PrepShorts · Study sheet · Class 7 Mathematics · Chapter 3, Finding Common GroundPrepShorts

Chapter 3 · Finding Common Ground

Reading every factor of a number off its prime factorisation

यह वीडियो हिंदी में भी · Watch in Hindi

Prime factorisation10 min

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10 min.

Also recorded in Hindi.Englishहिन्दी

Is 28 a factor of 840? You could divide and see. That works, and it teaches you nothing.

The idea

A factor of a number cannot be anything other than a piece cut out of that number's prime factorisation — the chapter's word for such a piece is a subpart. Once you believe that, finding all the factors stops being a search you might botch and becomes an enumeration you can finish and defend. And the enumeration reveals something the size of a number never tells you: how many factors it has is decided by the shape of its factorisation, not by how big it is. That is why 121, which is larger than 96, has fewer factors and a shorter factorisation, and why the chapter can print a claim about size and then knock it down with one example.

What you should be able to do

  • Decide whether a stated product of primes divides a stated number, by looking at its factorisation instead of by dividing
  • Say what the other half of the pair must be when a subpart is pulled out
  • Explain why a subpart of the factorisation must be a factor
  • Explain why nothing outside the factorisation can be a factor — and identify where the previous topic's result is doing that work
  • List every factor of a number by taking its prime factors none at a time, one at a time, two at a time, and so on
  • Say why 1 has to be put into that list separately
  • Assess a claim of the pattern-spotting kind by looking for a single example that breaks it
  • State, with an example, why a larger number need not have a longer factorisation or more factors

Words to know

TermDefinition in one lineFirst introduced
subpartthe chapter's word for a piece cut out of a factorisation and multiplied togetherprinted, in single quotes, in §3.1, Part II, p.51, and used throughout the rest of the chapter
factora number that divides the given number exactlyClass 6; used from p.47 of Part II and defined by use here
prime factorisationthe number rewritten as primes multiplied togetherprinted as a bold subheading in §3.1, Part II, p.49
reorderto rearrange the primes in a product, which leaves the product aloneprinted in §3.1, Part II, p.50
combinationthe chapter's word for a selection of some of the prime factorsprinted three times in the 225 enumeration, §3.1, Part II, p.51
conjecturea claim put forward without proof or checkingprinted in a side box in §3.1, Part II, p.52; unpacked in Conjecture and generalisation: what mathematicians mean by those words
counterexampleone instance that shows a claim falseprinted in the same side box, §3.1, Part II, p.52
divisor-counting ruleadd one to each prime's repeat-count and multiplyan added name for a shortcut this chapter never prints — it enumerates instead (all twenty pages, pp.47–66, read)
proper factora factor other than the number itselfan added term, not printed in this chapter; use it only if the explanation needs the distinction

Where people slip up

  • "Every subpart of the factorisation is a factor — so 3 × 3 × 3 is a factor of 840." It is not a subpart. 840's factorisation holds a single 3, so you cannot cut three of them out of it. The word subpart is doing precise work: you may take a prime only as many times as it is actually there. Make the running-out visible.
  • "You could still find a factor that is not made of the number's own primes." You could not, and this is exactly where the previous topic pays off: if the factorisation were not forced, a factor built from other primes would be conceivable.
  • "With four primes there are four ways to choose two of them." 225 = 3 × 3 × 5 × 5 has four prime factors and only three distinct products from a pair, because 3 × 3, 3 × 5 and 5 × 5 exhaust the possibilities and the two 3s are interchangeable. Repeats collapse. Any enumeration that treats the copies as different produces duplicates and an inflated count.
  • "1 is not really a factor." It is, it belongs in the list, and it is the one entry that is not a positive-length subpart — it is what you get by taking no primes at all. The book adds it explicitly for that reason.
  • "A larger number must have more factors." 121 against 96 kills this in one line. So does the observation that primes of any size have exactly two.
  • "A claim that works for the examples I tried is true." It is a conjecture until it is argued for every case. The book prints Anshu's claim precisely because it is plausible and false.
Transcript1,409 words

Is twenty-eight a factor of eight hundred and forty? You could divide and see. That works, and it teaches you nothing. It answers this one question and leaves you no better placed for the next one. So here is a better way, and it turns out to answer a far larger question at the same time. Take the prime factorisation of eight hundred and forty. Two, two, two, three, five, seven. Six primes.

That is the whole of eight hundred and forty. There is nothing else in it. And the claim we are going to earn is this: every factor it has is a piece cut out of that row. Start with the one question we were asked. Twenty-eight is two times two times seven. So look along the row and see whether those are in it. A two, yes. Another two, yes, there are three of them. A seven, yes.

Now slide the ones you took to one side. Two, two and seven on the left. Two, three and five on the right. Nothing was added and nothing thrown away. The primes were only reordered, and reordering never changes a product. So eight hundred and forty is twenty-eight times thirty, and twenty-eight is a factor. No division happened anywhere. Look at what arrived alongside the answer. You asked about twenty-eight, and you were handed thirty as well.

