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Chapter 4 · Quadratic Equations

Why the sign of b² − 4ac settles how many real roots exist

What the discriminant decides15 min

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15 min.

You can say how many real roots an equation has without solving it, and without even knowing where they are. Both roots start at the same place and are pushed apart by one term, so the only question is what that push is - a real distance, no distance, or no real number to push by.

The idea

The three cases are not three rules to be memorised — they are one sentence read three times. Both roots sit at the same place, −b⁄2a, and are then pushed apart by √(b² − 4ac)⁄2a; that push is the only part of the formula where the count of answers can change. A positive b² − 4ac pushes them a real distance either way and there are two; a b² − 4ac of nothing pushes them nowhere and they land together; a negative b² − 4ac supplies no real distance to push by, and no real answer survives. That is why the sign alone decides, why its size is irrelevant, and why the question "how many?" can be settled without ever finding a root — which is exactly the move the chapter makes when it declares a pole can be erected before saying where.

What you should be able to do

  • Compute b² − 4ac from an equation in standard form, keeping every sign
  • State the three verdicts the sign of b² − 4ac produces, and give the reason for each from the shape of the formula rather than from memory
  • Explain why the two roots are always arranged symmetrically about −b⁄2a
  • Explain why a negative b² − 4ac leaves no real root, in terms of what squaring a real number can and cannot produce
  • Answer a "is this possible?" question by computing a discriminant alone, without solving
  • Recognise that a vanishing discriminant and a repeated linear factor are the same situation described two ways, and demonstrate it on a worked example
  • Find the value of an unknown coefficient that forces equal roots, and say why one of the algebraic answers may have to be discarded
  • Decide whether a described rectangle can exist, using the discriminant of the equation the description produces

Words to know

TermDefinition in one lineFirst introduced
discriminantthe quantity b² − 4ac, whose sign alone settles how many real roots there areprinted in this chapter (§4.4, p. 45)
distinctdifferent from each other — the word the chapter uses for the two roots in the positive caseprinted in this chapter (§4.4, p. 45, and §4.5, p. 47)
coincidentlanding on the same value, the Summary's word for the case where the discriminant vanishesprinted in this chapter (§4.5, p. 47)
real numberthe only kind of number this chapter works with, which is why a negative discriminant ends the searchprinted in this chapter (§4.2, p. 39, and §4.4, p. 45)
roota number satisfying the equationprinted in this chapter (§4.3, p. 42)
repeated factora linear factor occurring twice, the factorising counterpart of a vanishing discriminantprinted in this chapter (§4.3, p. 43)
perimeterthe total boundary length of the park in Exercise 4.3 Question 5printed in this chapter (Exercise 4.3, p. 47)
nature of rootsthe chapter's own name for the question this topic answersprinted in this chapter (§4.4 heading, p. 44)
centre of the rootsthe value −b⁄2a, which both roots are measured froman added term; not printed in this chapter, which writes the quantity without naming it
perfect-square discriminanta discriminant that is itself a square, which would separate rational from irrational rootsan added term; this chapter does not draw that distinction anywhere

Where people slip up

  • "A bigger discriminant means more roots." It means the roots are further apart. Only the sign changes the count.
  • "No real roots means no solution, so the question is broken." It means the described situation cannot occur, which is a real and useful answer — Exercise 4.3 Question 4 asks precisely for it.
  • "No real roots means there are roots somewhere else." That is true in mathematics beyond this book, but this chapter works entirely within the real numbers and never introduces any other kind; a Class X answer stops at "no real roots".
  • "Equal roots means one root." The chapter counts two, and the Summary calls them coincident. The factorising picture explains why: the factor producing that value occurs twice.
  • "b² is negative when b is negative." In Example 7, b is −4 and b² is 16. This single slip flips the verdict in that example from none to two.
  • "4ac is negative when c is negative." In Example 8, c is −60, so 4ac is −240, and subtracting it adds 240 to the discriminant. Getting this right is what makes 289 rather than −191.
  • "If the discriminant is a perfect square the roots are rational." True, but this chapter neither states nor uses it, and a Class X answer should not depend on it. It is offered here so that a student who has met it elsewhere knows where it sits.
  • "You still have to solve to know how many roots there are." You do not, and Example 8 is the chapter's demonstration that you do not.
Transcript2,078 words

Here is a question about an equation, and it is not the question you are used to. Not 'what are the roots'. Just: how many are there? It sounds like the smaller half of the same job. It is not. You can answer it without solving anything, from one number you can work out in a single line. And that number is not really a number. What matters about it is only its sign.

