PrepShorts · Study sheet · Class 7 Mathematics · Chapter 1, Large Numbers Around Us
Chapter 1 · Large Numbers Around Us
Predicting how many digits a product will have, before multiplying
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You can say how many digits a product will have before you multiply. Checking examples and settling the question are different acts.
The idea
There are 8,100 ways to multiply one 2-digit number by another, and the chapter settles a claim about every one of them using two multiplications. It can, because how long a product is depends only on which size band its factors sit in: the smallest 2-digit number times itself already clears 100, and the smallest 3-digit number times itself only reaches 10,000. Everything is trapped between. This is the first place in the chapter where checking examples is replaced by an argument that covers cases nobody will ever check — and the patterns in the boxes just before it are there to show why examples alone are not enough.
What you should be able to do
- Evaluate a short chain of patterned products and describe the pattern in the answers
- State what a pattern in four examples does and does not establish
- Give the smallest and largest number having a stated count of digits
- Bound the product of two numbers by multiplying the extreme cases, and read the digit count off the bounds
- State how many digits the product of an m-digit and an n-digit number can have, and show that no other count is possible
- Decide whether a stated combination of digit counts can occur, giving a reason rather than an example search
- Say what the digit-count rule cannot tell you
Words to know
| Term | Definition in one line | First introduced |
|---|---|---|
| product | the result of a multiplication | printed in this chapter (Part I, §1.5, p.14) |
| digit | one of the ten symbols a number is written with | printed in this chapter (Part I, §1.1, p.2) |
| pattern | a regularity noticed across several worked cases | printed in this chapter (Part I, §1.5, p.14) |
| multiplication statement | a written line of the form so-many-digits × so-many-digits = so-many-digits | printed in this chapter (Part I, §1.5, p.15) |
| smallest 3-digit number | 100, used here as the ceiling for two-digit factors | printed in this chapter (Part I, §1.5, p.15) |
| bound | a value the answer is guaranteed to stay above or below | an added term, not printed in this chapter; the chapter performs the bounding without naming it |
| digit count | how many digits a written number has | an added compound, not printed in this chapter, which spells the idea out each time |
| proof by extremes | settling a claim about every case by testing only the two most extreme ones | an added label, not printed in this chapter |
Where people slip up
- "Four examples that fit means the pattern is true." Box four's neat reading breaks at 105 × 105. The chapter puts patterns immediately before an argument for exactly this reason.
- "You would have to try all the pairs." You would have to try 8,100. Roxie tries two. Naming the number 8,100 is what makes her move feel like a gain.
- "The largest product of two 2-digit numbers is 100 × 100." It is 99 × 99 = 9,801. Roxie multiplies 100 × 100 deliberately because it is easy and safely above every real case — that is the whole idea of a ceiling, and students read it as an error unless it is spelled out.
- "The product has as many digits as the two factors together." It has that many or one fewer. Both really occur.
- "The rule tells you the product." It tells you its length. 12-digit × 13-digit gives 24 or 25 digits and nothing more.
- "Multiplying always adds digits." 1-digit × 1-digit can stay at one digit: 2 × 3 = 6.
- "3-digit × 3-digit could be 4 digits if the numbers are small enough." The smallest they can be is 100 each, and that already gives five digits.
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Worked answers to this chapter’s exercises
Transcript1,332 words
Here are three multiplications. Eleven times eleven. One hundred and eleven times one hundred and eleven. And one thousand one hundred and eleven, times itself. Work them out and something lovely happens. One two one. One two three two one. One two three four three two one. The answers climb up and come back down, and each one is a step longer than the last. Here is another. Three times five is fifteen. Thirty three times thirty five is one thousand one hundred and fifty five.
Three hundred and thirty three, times three hundred and thirty five, is one hundred and eleven thousand five hundred and fifty five. Ones, then fives, and one more of each every time. These are genuinely satisfying, and they are the reason this part of the topic exists. Because they are about to teach us something quite different from what they look like. Try this one yourself. One hundred and one, times one hundred and one, is ten thousand two hundred and one.
One hundred and two times itself is ten thousand four hundred and four. One hundred and three times itself is ten thousand six hundred and nine. Look at those three answers and you can almost certainly see the rule. A one. A zero. Then double the small number. Then the small number squared. Two, then four, then six. And one, then four, then nine. Check it on the next one. One hundred and four squared should be one, zero, eight, sixteen. Ten thousand eight hundred and sixteen.
And it is. Four for four. At this point most people would call it a rule. So take one more step. One hundred and five. The rule says: a one, a zero, then ten, then twenty five. Which would be one hundred and one thousand and twenty five. The real answer is eleven thousand and twenty five. Not slightly out. Out by ninety thousand, and a whole digit shorter than predicted.
