PrepShorts · Study sheet · Class 11 Mathematics · Chapter 9, Straight Lines
Chapter 9 · Straight Lines
The gap between two parallel lines as one distance measured once
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Stand anywhere on one of two parallel lines and measure across to the other, and the answer never changes - though the usual proof only ever measures from one convenient point.
The idea
Talking about the distance between two parallel lines presumes something: that the perpendicular distance from a point of one to the other is the same wherever on the first line you stand. §9.4.1 does not prove that — it assumes it, by picking one convenient point and measuring there. The choice it makes is the crossing of the first line with the x-axis, which does not exist when the lines are horizontal, so the derivation as printed excludes a case its own formula handles perfectly. The version the chapter leaves to the reader, taken in the general form, has no such exclusion and is the better argument: it never names a point at all, and that is exactly why the answer cannot depend on one.
What you should be able to do
- Say what has to be true before "the distance between two parallel lines" is a well-defined quantity
- Follow the §9.4.1 derivation, naming the point it measures from
- Identify the family of parallel pairs for which that point does not exist
- Check that the printed formula still gives the right answer for that family
- Reproduce the general-form derivation the chapter leaves to the reader, and say why it is free of the exclusion
- Recognise that two parallel lines in general form must be scaled to share their leading coefficients before the constants may be subtracted
- Compute the distance between two parallel lines given in either shape
- Write a line parallel to a given line through a stated point
- Find the line lying midway between two given parallels
Words to know
| Term | Definition in one line | First introduced |
|---|---|---|
| parallel lines | lines with equal slopes, which is the situation this section measures across | printed in the §9.4.1 heading, p. 166 |
| perpendicular distance | the length of the perpendicular, which remains the measure used here | printed in §9.4, p. 166 |
| slope-intercept | the shape §9.4.1 writes the two lines in first | printed in §9.3.4, p. 161 |
| general form | the shape §9.4.1 restates the result in, and leaves the reader to derive | printed as general equation of a line at the end of §9.3.5, p. 163 |
| equidistant | at equal distances from both lines — the condition defining the midway line | printed in Miscellaneous Exercise q20, p. 174 |
| well defined | said of a quantity whose value does not depend on the arbitrary choice made to compute it | an added term, not printed in this chapter; the section relies on the property without naming it |
| matched coefficients | the explanation's name for scaling two parallel equations until their leading pairs agree | an added term; the chapter presents the general-form result already matched |
Where people slip up
- "The distance between two parallel lines obviously does not depend on where you measure." It is true and it is not obvious, and §9.4.1 assumes rather than establishes it. The general-form derivation is the one that proves it, because it never picks a point.
- "Subtract the constants and divide." Only when the two leading pairs are identical. Miscellaneous Exercise q20 gives two parallel lines whose coefficients are proportional but not equal, and subtracting first gives a wrong answer that still looks plausible.
- "The derivation covers all parallel pairs." It does not cover horizontal ones, because the point it measures from is a crossing with the x-axis, and a horizontal line either misses that axis altogether or else coincides with it. Either way the coordinates the derivation writes down demand a division by zero. The formula covers such pairs; the printed argument does not.
- "Distance between parallel lines is a new formula." It is the §9.4 formula applied once, at a point chosen for convenience. Nothing is added except the observation that the choice does not matter.
- "You can measure between the two y-intercepts." That measures a vertical gap, not a perpendicular one. The two agree only when the lines are horizontal, and the divisor in the formula is exactly the correction factor between them.
- "Two lines with the same slope are always a distance apart." If the constants are equal the two equations describe one line and the distance is zero. That is the boundary case of the formula and it comes out right.
- "Any two lines that do not meet are parallel in this sense." In a plane that is true; the chapter is working entirely in one plane and never says so. Do not carry the criterion into three dimensions unexamined.
