PrepShorts · Study sheet · Class 10 Mathematics · Chapter 14, Probability
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Across 510 events from every experiment up to eight outcomes, favourable over unfavourable gives the right answer 8 times, and two ways so a half gives it 98 times — under one in five.
The idea
The definition converts a question about chance into a question about counting, and that conversion is legitimate only because equal likelihood has made the outcomes interchangeable: each of the n possibilities carries weight 1/n, so an event assembled from k of them carries k/n. The book prints the ratio and moves on. The reason the ratio deserves to be called a probability is that the equal weights add — and once that is said out loud, the single most common error in the whole chapter, counting events instead of counting outcomes, has nowhere left to hide.
What you should be able to do
- State the definition in terms of what each of its two counts counts, and say which clause of it carries the assumption
- Justify the definition by assigning weight 1/n to each of n interchangeable outcomes and adding
- Compute the probability of a single-outcome event, as in the coin and the three balls
- Compute the probability of an event covering several outcomes, as in a die result above 4
- Translate an event described in words into an explicit list of the outcomes that favour it, before dividing anything
- Explain why the denominator never changes between parts of the same question while the numerator does
- Say what the definition does not require — no trials, no history, no repetition
- Place the definition historically, naming Laplace and the year the chapter attaches to it
Words to know
| Term | Definition in one line | First introduced |
|---|---|---|
| theoretical probability | the ratio of the favourable possibilities to all of them, computed under the equal-likelihood assumption | printed on p. 203, restated in the Summary on p. 217 |
| classical probability | the chapter's alternative name for the same quantity | printed on p. 203 |
| favourable | said of an outcome that would make the event happen | printed on p. 203 inside the definition |
| event | the thing whose probability is being asked for, made up of one or more outcomes | printed on p. 203 |
| outcome | one of the individual results the experiment can end in | printed on p. 202 |
| P(E) | the chapter's notation for the probability of the event E | printed on p. 203 |
| equally likely | the assumption the definition names in its own final clause | printed on p. 202 |
| weight of an outcome | the share 1/n that each of n interchangeable outcomes carries | an added term; the chapter never decomposes the ratio this way |
| additivity | the fact that an event's probability is the total of the weights of its outcomes | an added vocabulary, not printed in this chapter |
Where people slip up
- "Probability is favourable over unfavourable." It is favourable over everything. In Example 3 the wrong reading would give 2/4 for a result above 4 instead of 2/6. Students who have met odds elsewhere import this constantly.
- "Two possible answers, so one-half." Example 3 is the chapter's own refutation: the event and its denial are each one description, and they come out 1/3 and 2/3. Counting descriptions is not counting outcomes.
- "The denominator is whichever number the question mentions." It is the size of the outcome list, fixed once for the whole experiment. Both parts of Example 3 divide by 6.
- "Balls of the same size is just scene-setting." It is the clause that makes the three outcomes interchangeable. Delete it and the computation is not justified.
- "You have to run the experiment to know the answer." Nothing in Example 1 was tossed. That is the point of the previous topic and this is where it pays.
- "Probability is a fraction, so it cannot be a decimal or a percentage." The chapter later prints 0.88 and 0.96 for the same kind of quantity. The ratio is a number; how it is written is a separate matter.
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Worked answers: Exercise 14.1
Transcript1,750 words
Two ideas are already on the table, and this is where they pay off. The first: sometimes the outcomes of an experiment are interchangeable, so that nothing about the set-up prefers one to another. The second: a definition that needs no trials is worth having, because most questions worth asking cannot be rehearsed. Put those together and you get a rule you can compute with, and it is the rule the whole subject runs on.
It is short enough to memorise in ten seconds, which is exactly the problem. Memorised without its reason, it produces wrong answers that look right. So this is the rule, and then the reason, and then the one distinction that decides almost every mistake anybody makes with it. Here it is. The probability of an event is the number of outcomes that would make it happen, divided by the number of outcomes there are altogether.
Favourable over total. Two counts, and both of them count the same kind of thing: outcomes. Not descriptions. Not answers. Not the numbers the question happens to mention. Outcomes. And there is a clause attached to it that is part of the rule and not a footnote to it. All of this holds provided the outcomes are equally likely. Keep that clause on the board, because everything else in this video is either the reason for it or the price of forgetting it.
Now the reason, because a ratio handed over with no reason is exactly the kind of thing that gets misapplied. Suppose an experiment has six outcomes and nothing separates them. Then each one has to carry the same share of the certainty, and the shares have to fill the experiment exactly, because the experiment always ends somewhere. Six equal shares filling one whole. So each is a sixth. Draw it as a strip cut into six equal cells, each labelled one sixth.
Now an event is not a new thing. It is just some of those cells. Shade the cells it covers and add them up. Two cells shaded, each a sixth, so a sixth plus a sixth: two sixths. And that is what favourable over total is. It is not a definition of chance handed down from nowhere. It is what you get when equal weights are added. Which is why the equal-likelihood clause is doing the work: without it the cells are different sizes, and adding two of them tells you nothing about how many there were.
Watch what the clause is holding up. Grey out the clause, keep the ratio, and the ratio still computes. It gives you a number every time. That is the danger. A bag with four red balls and one blue one has two colours, and one over two is not the chance of red. The chance of red is four fifths, because the balls are the interchangeable things and the colours are not.
So the rule never applies to an experiment. It applies to a list of outcomes you have chosen, and it is legitimate only when nothing separates the things on that list. Which means the first question is never what is the probability. The first question is: what is my list, and is anything on it different from anything else on it? Here is the distinction that decides almost every wrong answer in this subject.
