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Chapter 10 · The Other Side of Zero

Integer grids, and why the total comes out the same every time

यह वीडियो हिंदी में भी · Watch in Hindi

Integers in the world, in puzzles, and in history10 min

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10 min.

Also recorded in Hindi.Englishहिन्दी

The total in an integer grid is decided before you play. Circle whatever you like and it comes out the same.

The idea

Both puzzles in this section look like magic, and neither is: each grid was made to behave the way it does before anyone touched it. They are not made the same way, though, and merging them would be a mistake. The strike-out grid always totals the same because it was built by adding a row number to a column number — so whatever route you take through it, you collect every row number once and every column number once, and the total was decided before you started choosing. The hollow grid answers to a different condition, one on its two outer rows and two outer columns, and it is not a row-plus-column table. What the two share is the lesson: what looks like a property of your choices is a property of how the grid was made, which is why you can make one yourself and know the answer in advance.

What you should be able to do

  • Compute the sum of a row and of a column in a bordered grid and compare them
  • State what the section's border sum is, and find it for a given grid
  • Complete a partly filled grid so that all four border sums agree
  • Say which grids are forced to a single answer and which admit many, and why
  • Carry out the strike-out procedure on a grid and total the circled numbers
  • Predict the total before playing, by identifying the row and column numbers the grid was built from
  • Explain why the procedure always selects one entry from each row and each column
  • Construct a grid of either kind to a required total
  • Evaluate a repeating token pattern by finding its period and its value per period

Words to know

TermDefinition in one lineFirst introduced
border sumthe common total of each of the two outer rows and each of the two outer columnsprinted and defined in §10.4, p.263
hollow integer gridthe book's name for a square grid whose middle cell is emptyprinted as a sub-heading in §10.4, p.263
gridthe square array of integers both puzzles are set onprinted in §10.4, p.263
rowone horizontal line of cellsprinted in §10.4, p.263
columnone vertical line of cellsprinted in §10.4, p.263
strike outto rule through a whole row and column, removing them from playprinted in §10.4, p.264
circleto select an entry, the move that alternates with striking outprinted in §10.4, p.264
border integer square puzzlethe book's name for a puzzle of the first kind that you make yourselfprinted in §10.4, p.264
addition tablea grid whose entry is the sum of a row number and a column numbernot printed in this chapter; the explanation's name for the structure the book asks the reader to discover

Where people slip up

  • "The grid is magic." It is constructed. The whole value of the section is replacing "it always works" with "here is what was done to it", and the book asks that question outright.
  • "The border sum is the sum of all the numbers round the edge." It is not: it is the total of each single outer row and each single outer column, and the four corner entries are counted in two of those totals apiece. Getting this wrong makes every exercise in the section come out wrong.
  • "If I can complete the grid, my answer is the answer." Two of the three puzzle grids have many completions. A student who finds one and thinks they have found the one has missed the section's second question.
  • "In the strike-out game, choosing bigger numbers gives a bigger total." It gives the same total. Let the class try to beat it and fail; that failure is the motivation for section 8.
  • "The strike-out total is the sum of one row plus one column." It is the sum of all four row numbers plus all four column numbers, because the procedure takes one entry from every row and every column. Demonstrating that is section 9.
  • "Counting years back across the start of the common era is plain subtraction." It is not, and the chapter prints the hint that says why: the year before 1 CE is 1 BCE, with no year 0 between them. A count that crosses that boundary comes out one year short unless you allow for it. A count that stays on one side of it is unaffected, which is why only one part of the question needs the hint.
  • "To find the value of a hundred tokens you must count a hundred tokens." Find the repeating block, find its value, and count the blocks. The block is what the question is testing.
Transcript1,407 words

Here is a square of nine cells, and the cell in the middle of it is empty. Not zero. Empty. Nothing is written there, and nothing is meant to be. Around the outside sit eight numbers. Four, minus one and minus three along the top. Minus three and one down the sides. Minus one, minus one and two along the bottom. Add the top row. Four, take away one, take away three, and you land on zero.

Now add the bottom row. Minus one, minus one, two. Zero as well. Two rows, two zeros. That could be luck. It is not, and the reason is worth the next ten minutes. Try the left column, reading downwards. Four, minus three, minus one. Zero again. And the right column. Minus three, one, two. Zero. Four totals, four zeros, and that shared number has a name. It is the border sum.

Now a second square, with completely different numbers in it. Five, minus three, minus five along the top. Zero and minus five down the sides. Minus eight, minus two, seven along the bottom. Its four totals are minus three, minus three, minus three and minus three. Different numbers, a different answer, and exactly the same strange agreement. Before going any further, the one mistake that ruins every puzzle in this family.

