Exercise 13.1 answers: Statistics
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Exercise 13.1
9 questions · page 181 of the book
Question 1
“collected the following data regarding the number of plants in 20 houses in a locality” · p. 181
Open NCERT p. 181Matches NCERT’s answer
Number of plants Houses (f) Class mark (x) f × x 0 − 2 1 1 1 2 − 4 2 3 6 4 − 6 1 5 5 6 − 8 5 7 35 8 − 10 6 9 54 10 − 12 2 11 22 12 − 14 3 13 39 - Each class mark is the middle of its two limits, so the marks are 1, 3, 5, 7, 9, 11, 13.
- Multiply every mark by its own frequency and add the column: 1+6+5+35+54+22+39 = 162.
- The frequencies add to 20, which matches the 20 houses in the survey.
- Mean = 162 ÷ 20 = 8.1 plants per house.
- All the class marks and frequencies here are small, so the direct method — multiply, total, divide — needed no large numbers. That is why it was chosen.
AnswerMean number of plants per house = 8.1. The direct method was used, because the class marks and frequencies are all small enough to multiply in one line.
Watch this explained “Four sizes of one shape”, 9:26 into The direct method, and where it becomes unwieldy
Question 2
“Consider the following distribution of daily wages of 50 workers of a factory” · p. 181
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Daily wages (₹) Workers (f) Class mark (x) f × x 500 − 520 12 510 6120 520 − 540 14 530 7420 540 − 560 8 550 4400 560 − 580 6 570 3420 580 − 600 10 590 5900 - The class marks are 510, 530, 550, 570, 590 — the middle of each ₹20 band.
- Multiply each mark by its frequency: 6120, 7420, 4400, 3420, 5900. Total = 27260.
- The frequencies add to 50, matching the 50 workers.
- Mean = 27260 ÷ 50 = ₹545.20.
AnswerMean daily wages = ₹545.20.
Watch this explained “Four sizes of one shape”, 9:26 into The direct method, and where it becomes unwieldy
Question 3
“The mean pocket allowance is Rs 18. Find the missing frequency f” · p. 181
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Pocket allowance (₹) Children (f) Class mark (x) f × x 11 − 13 7 12 84 13 − 15 6 14 84 15 − 17 9 16 144 17 − 19 13 18 234 19 − 21 f 20 20f 21 − 23 5 22 110 23 − 25 4 24 96 - Add the known frequencies: 7+6+9+13+5+4 = 44, so the total is 44 + f children.
- Add the known f×x values: 84+84+144+234+110+96 = 752, so the f×x total is 752 + 20f.
- The mean is given as 18, so (752 + 20f) ÷ (44 + f) = 18.
- Multiply out: 752 + 20f = 792 + 18f, so 2f = 40.
- f = 20.
AnswerThe missing frequency is f = 20.
Watch this explained “The same equation, read backwards”, 13:35 into The direct method, and where it becomes unwieldy
Question 4
“the number of heartbeats per minute were recorded and summarised as follows” · p. 182
Open NCERT p. 182Matches NCERT’s answer
Heartbeats/min Women (f) Class mark (x) f × x 65 − 68 2 66.5 133 68 − 71 4 69.5 278 71 − 74 3 72.5 217.5 74 − 77 8 75.5 604 77 − 80 7 78.5 549.5 80 − 83 4 81.5 326 83 − 86 2 84.5 169 - Each class is 3 units wide, so the class marks are 66.5, 69.5, 72.5, 75.5, 78.5, 81.5, 84.5.
- Multiply each mark by its frequency and total the column: 133+278+217.5+604+549.5+326+169 = 2277.
- The frequencies total 30, matching the 30 women.
- Mean = 2277 ÷ 30 = 75.9 heartbeats per minute.
- The numbers stay small here, so the direct method is a suitable choice for this table.
AnswerMean heartbeats per minute = 75.9.
Watch this explained “The shape of the work: four actions, one of them heavy”, 1:41 into The direct method, and where it becomes unwieldy
Question 5
“These boxes contained varying number of mangoes. The following was the distribution of mangoes” · p. 182
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Number of mangoes Boxes (f) 50 − 52 15 53 − 55 110 56 − 58 135 59 − 61 115 62 − 64 25 - The printed classes have a gap of 1 between them (52 to 53, and so on), so they are not continuous yet.
