PrepShorts · Study sheet · Class 11 Mathematics · Chapter 10, Conic Sections
Chapter 10 · Conic Sections
The latus rectum measured on an open curve, by the ellipse's own calculation
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An ellipse's latus rectum and a hyperbola's reduce to the identical formula - no coincidence, since both curves' eccentricities cancel out of the working entirely.
The idea
The ellipse's latus rectum is found by substitution — put the focus's abscissa into the standard equation and solve — and the striking thing about the answer is what is missing from it. The half-length comes out as b²(1 − e²) under a square root, and 1 − e² is not a new quantity at all: it is b²/a². The two appearances of e cancel, c disappears, and the length 2b²/a depends only on the two denominators already written in the equation. That cancellation is why §10.6.3 can hand the hyperbola the identical formula in a single sentence without repeating any work. And the sign that separates the two curves enters this working twice — once in the equation, which leaves the ellipse with 1 − e² and the hyperbola with e² − 1, and once in the identity, which makes the first of those b²/a² and the second b²/a² as well. Two reversals, cancelling each other, which is why the answer comes out unchanged. One formula, two curves, and the reason is arithmetic rather than coincidence.
What you should be able to do
- State Definition 6 and Definition 9 and say what the two have in common
- Locate a latus rectum on a drawing of an ellipse and of a hyperbola
- Derive the ellipse's latus rectum length by substituting the focus's abscissa
- Express e² in terms of a and b for the ellipse, and show the cancellation that removes e from the answer
- Verify the hyperbola's formula independently, and identify the single sign that differs
- Explain why the chapter is entitled to assert the hyperbola's result in one sentence
- Contrast the algebraic route used here with the definition-based route used for the parabola
- Compare the latus rectum against the major or transverse axis and say when it can be the longer of the two
- Read a latus rectum off a given equation, and recover an equation from a given latus rectum
Words to know
| Term | Definition in one line | First introduced |
|---|---|---|
| latus rectum | the chord through a focus, perpendicular to the main axis, ending on the curve | printed in this chapter (Definition 6, §10.5.4, p. 192; Definition 9, §10.6.3, p. 200) |
| major axis | the ellipse's axis through the foci, of length 2a | printed in this chapter (§10.5, p. 187) |
| transverse axis | the hyperbola's axis through the foci, of length 2a | printed in this chapter (§10.6, p. 196) |
| eccentricity | the ratio c/a, which enters the derivation and then cancels out of the answer | printed in this chapter (§10.5.2, p. 188) |
| foci | the two fixed points; each carries a latus rectum of its own | printed in this chapter (§10.5, p. 187) |
| semi-latus rectum | half the chord, the length b²/a | an added term; the chapter computes this length and calls it l |
| scale-free quantity | a number unchanged when every length in the figure is multiplied by the same factor | an added compound, not printed in this chapter |
Where people slip up
- "The hyperbola must have a different formula." It has the identical one, and the reason is the cancellation, not luck. Students who accept the chapter's one-sentence assertion without checking it cannot say why it is true, and cannot reconstruct it when they misremember which of e² and 1 is the larger.
- "An ellipse has one latus rectum." It has two, one at each focus, and they are equal. Definition 6 permits either focus and Fig 10.26 draws both. The same holds for the hyperbola, with one chord on each branch.
- "l = b²/a is the latus rectum." That is the half-chord. The symmetry step doubling it is easy to skip and gives an answer exactly half the truth.
- "The latus rectum is always shorter than the main axis." True for every ellipse, false for hyperbolas with b > a. Exercise 10.4 item 2 is the counterexample and it is printed in the book.
- "Because 4a works for the parabola, some multiple of a works here." The ellipse's and hyperbola's answers need both a and b. Only the parabola, which has a single shape parameter, can express it through one letter.
- "c has to be computed first." It does not appear in the final formula at all. That is precisely what the cancellation buys, and it is worth pointing at explicitly because students reflexively find c before doing anything else.
- "Negative roots can be kept if you take the modulus." In Example 16 the rejected root is discarded because a is a length in a geometric configuration, not because of a sign convention. The quadratic is honest; the geometry is what selects.
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Worked answers: Exercise 10.1 · Exercise 10.2 · Exercise 10.3 · Exercise 10.4 · Miscellaneous Exercise · this video explains Exercise 10.4 Q12, Exercise 10.4 Q13
Transcript2,012 words
Here is a length worth having a name. Stand at one of a curve's two fixed points, draw the line straight across the main axis, and measure the piece of it the curve cuts off. That chord is what we are after. Two things about the definition before any algebra. First, it says either fixed point, so there are two such chords and not one. Over twelve curves built here, the number whose two fixed points give chords of different length is zero.
Second, on an open curve those two chords sit on different pieces, one on each branch: sets where they landed on the same piece, zero. Take the closed curve first and pick one end of the chord. Its position across the page is the offset, because the chord stands over a fixed point. Call its height, half the chord, simply l. So the end of the chord sits at the offset across and l up.
Now one rewriting, and it is the whole reason the answer looks the way it does. The offset is the ratio times the half-length along the main axis - that is what the ratio means. So write that end as the ratio times the half-length across, and l up. Nothing has happened yet. But the ratio is now in the working, and watching it leave again is the point of this whole topic.
