PrepShorts · Study sheet · Class 11 Mathematics · Chapter 6, Permutations and Combinations
Chapter 6 · Permutations and Combinations
A shorthand for descending products, and why the empty product is set to one
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One factorial equals one times zero factorial — that single line forces zero factorial to equal one, not zero, the way an empty sum is forced to equal nothing.
The idea
The exclamation mark introduces no new operation; it names a product the counting argument had already produced, and almost everything this chapter goes on to do with it flows from one relation — that n! is n times the factorial below it. That relation is why a quotient of two factorials collapses to a handful of factors without either factorial ever being evaluated, and running it downward one step past 1 forces the value of 0! : if 1! is to equal 1 × 0!, then 0! can only be 1. The chapter sets 0! = 1 by definition; the reason it is the only workable choice is that every later formula, starting with the arrangement of all n objects, divides by it.
What you should be able to do
- Write out n! for small n and read the symbol aloud correctly
- State the relation between n! and the factorial one step below it, and use it to rewrite a factorial in cascade
- Say why a peel of two or three factors carries a lower bound on n, and what goes wrong without it
- Evaluate a quotient of factorials by cancelling rather than by computing either one
- Explain why 0! is set to 1, arguing from the relation rather than from convention
- Demonstrate that factorial does not distribute over addition or subtraction, by computing a stated instance
- Solve an equation for an unknown numerator standing over a factorial
- Recognise the general result behind the chapter's two such equations
Words to know
| Term | Definition in one line | First introduced |
|---|---|---|
| factorial | the product of the whole numbers from 1 up to a given one, written with an exclamation mark after the number | printed in this chapter, §6.3.2, p. 105 |
| natural number | one of the counting numbers the factorial product runs over | printed in this chapter, §6.3.2, p. 105 |
| define | to fix a value by stipulation, as the chapter does for the factorial of zero | printed in this chapter, §6.3.2, p. 105 |
| empty product | a product with no factors in it, whose agreed value is 1 | an added term; the chapter fixes the value without naming the idea |
| peeling | rewriting a factorial as a few explicit factors multiplied by a smaller factorial | an added phrasing; the chapter performs this repeatedly with no name for it |
Where people slip up
- "3! + 4! = 7!" The chapter puts this question to the student directly, which means it expects the belief. It is false by a wide margin: 30 against 5040. Factorial does not carry across a plus sign, and neither does it carry across a minus sign — Example 5(iii) computes 4920, not 2 and not 2!.
- "0! = 0, because there is nothing to multiply." A product of no factors is taken to be 1 for the same reason a sum of no terms is taken to be 0: it is the value that leaves the neighbouring rules undisturbed. Here the neighbouring rule is 1! = 1 × 0!.
- "0! = 1 is just a convention, so it does not matter." It matters at the next section: the arrangement of all n objects is written as n! divided by 0!, and the answer is n! only because that divisor is 1.
- "You have to work out 12! before you can divide by 10!." You never do. The larger factorial contains the smaller one whole, and cancelling it is the entire technique of this section.
- "(10!)(2!) is the same as 20! or 12!." It is a product of two numbers, 3628800 and 2. The exclamation mark binds to the number it follows, not to the whole expression.
- "n! = n(n − 1)(n − 2)! always." Only for n at least 2. The printed brackets carrying those lower bounds are content, not decoration: you cannot peel off more factors than the number has.
- "7!/5! = (7/5)!" Nothing licenses that. Cancel, do not simplify the argument.
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Worked answers: Exercise 6.1 · Exercise 6.2 · Exercise 6.3 · Exercise 6.4 · Miscellaneous Exercise · this video explains Exercise 6.2 Q1, Exercise 6.2 Q2, Exercise 6.2 Q3, Exercise 6.2 Q4, Exercise 6.2 Q5
Transcript1,916 words
Fill three places from six objects and you write six times five times four. Fill five places from nine and the line runs to five factors. Use every object you have, and the line runs all the way down to one. That last case turns up so often it was given a name, and the name is a mark you have seen: a number with an exclamation mark after it.
It introduces no new operation. It is a name for a product you were already writing out. Here is what it names, one line at a time. One on its own is one factorial. One times two is two factorial, and it comes to two. One times two times three is three factorial, which is six. One times two times three times four is four factorial, twenty-four. The pattern is the whole definition: multiply the whole numbers from one up to the number in front of the mark.