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Worked answers: Exercise 9.1 · Exercise 9.2 · Exercise 9.3 · Miscellaneous Exercise · this video explains Exercise 9.3 Q5, Exercise 9.3 Q6, Miscellaneous Exercise Q20
Transcript1,743 words
Two lines run alongside each other and never meet. How far apart are they? Stand at a point of the first line and measure across to the second, and you get a length. Walk a little way along the first line and measure again. Nothing so far says the two lengths have to agree. The phrase everybody uses - the distance between two parallel lines - is quietly claiming that they do.
Before that phrase means anything at all, somebody has to check it. In a window of one hundred and sixty-nine points there are one hundred and forty-eight thousand and fifty pairs of distinct lines running in the same direction. For every one of those pairs, the shortest way across was measured from every single point of the first line, and then from every point of the second. Pairs where two points of a line gave different answers: none.
Pairs where the two directions of measuring disagreed: none. And to be sure the test can say no, the very same machinery was run on thirteen thousand seven hundred and seventeen pairs of lines that do cross. Forty-seven of those came out constant as well - every one of them a line the window sees at exactly twice, whose two points sit either side of the crossing line. Of the four thousand and thirty-two crossing pairs whose first line has three points or more, the number that came out constant is none.
Write the two lines with the same slope and different heights, and draw them. The first one crosses the flat axis somewhere, and that crossing is a point of the first line that costs nothing to find. Its second coordinate is nothing, and its first coordinate is minus the first height divided by the slope. That is the point the argument measures from. Drop the perpendicular from there onto the second line and its length is the answer.
It is the point-to-line formula, run once, at a point chosen because it was easy to write down. Put that point into the second line's equation and watch what happens. The second line, tidied, is the slope times x, minus y, plus the second height. At our point, y is nothing, so the middle term goes. And x is minus the first height over the slope, so the slope multiplying it cancels the slope underneath, leaving minus the first height.
What is left upstairs is the second height minus the first, and the size of that. Underneath is the root of one plus the slope squared. So the answer is the difference of the two heights, divided by that root. There is a hole in that, and it is exactly where the argument was most convenient. The point we measured from was a crossing with the flat axis, found by intersecting.
Ask the intersection routine for that point on every line the window sees, and it refuses thirteen times. Twelve of the refusals say the two never meet. One says something different: that line does not miss the flat axis, it IS the flat axis, so every point of it is a crossing and no single point is the crossing. Two distinct reasons, and the routine produced both without being told to look for them.
Those thirteen lines are exactly the ones every point of which stands at one height - none refused that is not level, and none level that was not refused. Which makes seventy-eight of the parallel pairs impossible to run this argument on at all. But now look at what the formula itself says about those seventy-eight. If the two lines are level, the slope is nothing, so the root of one plus the slope squared is just one.
The answer collapses to the difference of the two heights, full stop - which is the vertical gap you could measure with a ruler. It is plainly right, and the argument that produced it could not be run. Scored properly, one pair in every seven was put through the whole derivation: twenty-one thousand one hundred and thirty-eight of them went through, with no disagreement anywhere against the smallest way across.
Twelve refused to start. So the exclusion belongs to the choice of point, and not to the result. Write both lines in the general shape, with the same two leading coefficients and different constants. Now take any point of the first line at all - do not say which one, do not write its coordinates down. Because that point is on the first line, the first coefficient times its x plus the second times its y is minus the first constant.
So when you feed it into the second line's left-hand side, those two terms collapse and what is left is the second constant minus the first. The numerator is the difference of the two constants, and no coordinate of the point has survived. Divide by the root of the two leading coefficients squared and added, and that is the whole thing. Over all six hundred and eighty-three thousand eight hundred and forty-four points stood at, the number where that left-hand side was not the difference of the two constants is none.
No point was chosen, and there is no case to leave out. We asked whether the answer depends on where you stand, and here is the reason it cannot. The derivation began at an arbitrary point of the first line and ended with an expression the point is not in. That is not the same as measuring at one convenient place and hoping. It is why the phrase is allowed to say THE distance rather than A distance.
