Exercise 13.1 answers: Statistics

Class 10 Maths9 questions

Exercise 13.1

9 questions · page 181 of the book

Question 1

“collected the following data regarding the number of plants in 20 houses in a locality” · p. 181

Open NCERT p. 181Matches NCERT’s answer

  1. Number of plantsHouses (f)Class mark (x)f × x
    0 − 2111
    2 − 4236
    4 − 6155
    6 − 85735
    8 − 106954
    10 − 1221122
    12 − 1431339
  2. Each class mark is the middle of its two limits, so the marks are 1, 3, 5, 7, 9, 11, 13.
  3. Multiply every mark by its own frequency and add the column: 1+6+5+35+54+22+39 = 162.
  4. The frequencies add to 20, which matches the 20 houses in the survey.
  5. Mean = 162 ÷ 20 = 8.1 plants per house.
  6. All the class marks and frequencies here are small, so the direct method — multiply, total, divide — needed no large numbers. That is why it was chosen.

AnswerMean number of plants per house = 8.1. The direct method was used, because the class marks and frequencies are all small enough to multiply in one line.

Watch this explained “Four sizes of one shape”, 9:26 into The direct method, and where it becomes unwieldy

Question 2

“Consider the following distribution of daily wages of 50 workers of a factory” · p. 181

Open NCERT p. 181Matches NCERT’s answer

  1. Daily wages (₹)Workers (f)Class mark (x)f × x
    500 − 520125106120
    520 − 540145307420
    540 − 56085504400
    560 − 58065703420
    580 − 600105905900
  2. The class marks are 510, 530, 550, 570, 590 — the middle of each ₹20 band.
  3. Multiply each mark by its frequency: 6120, 7420, 4400, 3420, 5900. Total = 27260.
  4. The frequencies add to 50, matching the 50 workers.
  5. Mean = 27260 ÷ 50 = ₹545.20.

AnswerMean daily wages = ₹545.20.

Watch this explained “Four sizes of one shape”, 9:26 into The direct method, and where it becomes unwieldy

Question 3

“The mean pocket allowance is Rs 18. Find the missing frequency f” · p. 181

Open NCERT p. 181Matches NCERT’s answer

  1. Pocket allowance (₹)Children (f)Class mark (x)f × x
    11 − 1371284
    13 − 1561484
    15 − 17916144
    17 − 191318234
    19 − 21f2020f
    21 − 23522110
    23 − 2542496
  2. Add the known frequencies: 7+6+9+13+5+4 = 44, so the total is 44 + f children.
  3. Add the known f×x values: 84+84+144+234+110+96 = 752, so the f×x total is 752 + 20f.
  4. The mean is given as 18, so (752 + 20f) ÷ (44 + f) = 18.
  5. Multiply out: 752 + 20f = 792 + 18f, so 2f = 40.
  6. f = 20.

AnswerThe missing frequency is f = 20.

Watch this explained “The same equation, read backwards”, 13:35 into The direct method, and where it becomes unwieldy

Question 4

“the number of heartbeats per minute were recorded and summarised as follows” · p. 182

Open NCERT p. 182Matches NCERT’s answer

  1. Heartbeats/minWomen (f)Class mark (x)f × x
    65 − 68266.5133
    68 − 71469.5278
    71 − 74372.5217.5
    74 − 77875.5604
    77 − 80778.5549.5
    80 − 83481.5326
    83 − 86284.5169
  2. Each class is 3 units wide, so the class marks are 66.5, 69.5, 72.5, 75.5, 78.5, 81.5, 84.5.
  3. Multiply each mark by its frequency and total the column: 133+278+217.5+604+549.5+326+169 = 2277.
  4. The frequencies total 30, matching the 30 women.
  5. Mean = 2277 ÷ 30 = 75.9 heartbeats per minute.
  6. The numbers stay small here, so the direct method is a suitable choice for this table.

AnswerMean heartbeats per minute = 75.9.

Watch this explained “The shape of the work: four actions, one of them heavy”, 1:41 into The direct method, and where it becomes unwieldy

Question 5

“These boxes contained varying number of mangoes. The following was the distribution of mangoes” · p. 182

Open NCERT p. 182Matches NCERT’s answer

  1. Number of mangoesBoxes (f)
    50 − 5215
    53 − 55110
    56 − 58135
    59 − 61115
    62 − 6425
  2. The printed classes have a gap of 1 between them (52 to 53, and so on), so they are not continuous yet.
  3. Close the gaps by moving every limit by half a unit: 49.5 − 52.5, 52.5 − 55.5, 55.5 − 58.5, 58.5 − 61.5, 61.5 − 64.5.
  4. This does not move any class mark, since each mark is the average of its two limits and both limits moved by the same half-unit: the marks are 51, 54, 57, 60, 63.
  5. Class mark (x)Boxes (f)f × x
    5115765
    541105940
    571357695
    601156900
    63251575
  6. Total of f×x = 765+5940+7695+6900+1575 = 22875. Total boxes = 400.
  7. Mean = 22875 ÷ 400 = 57.1875 mangoes per box.
  8. The direct method was used, once the classes were made continuous.

