nineteen. Right. This matters more than it sounds. Two values that satisfy the row you solved last are guaranteed - you built them from it. The question is always whether they survive the other rows.

These do. So they are the answer, and not merely an answer. Now a harder one, and the difficulty is not the arithmetic. Three rows this time. Two squares and a circle make twenty-seven. Two circles and a square make twenty-one. And a third row whose total has been left blank. Look for the row made of one shape. There isn't one. Every row has both unknowns in it. There is nowhere to start.

So the move that worked last time is simply not available, and this is exactly the moment most people stall. Here is what to do instead. If no row has one unknown, MAKE one. Take the first row twice. Two of it: four squares and two circles, totalling fifty-four. Now take the second row away from that. The two circles cancel with the two circles, and one square comes off the four.

What is left is three squares making thirty-three. A row with one unknown, which we built rather than found. So the square is eleven. Put that into the second row: two circles and eleven make twenty-one, so twice the circle is ten, and the circle is five again. Check both rows. Twenty-two and five is twenty-seven. Ten and eleven is twenty-one. Both hold. Which leaves the third row, the one with the blank total.

People treat that blank as a third thing to find, and then complain there are too many unknowns. It is not. The moment the shapes are known, that total is fixed - there was never anything to choose. Five, eleven and five. Twenty-one. But look more carefully. That third row holds a circle, a square and a circle. The second row held a circle, a circle and a square. Same three shapes. Different order. And adding does not care about order.

So the third row's total is twenty-one, and you can say so without doing a single sum. That is not laziness. That is seeing what the row actually says. One more grid, because it contains something genuinely strange. A circle and two diamonds make eighteen. A diamond and two circles make fifteen. Same move as before: take the second row twice, take the first away, and three circles make twelve.

So the circle is four and the diamond is seven. Check: four and fourteen is eighteen; eight and seven is fifteen. The third row repeats the second exactly, so its total is fifteen with no work at all. And then the fourth row. Every cell of it is empty, the total included. You cannot complete that row, and not because it is hard. Three empty cells could hold twelve, or fifteen, or eighteen, or twenty-one, depending on what you put in them. A row constrains its shapes only if it has shapes in it.

So step back and look at what we were actually doing. Each row was an equation. The grid was several equations about the same unknowns, all true together. Solving it was three moves and no others: find a row with one unknown, or build one by combining rows; solve it; and carry the answer into every other row. The shapes never mattered. Neither did the picture. What mattered was that a symbol held one fixed number everywhere it appeared, which is the entire reason the rows could talk to each other.

And that is worth knowing, because guessing would also have found nine and five. It would not have found eleven and five, and it will not find anything on a grid with five shapes in it. So the next time a puzzle hands you shapes and totals, do not look for a clever guess. Write the rows out and see which one has a single unknown standing in it. The picture was never the point. It was equations, drawn.

Where this fits

Either side of this one

The book

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