To see why, take the formula and split it in the right place. x is minus b over two a, plus or minus the square root of b squared minus four a c, over two a. The first piece has no plus-or-minus in it. It is one number, and both roots carry it. So think of it as a place: both roots start there. Call it the centre. The second piece is what tells them apart. One root moves that far to the right, the other that far to the left.

That is a push. And the centre is genuinely a centre — the whole expression is symmetric about it. That was measured, not asserted. Over seventeen thousand offsets, the value a step right of the centre matched the value a step left, every single time. And the same test about a different point — minus b over a — failed on sixteen thousand of them. So the centre is that value and not another.

Now look at where the count of answers could possibly change. Not in the centre. The centre is one number whatever a, b and c are, and it is there in both roots. It has to be the push. That is the only part that can behave differently. And there are exactly three things a push can be. It can be a real distance, in which case the two roots go to different places.

It can be no distance at all, in which case they both stay where they started. Or there can be no real number available to push by — and then nothing real comes out at all. Three cases — one picture with the push set to three different things. Take the first case. b squared minus four a c is positive. Then its square root is a real number, and it is not nothing. So the push is a genuine distance.

One root lands to the left of the centre, the other the same distance to the right, and they are two different numbers. Two real roots, and the word for them is DISTINCT — different from each other. That is the case you have met most often — which is why it is worth naming as a case at all. Now let b squared minus four a c be nothing at all.

The square root of nothing is nothing. So the push has no length. Add nothing to the centre and you get the centre. Subtract nothing and you get the centre again. Both roots land on minus b over two a. One value, arrived at twice. And the careful way to say it is that there are two roots which happen to be the same number. The word for that is COINCIDENT — they coincide.

That is not pedantry. The second one is hiding in a factorisation, and we will go and find it. The third case. b squared minus four a c is negative. Now the formula asks for the square root of a negative number, and there is no real number that answers. Because a square root is a number you multiply by itself. And a real number multiplied by itself is never negative.

Positive times positive is positive. Negative times negative is also positive. And nothing times nothing is nothing. That was checked over twelve hundred and one numbers, six hundred of them negative. Not one square came out negative. So there is no real distance to push by, and no real root exists. Not hidden, not hard to find — there is nothing to find. The quantity doing all this work has a name. It is called the discriminant, and it is b squared minus four a c.

And the name is exact. To discriminate is to tell things apart, and that is precisely what it does: it tells the three cases apart, and it does nothing else. Positive: two distinct real roots. Nothing: two real roots which coincide. Negative: no real roots. You will see both wordings for the middle one; learn both. And notice what is NOT in that list. Nothing about where the roots are, and nothing about how big anything is.

Which brings up the mistake this topic actually produces: that a bigger discriminant means more roots. It does not. Take x squared minus one. Its discriminant is four, and its roots are one and minus one. Now take x squared minus ten thousand. Its discriminant is forty thousand — ten thousand times as large — and its roots are a hundred and minus a hundred. Two roots in both. The bigger discriminant did not buy a third one.

What it bought was distance. The roots are further apart, because the push is longer. That was swept as well. Five thousand quadratics, sorted by the SIZE of their discriminant instead of its sign. The band of discriminants a hundred or more holds fifteen hundred equations with two roots and two hundred and forty with none. The size tells you nothing about the count. Sort the same five thousand by sign instead and every single one falls into line. Only the sign decides.

So here is the whole method, on a real equation. Two x squared minus four x plus three equals nought. a is two, b is minus four, c is three. b squared. Careful here — b is minus four, and minus four squared is sixteen, not minus sixteen. Four a c is four times two times three, which is twenty-four. Sixteen minus twenty-four is minus eight. Negative. So there are no real roots, and we are finished. One line, no solving, no formula.

And that sign trap is not a small thing. Read b squared as minus sixteen and you would get minus forty, which is still negative — but on other equations that slip flips the verdict outright. The real power of this shows up when the question is not about an equation at all. A pole is to stand on the boundary of a circular park thirteen metres across, seven metres further from one gate than from the other, the two gates sitting at opposite ends of a line through the centre.