That is not a bonus. It is unavoidable. The primes you cut out make one number. The primes left behind make the other. Between them they use every prime in the row exactly once, so multiplying the two gives the whole thing back. Which means factors always arrive in pairs, and pulling one out names the other for nothing. Two, two, seven leaves two, three, five. Twenty-eight leaves thirty. Every question of this kind answers two things at once, and you still never divide.

Now three quick ones, all on the same number. Is two times seven a factor of eight hundred and forty? A two and a seven, both in the row. Yes. And the leftovers say its partner is sixty. Is two times two times two a factor? That wants three twos, and the row holds exactly three. Yes, with a hundred and five left over. Now this one. Is three times three times three a factor?

That wants three threes. Look along the row. There is one. You take it, then you reach for another, and there is nothing there. It runs out. So twenty-seven is not a factor, and again you never divided. Now turn the idea round, because it is worth far more than these one-off questions. We have been checking candidates that were handed to us. Suppose instead we generate them. Cut out every possible piece of the row, multiply each piece together, and collect the results.

Would that list be all the factors? Or only some of them? Half of that is easy, and we have already done it three times. Any piece you cut out is a factor, because the leftovers are sitting there ready to make up the difference. So everything on that list certainly belongs on it. The hard half runs the other way. Could there be a factor that never appears on the list at all?

This is the step worth slowing down for, because it is where the real work happens. Suppose some number divides eight hundred and forty but is built out of a prime the row does not contain. Eleven, say. Then eight hundred and forty is that number times something else. Break both of those into primes, and you have just written eight hundred and forty as a product of primes with an eleven sitting in it.

But a number has only one prime factorisation. And eight hundred and forty's has no eleven, so the number we supposed cannot exist. Nothing from outside can get in. The row is the entire supply. Which is why it mattered so much that the factorisation is forced. This whole method is standing on it. So let us do it properly, and list every factor a number has. Two hundred and twenty-five. Divide by five, and by five again. Then by three, and by three.

Three, three, five, five. Four primes. Now work through the pieces by how many primes they use. One at a time: three, and five. Two at a time: three and three make nine, three and five make fifteen, five and five make twenty-five. Three at a time: three, three and five make forty-five. Three, five and five make seventy-five. And all four at once, which is two hundred and twenty-five itself.

That is eight factors. Three, five, nine, fifteen, twenty-five, forty-five, seventy-five and two hundred and twenty-five. One is missing, and the one that is missing is one. One divides everything, so it is certainly a factor. But it is not built out of any of the primes in the row. So where is it supposed to come from? Go back to how we organised the search. One at a time, two at a time, three, four.

We never did none at a time. Take no primes at all, multiply nothing together, and what you have is one. So it is not an exception being smuggled in at the end. It is the first line of the table, and the finished list has nine. Now a trap, and it is the one that ruins these counts. Two hundred and twenty-five has four prime factors. Three, three, five, five.

How many ways are there of picking two things out of four? Six. But we only found three numbers on that line. Nine, fifteen and twenty-five. The reason is that the two threes are not two different things. They are both just three. Take the first three with the second five and you get fifteen. Take the second three with the first five and you get fifteen again. Six selections, three answers. The repeats collapse.

Any count that treats identical primes as though you could tell them apart comes out too big, and that is much the commonest way to get these wrong. Look at the shape of what we found. None at a time, one. One at a time, two. Two at a time, three. Three at a time, two. Four at a time, one. One, two, three, two, one. It reads the same forwards and backwards.

That is not a coincidence, and you already know the reason. Every piece you cut out leaves a partner behind. Take one prime and you leave three of them. Take two and you leave two. So the line for one and the line for three must be the same length, because their entries are paired off one to one. And the entry in the middle, fifteen, is its own partner. Fifteen times fifteen is two hundred and twenty-five.

Try it on a few of your own. Ninety is two, three, three, five. A hundred and five is three, five, seven. A hundred and thirty-two is two, two, three, eleven. Three hundred and sixty is two, two, two, three, three, five. Enumerate those and you get twelve factors, then eight, then twelve, then twenty-four. And eight hundred and forty, where we started, has thirty-two. Once you have done a few, a shortcut turns up on its own.

Count how many times each prime repeats, add one to every count, and multiply those numbers together. Three hundred and sixty has three twos, two threes and one five. Four times three times two is twenty-four. The added one is the choice of not taking that prime at all. One last thing, and it is about a very tempting idea. Here it is. The bigger the number, the longer its prime factorisation.

It sounds obviously right. Bigger numbers ought to be built out of more. Ninety-six is two, two, two, two, two, three. Six primes. A hundred and twenty-one is eleven times eleven. Two primes. A hundred and twenty-one is the larger number, with the shorter row, and only three factors against ninety-six's twelve. One example is enough to sink a claim of that shape, and it is worth noticing how cheap the sinking was.

The method itself survives untouched, because it never cared how big the number was. It only ever cared what the row said. Which is exactly what you want when you start asking what two numbers have in common.

Where this fits

Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.

Builds on

Comes up again in

The book

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