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Chapter 4 · Expressions using Letter-Numbers

Collecting like terms, and what "simplest form" is for

यह वीडियो हिंदी में भी · Watch in Hindi

Notation and simplest form10 min

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10 min.

Also recorded in Hindi.Englishहिन्दी

Simplifying is not tidying up. Two expressions are equal here only if they agree for every replacement of their letters.

The idea

Simplifying is not tidying up. Two expressions count as equal here when they take the same value for every replacement of their letters, and simplifying is the only way to see that two expressions reached by different routes are the same relation. So the stopping point is not a matter of taste: 5c + 3c + 10c collapses because the distributive property makes it collapse for every value of c, and 18c + 11d stops because no arithmetic fact makes c and d combine for every pair of values — not because it looks short enough.

What you should be able to do

  • Simplify an expression by collecting terms that carry the same letter-number
  • State what makes two expressions equal, and check a claimed equality by substituting values
  • Identify like terms and unlike terms in a given expression
  • Remove a bracket that has a minus sign in front of it, inside an algebraic expression
  • Expand a bracket that has a number in front of it, and collect the like terms that result
  • Add and subtract two algebraic expressions
  • Explain why an expression such as 18c + 11d cannot be simplified further
  • Given a simplification, decide whether it is correct and, if not, repair it

Words to know

TermDefinition in one lineFirst introduced
simplified forman expression rewritten with fewer terms but the same value everywhereprinted and set in bold in Part I, §4.4, p.88
simplest formthe form in which brackets are gone, like terms are collected and number-only terms are addedprinted in Part I, §4.4, p.89
like termsterms carrying the same letter-numbers, which may be added into oneprinted and set in bold in Part I, §4.4, p.90
unlike termsterms carrying different letter-numbers, which may notprinted and set in bold in Part I, §4.4, p.90
distributive propertya multiple of a sum equals the sum of the multiplesprinted in Part I, §4.2, p.85; used on letters in §4.4, p.89
term (of an expression)one of the pieces an expression is read as a sum ofprinted in Part I, §4.1, p.83
equal (of two expressions)taking the same value for every replacement of the letter-numbersprinted in Part I, §4.4, p.88
areathe amount of surface a figure coversprinted in Part I, §4.4, p.89
perimeterthe total distance round a closed figureprinted in Part I, §4.4, p.87
breadththe shorter side of a rectangle, paired with its lengthprinted in Part I, §4.4, p.88
collecting like termsthe act of adding like terms into one terman added phrase; the two words like terms are the book's, but this compound is not printed in this chapter

Where people slip up

  • "3a + 2b = 5, because 3 and 2 make 5." Item 1 of the p.94 block. The numbers are not free to be added: they are attached to different letters, and the sum would then have to be 5 of something. Ask which, and the error answers itself.
  • "Simplest means shortest." 3(j + 2k + 3h + 4) is shorter than the expression it came from, and it is still not the simplest form the block asks for, because a bracket survives. The definition, not the length, decides.
  • "Two expressions that look different are different." The chapter's whole method depends on the opposite. Example 11 reaches one expression by three routes on purpose, and the rectangle perimeter does it twice.
  • "Checking at one value proves two expressions equal." It does not. The reason the perimeter forms are equal is that one was obtained from the other by rules that hold for all numbers — the substitution is a confirmation, not the argument. This distinction is exactly what §4.5 will turn into a proof about calendars.
  • "A minus in front of a bracket flips only the first term." Item 5 of the p.94 block is this: 5 – (2 – 6z) claimed as 3 – 6z, where the correct form is 3 + 6z. Example 7 on p.91 is the repair: the minus reaches every term inside.
  • "Subtracting means taking the smaller number from the larger." Item 4 of the same p.94 block is this, and it is a separate error worth its own name. In (4x + 3y) – (3x + 4y) each pair of front numbers has been differenced the comfortable way round — 4 – 3 for the x terms, and 4 – 3 again for the y terms — which is how the claimed x + y arises. The correct form is x – y. Flipping only the first term inside the bracket would have given x + 7y instead, so item 4 is not the misconception above wearing a different hat.
  • "7p – p is 7p, because there is no number in front of the second one." Item 8. An unwritten 1 is still a 1, which is the mirror image of the unwritten multiplication sign in §4.3.
  • "18c + 11d is unfinished work." It is finished. There is no rearrangement that turns two independent letters into one, and saying so out loud is more useful than leaving the student hunting.
Transcript1,430 words

Here is a rectangle, and nobody has told you how big it is. Call the long side l and the short side b. The distance all the way round is just those four sides added. l plus b plus l plus b. That is honest, and it is also clumsy. So rearrange it. Put the two l terms together, and the two b terms. l plus l, plus b plus b.

And now each pair folds into one thing. Two l, and two b. The perimeter is two l plus two b. Four terms became two, and nothing was measured, guessed or looked up. But hold on. What exactly was just claimed there? That those two expressions are equal, and that word needs pinning down. Here it means something strict. They take the same value for every replacement of the letters.

Every single one. Not most, and not the ones you happened to try. So try it. Let l be three and b be four. The long form gives fourteen. The short form gives fourteen. But be careful about what that did and did not do. One matching pair proves nothing. Two l plus two b agrees with l plus three b on every square, and they are not the same expression.