The border sum is not the total of all eight numbers around the edge. On the first square those eight come to minus two. Its border sum was zero. The reason is the four corners. A corner sits in a row and in a column at the same time, so walking round the outside collects it twice over. A border sum is one row, or one column, taken on its own.

And the empty middle belongs to no row and no column that counts, which is precisely why it is drawn empty. Now turn the puzzle around. Instead of being handed the square and asked for its border sum, you are handed the border sum and most of the square is missing. Six in the top left, eight beside it, minus five at the middle right, minus two at the bottom centre. Everything else is blank, and the border sum has to be minus two.

Start where you have the most. The top row already holds six and eight, which make fourteen, so the last entry there must be minus sixteen. That fills a corner, and filling a corner is what unlocks a column. The right column now holds minus sixteen and minus five, which make minus twenty one, so the bottom right must be nineteen. Two more steps of the same kind and the square is finished. Every blank was forced by a corner that had just been filled.

But that is not what happens with every square. Here is another. Minus ten in the top left, nine in the bottom left, minus five at the middle right, and the border sum has to be four. The left column already holds two of its three entries, so the middle left is forced to be five. So far, the same as before. And then it stops. Choose anything you like for the top right corner, and the rest of the square arranges itself around your choice. There are dozens of answers.

The difference is not the numbers. It is how many entries you were handed at the start. Eight cells to fill and four conditions to meet means four entries is what it takes. The square that was forced had four. This one has three. Second puzzle, and this one is a game. Here is a square of sixteen numbers, four rows across and four columns down. Circle any number you like. Then rule out the whole row it sits in, and the whole column it sits in, and those are gone.

Circle any number that survived. Rule out its row and its column as well. Keep going until there is nothing left to circle. You will have circled four numbers, and the game is to add them up. Circle minus one. Then nine. Then minus seven. Then minus two. They add to minus one. Now play it again, and this time try to do better. Start with nine, the largest number on the board. Out goes its row, and out goes its column.

Take minus five next. Then two, then minus seven, because after two turns there is not much choice left. Nine, minus five, two, minus seven. Minus one. Try a third route, and a fourth. Chase the big numbers, or chase the small ones, or close your eyes. Minus one, every time. There are twenty four different ways to play this board, and all twenty four of them come to minus one.

So the total was never yours to choose. It was settled before you sat down. Look at the top row of the square: three, four, zero, nine. Now look at the second row. Minus two, minus one, minus five, four. That is the top row with five taken off every single entry. The third row is the top row with two taken off. The last row is the top row with ten taken off.

So every number in that square is a column number plus a row number. Three, four, zero and nine going across. Nothing, minus five, minus two and minus ten going down. It is an addition table, and it was one the whole time. Now watch what the rules of the game actually do to you. The moment you circle a number, its entire row leaves the board. So you can never circle twice from the same row.

The same is true of columns. Four circles, four different rows, four different columns. Which means the four numbers you circled are a row number plus a column number, four times over, and between them they use up every row once and every column once. So the total is all four row numbers plus all four column numbers, whichever four cells you happened to take. Three and four and zero and nine is sixteen. Nothing and minus five and minus two and minus ten is minus seventeen. Sixteen with minus seventeen is minus one.

Here is another board of the same kind, and there is something wrong with it. Seven, ten, thirteen, sixteen along the top, and each row below is the row above it with nine taken off. Except in one place. The second entry along the bottom row ought to be minus seventeen. What is sitting there is minus seven. One digit. And with that digit missing, the puzzle stops working. Eighteen of the twenty four ways to play still come to minus eight. The six routes that pass through that one cell come to plus two instead.

So the game is not magic, and it is not sturdy either. It works because somebody built it to work, and a single wrong entry is enough to break it. One more thing that is decided in advance. Here is a line of tokens. Three green, then two red. Three green, then two red. On and on it goes. Each green token is worth one, and each red token takes one away.

There are a hundred tokens in the line, and the question is what the whole line comes to. You could count them one by one. Better to find the piece that repeats. Three green and two red is five tokens, worth three take away two, which is one. A hundred tokens is twenty of those pieces, so the line is worth twenty. Sixty green and forty red, and you never had to count past five.

Which is the idea underneath all of it. What looked like a property of your choices turned out to be a property of how the thing was built. So build one. Choose four numbers for the columns and four for the rows, add them into a square, and hand it to somebody. Whatever they circle, they will land on the total of your eight numbers, and you knew that before they picked anything.

For the other puzzle, choose a border sum first and work inwards, and remember that four given entries is what pins a square down. That is the difference between a trick and a piece of mathematics. A trick you have to perform. This one you can hand over, and it still works.

Where this fits

Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.

Builds on

Either side of this one

The book

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