Look at the list of factors. The factors of five factorial are one, two, three, four, five. The factors of four factorial are one, two, three, four. The same list, with five missing off the end. So five factorial is five times four factorial, and that is not a trick. It is what the two lists are. In general, a factorial is the number itself times the factorial one step below it.
That single relation is what almost everything done with this symbol rests on, and it was got by nothing more than noticing how the two lists of factors sit inside each other. Now apply it over and over to the same number. Five factorial is five times four factorial. Apply it again to the four factorial: five times four times three factorial. Again: five times four times three times two factorial.
And again: five times four times three times two times one factorial. Four lines. Every one of them is the same relation used once more, and every one of them comes to a hundred and twenty. Nothing was calculated: the number has been rewritten four ways, with more of its factors standing outside the symbol each time. Here is the interesting part. Nothing stops you doing it once more. One factorial is one times nought factorial. So the last line becomes five times four times three times two times one times nought factorial.
And now you have to say what nought factorial is worth. Go back to the definition: the whole numbers from one up to the number in front of the mark. From one up to nought. There are no such numbers. The list of factors is empty. So this is not an arithmetic question at all. It is a question about what to write down when there is nothing to multiply.
You could argue for zero, on the grounds that there is nothing there. You could argue for one. You could refuse to answer. So let us not argue. Let us try each and see which survives. Four candidates: nought, one, two, or a flat refusal to say. And one test they all have to pass: the relation. A factorial is the number times the factorial below it. Score each candidate at every value of n from one to nine.
Start high. At n equal to five it reads a hundred and twenty equals five times twenty-four, which is true, and no candidate was consulted to get there. The same at four, at three, at two: the relation never reaches down that far, so all four agree everywhere above one. There is exactly one place any of them is tested, and it is n equal to one. There the relation reads: one factorial equals one times nought factorial.
One factorial is one. So the candidate has to satisfy one equals one times itself. Nought fails, since that would make one factorial come out as nothing. Two fails, since that would make it come out as two. Refusing to answer does not make the relation false, but it does not carry it either. It leaves the last step unspoken. One passes. Out of nine values of n, the counts are eight, nine, eight and eight, so exactly one candidate carries the relation the whole way down.
Put the cascade back up and work out all five lines under each candidate in turn. The first four lines never touch nought factorial, so they read a hundred and twenty every time, whichever candidate you are using. It is the fifth line that moves. Under nought it collapses to zero; under two it jumps to two hundred and forty; under one it stays at a hundred and twenty. Count the different values in each column and you get two, one, two.
Only one candidate leaves the column standing at a single value, which is the very least you can ask of a rewriting that was supposed to change nothing. So nought factorial being one is not a convention you have to swallow. It is the only value that leaves the relation alone. The same relation lets you pull factors out one at a time, and it is worth knowing where that stops.
Pull one factor off: n factorial is n times n minus one factorial. Pull two off: n times n minus one times n minus two factorial. Pull three off: n times n minus one times n minus two times n minus three factorial. Each needs room underneath, and you can find out how much by asking. Take the three-factor version at n equal to two. It asks for two times one times nought, times the factorial of minus one.
There is no such thing. There is no run of whole numbers from one up to minus one, so there is nothing there to name. Ask each version for the smallest n it will say anything about, and you get one, two and three. That is where the lower bound written beside each of these comes from. It is not decoration; it is the point at which the rewriting stops naming anything.
Now the reason this symbol is worth having. Seven factorial over five factorial. The obvious move is to work out both numbers and divide. Do not. Seven factorial contains five factorial whole: one, two, three, four, five, and then six and seven. Strike out the shared block on both sides. What is left above is six and seven. What is left below is nothing at all. Six times seven is forty-two, and neither factorial was ever worked out.
Harder: twelve factorial, over ten factorial times two factorial. Above, the whole numbers up to twelve. Below, the whole numbers up to ten, and then one and two again. Strike out one for one. Left standing above: eleven and twelve. Left standing below: one and two. A hundred and thirty-two over two. Sixty-six. Twelve factorial is a nine-digit number, and the answer is two digits long. That is the whole saving, in one line.