What broke is that doubling finally needed two columns instead of one, and it carried. Now, four cases fitting was not nothing. It was worth noticing. But it was not evidence that the fifth would fit, and here that is not a technicality. It is simply false. So if examples cannot settle a question about every number, what can? Here is a claim worth settling properly. Take any two two-digit numbers. Any two at all.
Multiply them together. The answer will have either three digits or four digits. Never two. Never five. Now that is a claim about every single pair of two-digit numbers. And your instinct, quite reasonably, is to start trying some. Twelve times thirteen is one hundred and fifty six. Three digits. Eighty seven times ninety four is eight thousand one hundred and seventy eight. Four digits. So far so good. But how long would trying them all take?
There are ninety two-digit numbers. Ten up to ninety nine. So the first number has ninety choices, and so does the second. Ninety times ninety. Eight thousand one hundred pairs. Eight thousand one hundred multiplications to be certain. You will not do that. Nobody will ever do that. And here is the thing that makes this whole topic worth teaching. You do not have to. Two multiplications will settle all eight thousand one hundred of them.
Not sample them. Settle them. Here is the first one. What is the smallest a two-digit number can be? Ten. So the smallest this product could possibly be is ten times ten. Which is one hundred. One hundred has three digits. So no product in the whole collection can be shorter than three digits. That is the floor, and it is now settled for all eight thousand one hundred. Now the ceiling, and this is the clever half.
What is the smallest three-digit number? One hundred. So one hundred times one hundred is ten thousand. And every two-digit number is smaller than one hundred. So every one of our products must be smaller than ten thousand — which means at most four digits. Floor and ceiling. Done. I want to slow down on that second step, because it looks wrong. One hundred is not a two-digit number. It is not one of the cases at all.
So why are we multiplying it? Because a ceiling does not have to be reachable. It only has to be above everything. The largest product we could actually make is ninety nine times ninety nine, which is nine thousand eight hundred and one. That is comfortably under ten thousand, which is exactly what we needed. We could have used ninety nine times ninety nine as the ceiling instead. It is tighter, and it is harder.
One hundred times one hundred you can do in your head, and it is safely above every real case. Choosing a bound that is easy rather than tight is a real skill, and it is most of what makes this argument short. Now the same two multiplications work at any size, so let's ask harder questions. Can a three-digit number times a three-digit number ever give a four-digit answer? Floor first. The smallest three-digit number is one hundred, so the smallest such product is one hundred times one hundred.
Ten thousand. That already has five digits. So no. Not sometimes, not rarely. Never — and we did not test a single case. Try another. Can a four-digit number times a two-digit number give a five-digit answer? Floor: one thousand times ten is ten thousand. Five digits, so yes, it can. Ceiling: nine thousand nine hundred and ninety nine times ninety nine is nine lakh eighty nine thousand nine hundred and one. Six digits.
So that one gives five digits or six. Two answers, both possible, and nothing in between. By now you may have spotted what is going on. Two digits and two digits gave three or four. Three and three gave five or six. Four and two gave five or six as well. In every case, the answer is the two digit counts added together, or one less. And you can see exactly why, from the floor and the ceiling.
The floor multiplies a one followed by some zeros by a one followed by some zeros, and the zeros just add up. The ceiling is a shade under a one followed by all of them. So the product is squeezed between those, and only two lengths fit in the gap. Both really happen, too. Ten times ten gives the short one; ninety nine times ninety nine gives the long one.
So let's use it on cases nobody would attempt by hand. A five-digit number times a five-digit number. Five and five is ten, so the answer has nine digits or ten. An eight-digit number times a three-digit number. Eight and three is eleven. Ten digits or eleven. And one that is frankly absurd. A twelve-digit number times a thirteen-digit one. Twelve and thirteen is twenty five. So the answer has twenty four digits or twenty five.
You have just described the length of a number nobody in this room has ever written down. And you did it with addition. One last thing, and it is the honest part. This rule tells you how long the answer is. It tells you nothing else. It will not tell you the answer. It will not even narrow it much. Of those eight thousand one hundred pairs, there are only just over two and a half thousand different answers.
So knowing a product has four digits leaves thousands of possibilities standing. That is not a weakness. It is what the question asked for. And notice one more thing. Multiplying does not always make a number longer. Two times three is six. One digit times one digit, still one digit. Here is one to try. Pick any two sizes you like, predict the length before you multiply, and then check whether you landed on the short answer or the long one.
Where this fits
Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.
Builds on
- Factorise and regroup instead of multiplying head-onClass 7 · Ch 1, Large Numbers Around Us
- The Land of Tens: each place is ten of the one beforeClass 7 · Ch 1, Large Numbers Around Us
Comes up again in
- Cryptarithms: recovering digits from constraints aloneClass 7 · Ch 6, Number Play
Either side of this one
- Answering "could this possibly fit?" by estimating in stagesClass 7 · Ch 1, Large Numbers Around Us