Outcomes are what the experiment can actually end in. Descriptions are the words you put around them. One description can cover several outcomes. Several descriptions can cover one. The rule counts outcomes. It has nothing at all to say about how many descriptions you wrote down. The most common error is the same sentence every time: there are two ways this can go, so it is a half. Two ways this can go is a statement about descriptions.
A second error rides in beside it: favourable over unfavourable. Anybody who has met odds imports this without noticing, and it is a different quantity with a different denominator. Favourable over everything. Both counts, over the same list. So, the simplest case, done slowly. One coin, tossed once. List the outcomes: head, tail. Two of them, and the two faces of a fair coin are interchangeable. The event is: it comes up heads.
How many outcomes make that happen? One of the two. So the probability of a head is one half. Now the tail. And here is the thing worth noticing. You do not get one half for the tail by subtracting the head's answer from one. You get it by counting again. One outcome out of two makes a tail. One half. The two happen to add to one, and that is a fact you can check rather than a rule you applied.
Nothing was tossed. No coin moved. The whole thing was settled by listing and counting. Now three, so the pattern shows. A bag holds one red ball, one blue ball and one yellow ball, all the same size, and you draw one without looking. That phrase, all the same size, is not scene setting. It is the guarantee that your hand cannot prefer one of them. Delete it and the computation is not justified.
Three outcomes. Red, blue, yellow. The chance of yellow: one outcome out of three, so a third. The chance of red: one out of three, a third. The chance of blue: one out of three, a third. Three separate questions, three separate numerators, and one denominator that never moved. And the three thirds fill the experiment exactly, which is the weight strip again, seen from the other side. Now an event made of more than one outcome, which is where the counting starts to earn its keep.
A die is thrown once. Six outcomes: one, two, three, four, five, six. The event is: the result is greater than four. Do not divide yet. Turn the description into a list. Which of the six results are greater than four? Five, and six. That is the whole step, and it is the step people skip. Two outcomes favour it, out of six, so two sixths, which is a third.
Now compare that with what the two wrong readings would have said. Two ways this can go, above four or not above four, so a half. Wrong. Two favourable against four unfavourable, so two over four, a half again. Also wrong, and wrong by the same amount. The true answer is a third and both wrong readings say a half. They are out by a sixth, on a quantity that is only a third to begin with.
Now ask the same die for the rest. The event is: the result is four or less. Turn it into a list first. One, two, three and four. Four outcomes favour it. And out of how many? Six. The same six as before. Four sixths, which is two thirds. Put the two answers side by side and look at what moved. The numerator went from two to four. The denominator did not move at all.
It could not have. The denominator is the size of the outcome list, and the outcome list belongs to the experiment, not to the question. One die, one list of six, and as many questions as you like sitting on top of it. And a third plus two thirds is one, which is the strip filled: every cell is in one of the two events and none is in both.
So the whole method is four steps, and only one of them is arithmetic. Write down every outcome the experiment can end in. Check that nothing separates them, and if something does, go to a finer list until nothing does. Cross off the outcomes the description does not cover, and count what is left. Then divide, by the length of the whole list. The reason to insist on the list is that a description can hide its own size.
Greater than four sounds like one thing and is two. Four or less sounds like one thing and is four. Written as words they look like a matched pair. Written as lists they are two against four, and the answer is obvious before any dividing happens. It is worth knowing how often the wrong readings happen to be right, because that is why they survive. Take every experiment with up to eight outcomes and every event you can build inside one. There are five hundred and ten of them.
Favourable over unfavourable gets the right answer eight times. Once per experiment, and always in the same silly case: when no outcome at all is favourable and both readings are nought. Everywhere else it is wrong. That reading is not a shortcut, it is a different quantity. Two ways this can go, so a half, does better: it is right ninety-eight times out of five hundred and ten. Under one in five. Often enough to feel like a rule, rarely enough to be one.
And the thing the whole rule rests on holds everywhere it should. Take any two events with no outcome in common: the chance of one or the other is the chance of one plus the chance of the other, on all one thousand and ninety-two such pairs. Take two that do share an outcome and it fails on every single one of the four thousand three hundred and sixty-eight of them, because the shared cell got added twice.
That is the strip talking. Weights add when the cells are separate and not when they are shared. One last thing, because this rule has a history and it is a short one. The subject starts in the sixteenth century with Cardan, an Italian doctor who wrote the first treatise on the mathematics of gambling games. Then James Bernoulli, sixteen fifty-four to seventeen oh five. Fifty-one years. Abraham de Moivre, sixteen sixty-seven to seventeen fifty-four. Eighty-seven years.
And Pierre Simon Laplace, seventeen forty-nine to eighteen twenty-seven, who wrote the definition you have just been using in seventeen ninety-five, and his great work on the subject seventeen years later. More than two centuries on, it is used in biology, economics, genetics, physics and sociology. And it is still the same two counts, over the same list, with the same clause attached. Favourable over everything, once you have earned the right to say the outcomes are interchangeable.
The counting is the easy half. The list is the hard half, and it is the half that decides the answer.
Where this fits
Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.
Builds on
- Equally likely outcomes, and the everyday cases where that failsClass 10 · Ch 14, Probability
- Why repeating an experiment is often impossible, and what replaces itClass 10 · Ch 14, Probability
Comes up again in
- Single-outcome events, and why all of them together come to 1Class 10 · Ch 14, Probability
- The impossible and the certain pin the scale at 0 and at 1Class 10 · Ch 14, Probability
- Complements: knowing one probability hands you the otherClass 10 · Ch 14, Probability
- Coins, dice, bags and a deck of 52: getting the denominator rightClass 10 · Ch 14, Probability
- When outcomes cannot be counted, measuring length or area insteadClass 10 · Ch 14, Probability