AnswerMean number of mangoes per box = 57.1875, found by the direct method after closing the gaps between the classes.

Watch this explained “Continuity leaves the mean alone”, 12:08 into The direct method, and where it becomes unwieldy

Question 6

“The table below shows the daily expenditure on food of 25 households in a locality” · p. 182

Open NCERT p. 182Matches NCERT’s answer

  1. Expenditure (₹)Households (f)Class mark (x)f × x
    100 − 1504125500
    150 − 2005175875
    200 − 250122252700
    250 − 3002275550
    300 − 3502325650
  2. The class marks (125, 175, 225, 275, 325) are 50 units apart, so a step-deviation approach also works, but the direct total is easy here: 500+875+2700+550+650 = 5275.
  3. The frequencies total 25, matching the 25 households.
  4. Mean = 5275 ÷ 25 = ₹211.

AnswerMean daily expenditure on food = ₹211.

Watch this explained “The shape of the work: four actions, one of them heavy”, 1:41 into The direct method, and where it becomes unwieldy

Question 7

“To find out the concentration of SO2 in the air (in parts per million, i.e., ppm)” · p. 182

Open NCERT p. 182Matches NCERT’s answer

  1. SO2 (ppm)Localities (f)Class mark (x)f × x
    0.00 − 0.0440.020.08
    0.04 − 0.0890.060.54
    0.08 − 0.1290.100.90
    0.12 − 0.1620.140.28
    0.16 − 0.2040.180.72
    0.20 − 0.2420.220.44
  2. Keep every class mark as an exact decimal — do not round any of them before multiplying.
  3. Total of f×x = 0.08+0.54+0.90+0.28+0.72+0.44 = 2.96.
  4. The frequencies total 30, matching the 30 localities.
  5. Mean = 2.96 ÷ 30 = 0.0987 ppm (to 4 decimal places).

AnswerMean concentration of SO2 = 0.0987 ppm (37/375 exactly).

Watch this explained “Rounding once, at the end”, 11:01 into The direct method, and where it becomes unwieldy

Question 8

“A class teacher has the following absentee record of 40 students of a class for the whole term” · p. 183

Open NCERT p. 183Matches NCERT’s answer

  1. Days absentStudents (f)Class mark (x)f × x
    0 − 611333
    6 − 1010880
    10 − 1471284
    14 − 2041768
    20 − 2842496
    28 − 3833399
    38 − 4013939
  2. The classes here are of different widths (6, 4, 4, 6, 8, 10, 2), so there is no common step size to shrink the arithmetic — the direct method is the only practical choice.
  3. Total of f×x = 33+80+84+68+96+99+39 = 499.
  4. The frequencies total 40, matching the 40 students.
  5. Mean = 499 ÷ 40 = 12.475 days.

AnswerMean number of days a student was absent = 12.475.

Watch this explained “What h must satisfy, and when to give the method up”, 10:47 into Dividing through by the class width to shrink the arithmetic further

Question 9

“The following table gives the literacy rate (in percentage) of 35 cities” · p. 183

Open NCERT p. 183Matches NCERT’s answer

  1. Literacy rate (%)Cities (f)Class mark (x)f × x
    45 − 55350150
    55 − 651060600
    65 − 751170770
    75 − 85880640
    85 − 95390270
  2. Total of f×x = 150+600+770+640+270 = 2430.
  3. The frequencies total 35, matching the 35 cities.
  4. Mean = 2430 ÷ 35 = 69.43% (to 2 decimal places).

AnswerMean literacy rate ≈ 69.43% (486/7 exactly).

Watch this explained “Thirty-five territories, run directly”, 2:28 into The direct method, and where it becomes unwieldy

Every question here was solved twice, separately, by two different AI models, and each answer was put back into the question by a computer program to check it. Where the two disagreed, a stronger model solved it again and the computer check had to pass on its answer. A question about reasoning rather than a number is shown as “one way to think about it”, and anything not yet proven says so instead of guessing. Each answer links to the moment in the video that teaches it.

We quote only enough of each question to find it: keep your NCERT book open, or open this chapter in NCERT’s PDF. Spotted a mistake? Tell us.