That situation turns into x squared plus seven x minus sixty equals nought. Now: is such a position possible? The discriminant is forty-nine minus four times one times minus sixty. And c is minus sixty, so that is minus two hundred and forty — which we are subtracting. Forty-nine plus two hundred and forty. Two hundred and eighty-nine. Positive. So yes. A position exists. And notice that we now know it exists without having the faintest idea where it is.

Only afterwards do we find it: five metres from one gate, twelve from the other. Existence first, location second. They are different questions and the discriminant answers only the first. Now the promised second root, in the case where the discriminant is nothing. Take three x squared minus two root six x plus two equals nought. Its discriminant is twenty-four minus twenty-four. Nothing. And if you factorise that expression, you get the same linear factor twice.

That is where the second root is. The factor appears twice, so it supplies its number twice. A vanishing discriminant and a repeated factor are not two facts. They are one event, seen from two directions. That was tested across the whole sweep, and tested the hard way. For every one of five thousand quadratics, a search hunted for a number r such that a times x minus r, all squared, IS the expression.

The search knows nothing about discriminants. It just tries candidates. It found exactly forty-eight, and those forty-eight are exactly the forty-eight whose discriminant is nothing. Not one more, not one fewer. Because the discriminant is a single expression, you can also run the question backwards. Take two x squared plus k x plus three equals nought, and ask what k makes the roots equal. Equal roots means the discriminant is nothing. k squared minus twenty-four equals nought.

So k is two root six, or minus two root six — both of them answers. Now a second one, and it has a trap in it. k x times x minus two, plus six, equals nought. Tidy it first: k x squared minus two k x plus six equals nought. Its discriminant is four k squared minus twenty-four k, which is four k times k minus six. That is nothing when k is nought, and when k is six.

But look at k equals nought. There is no x squared term left at all. It is not a quadratic. And what remains is the bare statement that six is nothing, which is false — no value of x makes it true. So k equals six is the only answer, and six x squared minus twelve x plus six really is six times x minus one, squared. Three questions now, one of each case, and all three are answered by a discriminant alone.

First: a rectangular grove, twice as long as it is broad, of area eight hundred square metres. Possible? With breadth x the equation is two x squared minus eight hundred equals nought, discriminant six thousand four hundred. Positive. So yes. And a hunt through fourteen thousand four hundred rectangles turns up exactly one: twenty metres by forty. Second: two friends whose ages total twenty, and whose ages four years ago multiplied to forty-eight.

That gives x squared minus twenty x plus a hundred and twelve. Discriminant four hundred minus four hundred and forty-eight. Minus forty-eight. Negative. So the situation cannot occur. That is the answer — not a failure to find one, and the hunt through every candidate pair confirms it. Third: a rectangular park with eighty metres of boundary and an area of four hundred. Discriminant sixteen hundred minus sixteen hundred. Nothing.

So it is possible, and possible in exactly one way — and that one way turns out to be a twenty-metre square. A word on the checking, because this claim is the easiest in the subject to confirm without testing anything. It is TRUE that the sign settles the count. So a checker that counts the roots using the formula — which has b squared minus four a c under its square-root sign — has proved precisely nothing.

So the counting was done somewhere the discriminant is not. Each expression was evaluated at every twenty-fourth from minus sixteen to sixteen, and the roots were counted as the places where the value changed sign or landed on nothing. Three million eight hundred and forty-five thousand points, and nowhere in that walk is b squared minus four a c formed, or two a, or a square root. The two verdicts agreed on all five thousand: three thousand five hundred and sixty-four with two roots, forty-eight with one, one thousand three hundred and eighty-eight with none.

And beside it the same table built from a mis-stated discriminant, b squared PLUS four a c, which gets the count wrong two thousand eight hundred and fifty-six times. That is what makes the agreement mean something. A table that is diagonal with nothing beside it is a table of one column. Both roots sit at minus b over two a, and are then pushed apart by the square root of b squared minus four a c, over two a.

The push is the only part that can change the count, so the only question is what the push is. Positive discriminant: a real push, two distinct roots. Nothing: no push, two roots which coincide on one number — and a repeated factor is that same event seen from the other side. Negative: no real number to push by, and no real root. Only the sign decides. The size tells you how far apart they are, and nothing whatever about how many.

Which is why 'is this possible?' is a question you can answer in one line, and answer honestly with a no.

Where this fits

Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.

Builds on

Either side of this one

The book

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