Two more, quickly. Five factorial over two factorial times three factorial is ten, and that shape is worth remembering, because it comes back later carrying a meaning. Nine factorial over four factorial is fifteen thousand one hundred and twenty, from five factors and no evaluation. One warning. The mark binds to the number directly in front of it and to nothing else. Seven factorial over five factorial is not the factorial of seven over five. Cancel the factors; do not tidy up the number inside the symbol.
Back to nought factorial, because there is a second argument for it, and it shares no step with the first. Take four distinct objects and put all four of them in a row. Build every arrangement by hand and count them: twenty-four. Now the formula. Filling r places from n objects is n factorial over n minus r factorial. Set r equal to n, because we used everything. The bottom becomes nought factorial.
If nought factorial were nought, the formula divides by nothing and hands back no answer at all. If it were two, the formula gives twelve. Half of what we counted, and we counted by hand. If it is one, the formula gives twenty-four, which is what is actually there. So two arguments, one from the relation and one from a count made by hand, corner the same value. That is what makes it forced rather than agreed.
One belief worth killing before it costs you anything: the mark does not distribute across a plus sign. Three factorial is six. Four factorial is twenty-four. Add them and you have thirty. Seven factorial is five thousand and forty. Thirty against five thousand and forty: the right-hand side is a hundred and sixty-eight times the size, which is not a near miss you could put down to carelessness. Nor does it carry across a minus. Seven factorial less five factorial is four thousand nine hundred and twenty.
It is not two, and it is not two factorial. Subtracting the numbers does not subtract the marks. Here is a shape that turns up constantly. One over eight factorial, plus one over nine factorial, equals x over ten factorial. Solve for x. The move is to multiply every term by the largest factorial in sight, which is ten factorial. The right-hand side becomes x, which is the whole point of choosing it.
On the left, the first term becomes ten factorial over eight factorial. Strike out the shared block: nine and ten survive, so that is ninety. The second becomes ten factorial over nine factorial. Only ten survives, so that is ten. Ninety plus ten. x is a hundred. Try the same shape one size down: one over six factorial plus one over seven factorial equals x over eight factorial. Eight factorial over six factorial leaves seven and eight, so fifty-six. Eight factorial over seven factorial leaves eight.
Fifty-six plus eight. x is sixty-four. A hundred, and sixty-four. A hundred is ten times ten, and sixty-four is eight times eight. And ten and eight are exactly the numbers standing under the x in each problem. So do it once in n and be finished with the whole family. One over n minus two factorial, plus one over n minus one factorial, equals x over n factorial. Multiply through by n factorial. The first quotient leaves two factors: n minus one, and n.
The second leaves one factor: n. So x is n times n minus one, plus n. The minus n and the plus n cancel, and x is n times n. Run that from three up to twelve and the answers are nine, sixteen, twenty-five, thirty-six, forty-nine, sixty-four, eighty-one, a hundred, a hundred and twenty-one, a hundred and forty-four. Every one of them satisfies the equation it came from. Two problems that look like separate drill are one problem, and it has an answer you can read off without solving anything.
So, the habit this all adds up to. Small factorials: work them out, and know four factorial is twenty-four on sight. Large ones sitting in a quotient: leave them alone and strike out what the two sides share. A factorial you evaluated and then had to cancel was wasted effort. And nought factorial is one because the relation and the count both refuse to work with anything else, not because someone decided it.
The mark itself never was a new operation. It is a short name for the descending product the counting had already produced.
Where this fits
Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.
Builds on
- Filling a row of places one at a time from a supply of distinct objectsClass 11 · Ch 6, Permutations and Combinations
Comes up again in
- The closed formula, and how allowing repeats changes the count entirelyClass 11 · Ch 6, Permutations and Combinations
- Dividing out the swaps you cannot see when some objects are identicalClass 11 · Ch 6, Permutations and Combinations
- Every selection was counted once per arrangement of itselfClass 11 · Ch 6, Permutations and Combinations
- Choosing what to leave out, and the rule that builds each count from two smaller onesClass 11 · Ch 6, Permutations and Combinations
- Rewriting the triangle with selection counts, so any row is reachable directlyClass 11 · Ch 7, Binomial Theorem