What is the same, every time, is the answer within one pair. The two equations must carry the same pair of leading coefficients. Two parallel lines can perfectly well be written with coefficients that are proportional but not equal - multiply one equation through by three and it is the same line, still. Forty-five thousand five hundred and fifty-six such rescalings were tried, and the number that stopped naming the line they came from is none.
The equation is fine. It is the subtraction that is not. Subtract the constants anyway and the answer is wrong forty-four thousand nine hundred and twenty-one times. It is right six hundred and thirty-five times, which is the dangerous part, and those six hundred and thirty-five are not random. Three hundred and sixteen of them are pairs whose second line passes through the origin, so its constant is nothing and multiplying it changed nothing.
The other three hundred and nineteen are pairs where the rescaling happened to land on the mirror image of the right constant. Accidents of any other kind: none. So scale first, every time. A related habit is to measure between the two heights, straight up the page. That is not the distance, and the formula tells you exactly by how much it misses. Of one hundred and forty-seven thousand nine hundred and seventy-two parallel pairs that both reach the upright axis, the vertical gap between them equals the true distance in seventy-eight cases.
Those seventy-eight are the level pairs - the only ones where up the page and across are the same direction. Everywhere else the vertical gap is too big, and the number it is too big by is the divisor in the formula. Pairs where that relation failed to hold: none. So the root underneath is not decoration. It is the correction between the gap you can see and the gap you want.
Once the two constants are matched, the line lying midway between the two is almost free. Keep the leading pair, double it, and take the sum of the two constants. Four thousand seven hundred and seventy-six of those were built and then checked by minimising onto them. Ones whose distance varied along either line: none. Ones not equally far from the two: none. And the squared distance is a quarter of the pair's, every time, which is what halfway means.
Here is the version that catches people: nine x plus six y minus seven, and three x plus two y plus six. Those are parallel, but the leading pairs do not match, so scale the second by three - nine x plus six y plus eighteen - and only then average. The midway line is eighteen x plus twelve y plus eleven, and its squared distance from each of the two is six hundred and twenty-five over four hundred and sixty-eight.
Average the constants without scaling and the line you get is not equally far from the two at all - it sits much nearer the first. Three x minus four y plus seven, and three x minus four y plus five. The leading pairs already agree, the constants differ by two, the root of nine plus sixteen is five, so the distance is two fifths. Fifteen x plus eight y minus thirty-four, against fifteen x plus eight y plus thirty-one: the constants differ by sixty-five, the root of two hundred and twenty-five plus sixty-four is seventeen, and the answer is sixty-five over seventeen.
Some letter times x plus y, plus one number; and the same letter times x plus y, minus another. Eighty whole-number cases were tried and every one gave the sum of the two numbers over that letter times the root of two. But sixteen values were refused outright, because when the letter is nothing neither equation names a line at all, and there is nothing to be a distance between.
And to draw a parallel through a given point, keep the leading pair and solve for the constant. Parallel to three x minus four y plus two, through minus two and three, is three x minus four y plus eighteen. Keeping the leading pair and changing only the constant walks you along the parallel family; three hundred and twenty-four of those were built and the given point sits on every single one.
And if the two constants are equal, the two equations are one line and the distance is nothing, which the formula gets right without being asked. So: there is no new formula in any of this. There is the point-to-line formula, used once, and one observation - that the answer does not depend on where you used it. That observation is not obvious, it is not usually proved, and proving it is exactly what makes the phrase mean something.
Where this fits
Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.
Builds on
- The shortest route from a point to a line, read off its coefficientsClass 11 · Ch 9, Straight Lines
- Equal slopes mean parallel; slopes multiplying to minus one mean perpendicularClass 11 · Ch 9, Straight Lines
- Naming a line by where it crosses the axesClass 11 · Ch 9, Straight Lines
- Naming Ax + By + C = 0, the one form the distance formula ahead will takeClass 11 · Ch 9, Straight Lines
Either side of this one
- One surface, four curves, chosen by the angle of the cutClass 11 · Ch 10, Conic Sections