- Close the gaps by moving every limit by half a unit: 49.5 − 52.5, 52.5 − 55.5, 55.5 − 58.5, 58.5 − 61.5, 61.5 − 64.5.
- This does not move any class mark, since each mark is the average of its two limits and both limits moved by the same half-unit: the marks are 51, 54, 57, 60, 63.
Class mark (x) Boxes (f) f × x 51 15 765 54 110 5940 57 135 7695 60 115 6900 63 25 1575 - Total of f×x = 765+5940+7695+6900+1575 = 22875. Total boxes = 400.
- Mean = 22875 ÷ 400 = 57.1875 mangoes per box.
- The direct method was used, once the classes were made continuous.
AnswerMean number of mangoes per box = 57.1875, found by the direct method after closing the gaps between the classes.
Watch this explained “Continuity leaves the mean alone”, 12:08 into The direct method, and where it becomes unwieldy
Question 6
“The table below shows the daily expenditure on food of 25 households in a locality” · p. 182
Open NCERT p. 182Matches NCERT’s answer
Expenditure (₹) Households (f) Class mark (x) f × x 100 − 150 4 125 500 150 − 200 5 175 875 200 − 250 12 225 2700 250 − 300 2 275 550 300 − 350 2 325 650 - The class marks (125, 175, 225, 275, 325) are 50 units apart, so a step-deviation approach also works, but the direct total is easy here: 500+875+2700+550+650 = 5275.
- The frequencies total 25, matching the 25 households.
- Mean = 5275 ÷ 25 = ₹211.
AnswerMean daily expenditure on food = ₹211.
Watch this explained “The shape of the work: four actions, one of them heavy”, 1:41 into The direct method, and where it becomes unwieldy
Question 7
“To find out the concentration of SO2 in the air (in parts per million, i.e., ppm)” · p. 182
Open NCERT p. 182Matches NCERT’s answer
SO2 (ppm) Localities (f) Class mark (x) f × x 0.00 − 0.04 4 0.02 0.08 0.04 − 0.08 9 0.06 0.54 0.08 − 0.12 9 0.10 0.90 0.12 − 0.16 2 0.14 0.28 0.16 − 0.20 4 0.18 0.72 0.20 − 0.24 2 0.22 0.44 - Keep every class mark as an exact decimal — do not round any of them before multiplying.
- Total of f×x = 0.08+0.54+0.90+0.28+0.72+0.44 = 2.96.
- The frequencies total 30, matching the 30 localities.
- Mean = 2.96 ÷ 30 = 0.0987 ppm (to 4 decimal places).
AnswerMean concentration of SO2 = 0.0987 ppm (37/375 exactly).
Watch this explained “Rounding once, at the end”, 11:01 into The direct method, and where it becomes unwieldy
Question 8
“A class teacher has the following absentee record of 40 students of a class for the whole term” · p. 183
Open NCERT p. 183Matches NCERT’s answer
Days absent Students (f) Class mark (x) f × x 0 − 6 11 3 33 6 − 10 10 8 80 10 − 14 7 12 84 14 − 20 4 17 68 20 − 28 4 24 96 28 − 38 3 33 99 38 − 40 1 39 39 - The classes here are of different widths (6, 4, 4, 6, 8, 10, 2), so there is no common step size to shrink the arithmetic — the direct method is the only practical choice.
- Total of f×x = 33+80+84+68+96+99+39 = 499.
- The frequencies total 40, matching the 40 students.
- Mean = 499 ÷ 40 = 12.475 days.
AnswerMean number of days a student was absent = 12.475.
Watch this explained “What h must satisfy, and when to give the method up”, 10:47 into Dividing through by the class width to shrink the arithmetic further
Question 9
“The following table gives the literacy rate (in percentage) of 35 cities” · p. 183
Open NCERT p. 183Matches NCERT’s answer
Literacy rate (%) Cities (f) Class mark (x) f × x 45 − 55 3 50 150 55 − 65 10 60 600 65 − 75 11 70 770 75 − 85 8 80 640 85 − 95 3 90 270 - Total of f×x = 150+600+770+640+270 = 2430.
- The frequencies total 35, matching the 35 cities.
- Mean = 2430 ÷ 35 = 69.43% (to 2 decimal places).
AnswerMean literacy rate ≈ 69.43% (486/7 exactly).
Watch this explained “Thirty-five territories, run directly”, 2:28 into The direct method, and where it becomes unwieldy
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