These two are equal because one came from the other by rules that hold for all numbers. The substitution checks the working. Now watch that same collapse happen somewhere it matters more. Pencils cost c each. Over three days you buy five, then three, then ten. So you spend five c, plus three c, plus ten c. And that is eighteen c. Which looks like adding five, three and ten, and in a sense it is.

But notice that the letter was never added to anything. Five c plus three c is the distributive property read backwards. Bracket, five plus three, close bracket, times c. The numbers in front combine. The letter just sits there, being multiplied. And if a pencil costs fifty, both forms give nine hundred, which is a check rather than a reason. Erasers cost d each, and you buy four, then six, then one.

Four d plus six d plus one d, and that last one has an unwritten one in front. Eleven d. Same collapse, different letter. So the whole bill is eighteen c plus eleven d. And now a question people find genuinely uncomfortable. Can that go any further? It cannot, and here is how you know rather than how you feel. Hold c completely still, change only d, and the total changes anyway.

So the total is not settled by c alone, and no expression in one letter can possibly equal it. Eighteen c plus eleven d is not unfinished work. It is finished, and saying so is kinder than leaving you hunting. There is a way to see the collapse as a picture, and it is worth having. Take a rectangle of height v. Cut it with a vertical line into a piece four wide and a piece three wide.

The left piece has area four v. The right piece has area three v. Together, four v plus three v. But the whole rectangle is seven wide and v high, so its area is v times seven. Same rectangle, so the same area. That is the distributive property, drawn. And it works when you take a strip away just as well as when you add one. A rectangle twelve wide and n high, with a strip four wide cut off the end.

What is left is eight wide, so eight n, and also twelve n minus four n. Subtraction collects exactly as addition does. There are two words for all this, and they are worth having precisely. Terms carrying the same letter are called like terms. Five c, c and ten c are like terms. Twelve n and minus four n are like terms. Terms carrying different letters are unlike terms. Eighteen c and eleven d.

Like terms may be added into one. Unlike terms may not. And that is not a rule somebody invented in order to be strict. Like terms combine because the distributive property makes them combine, at every value. Unlike terms do not, because no arithmetic fact turns two independent letters into one. So the stopping point is decided by the mathematics, and never by how short the line looks. Now the step that goes wrong most often. A bracket with a minus in front of it.

You rent x chairs together with y tables. A chair costs forty, a table seventy five. When you return them, six comes back for each chair and ten for each table. So what you actually spend is forty x plus seventy five y, minus, bracket, six x plus ten y. The minus reaches everything in that second bracket. Both terms, not just the nearest one. So group the chairs with the chairs. Forty take away six, all of it times x.

And the tables with the tables. Seventy five take away ten, times y. Thirty four x plus sixty five y. You could have added that second bracket instead, provided both terms inside changed sign. Same rule, from the other end. The same move handles three expressions at once. In a quiz, p is what a right answer earns and q is what a wrong one costs. Charu scores seven p minus three q, then eight p minus four q, then six p minus two q.

Collect the p terms down one column. Seven, eight and six. Twenty one p. Collect the q terms down the other. Three, four and two, all being taken off. Minus nine q. Twenty one p minus nine q, and nothing was ever added across. Krishita totals twenty three p minus seven q, and the difference between them is worth looking at. Two p plus two q. The gap is itself an expression, not a number.

Which is exactly right, because how far ahead she is depends on what the marks are worth. One more shape, and then the audit. A number sitting in front of a bracket. Four, bracket, x plus y, close bracket, minus y. The four multiplies everything inside it. Four x plus four y. So the whole thing reads four x plus four y minus y. Now those two y terms are like terms, so they collect.

And here is the trap. That last y has no number written in front of it. It has an unwritten one, and an unwritten one is still a one. So four take away one, times y. Three y. Four x plus three y, and that same unwritten one is about to catch somebody out again. Here is a small block. Four threes, then r and s, then r and s again, then four threes.

Count it row by row. Twelve, then r plus s, then r plus s, then twelve. Count it by kind instead. Two r, two s, and eight threes. Or notice the block is symmetric, so count the top half and double it. Twelve plus r plus s, doubled. Three expressions that look nothing like each other. And every one of them simplifies to two r plus two s plus twenty four.

That last route only worked because the halves match, and it is worth knowing which step leaned on that. But the point stands. Different routes, one relation, and simplifying is how you see they were the same all along. So here are eleven finished simplifications, and the job is to judge them. The finish line is stated: no brackets left standing, like terms added, plain numbers added. Eight of the eleven are simply wrong.

Three a plus two b, claimed as five. Five of what? Those numbers were attached to different letters. Five minus, bracket, two minus six z, claimed as three minus six z. The minus stopped at the two. Seven p minus p, claimed to leave seven p, because the second had no number in front. It had an unwritten one. One of the eleven is already correct, and hunting for a mistake in it would itself be a mistake.

Two more contain no false arithmetic and are still not finished. One leaves like terms uncollected. The other is shorter than what it came from, but a bracket survives, and shortest was never the definition. And underneath it all: in simplest form the terms never outnumber the letters by more than one, and can be fewer. The letters cap the terms; they do not fix them.

Where this fits

Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.

Builds on

Comes up again in

The book

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