The end of the chord is a point of the curve, so it satisfies the curve's equation. Put it in. The first coordinate squared over the first half squared is the ratio times the half-length, all squared, over the half-length squared - and the half-lengths cancel, leaving the ratio squared. The second term is l squared over the second half squared, untouched. So the ratio squared plus l squared over the second half squared is one.
Rearranged: l squared is the second half squared, times one less the ratio squared. That is a complete answer. It is also a bad one, and it is worth saying why. Look at what that answer needs. It needs the second half-length, which is sitting in the equation already. And it needs the ratio, which is not - to get the ratio you must first find the offset, and that is a whole extra step people reach for reflexively.
Here that reflex is about to be shown up as unnecessary, because the ratio is not a new quantity at all. It is built from the two half-lengths, and if we say so out loud it will not survive to the end of the line. The ratio is the offset over the first half-length, so the ratio squared is the offset squared over the first half squared. And for a closed curve the offset squared is the first half squared less the second half squared.
Put those together and the ratio squared is one, less the second half squared over the first half squared. Which means one less the ratio squared - the exact thing standing in our answer - is the second half squared over the first half squared, and nothing else. That is the identity the whole topic turns on, and it is one rearrangement of something you already had. Now substitute it back.
l squared was the second half squared times one less the ratio squared. It is now the second half squared, times the second half squared over the first half squared. That is the second half to the fourth, over the first half squared. So l is the second half squared over the first half-length. And l was only half the chord. The curve is symmetric about the main axis, so the other half matches: over twelve curves, the number where the measured chord came out as the half rather than the whole is zero, and the number where it is exactly twice that half is twelve.
The whole chord is twice the second half squared, over the first half-length. Look at what is not in that. No ratio, and no offset. Only the two numbers already written underneath the equation. A formula you have derived is still only a formula, so this one was put to work against curves built from the definition instead. Each curve here is a set of points: two fixed points and one constant, nothing else. The chord is then found by asking that set which points it holds on the upright line through a fixed point - and the answer comes out of the two distances alone, with no equation consulted.
Twelve curves scored that way, six of each kind. Every one gives exactly two points on that line, and the number where the two heights are not each other's negatives is zero. Twenty-four chord ends, and the number where the distance the solve pinned down disagrees with the plane's own distance to that fixed point: zero. And the number of curves where the measured chord disagrees with twice the second denominator over the first: zero, out of twelve.
The half-lengths are not read off anything either. The first is walked to along the axis; the second is measured on the line through the middle, which for the six closed curves gives the second denominator exactly - and for the six open ones gives nothing, because that line misses them. Now the open curve, and it is very tempting to stop here. The definition is the same shape, with transverse axis in place of major axis, and the answer turns out to be the same length. Why not just say so and move on?
Because the derivation you have just watched used the closed curve's identity at one step, and the open curve's is not the same identity. Take the result on trust and you cannot rebuild it the day you misremember which of the ratio squared and one is the larger. Do the work once and there is nothing left to remember. The end of the chord still sits at the offset across and l up, and the offset is still the ratio times the first half-length.
But the equation now subtracts, so substituting gives the ratio squared, minus l squared over the second half squared, equals one. So l squared is the second half squared, times the ratio squared less one. The gap is taken the other way round. That is the first reversal. Now the identity. For an open curve the offset squared is the two half squares added, so the ratio squared is one plus the second half squared over the first half squared.
Which makes the ratio squared less one equal to the second half squared over the first half squared - the same expression the closed curve produced. That is the second reversal. Two sign changes, one in the equation and one in the identity, and they cancel each other. Over six closed curves the gap points below one every time and over six open ones it points above, but the size of that gap is the second denominator over the first for all twelve, with zero exceptions.
So l squared is the second half to the fourth over the first half squared again, and the chord is twice the second half squared over the first half-length. Same answer, reached honestly - and you can now point at the step that carried the sign. It is worth seeing what happens if you take the gap the wrong way round. Use the closed curve's version on an open one, or the other way about, and the quantity you get is negative.
Not slightly wrong - negative, and a squared length is not negative. Over all twelve curves, the number where the wrong way round leaves something that cannot be a squared length is twelve, and they all complain in the same words. So the arithmetic catches this by itself. You do not need to remember which way the gap goes; you need only notice when the answer stops being a length.
Here is the sharpest way to see what the cancellation bought. Four open curves were built to share one ratio exactly - four different sizes of the same shape. Distinct values of the ratio squared among them: one. Distinct chords among them: four. So the ratio alone does not fix the chord. But take each chord against its own main axis, and the distinct values of that comparison among the four: one. The ratio fixes the shape of the answer, and the size has to come from somewhere else.
Try the offset instead. Two curves built to share one offset: distinct offsets, one; distinct chords, two. The offset alone does not fix it either. Now group all twelve by their two denominators. Twelve groups, and the number of groups holding more than one chord is zero. That is what the cancellation says, said as a count. The chord needs both denominators, and it needs nothing else. One comparison before we finish, because it explains why this topic was harder than it looks.
There is a third curve, built from one fixed point and one fixed line, and it has a chord of exactly this kind - reached without solving anything at all. Take the end of that chord. By the definition its distance to the fixed point equals its distance to the fixed line, and on the upright line through the fixed point that second distance is just the separation between the point and the line.
So the half-chord is the separation and the chord is twice it. Over five such curves, the number where the endpoint's two distances differ is zero, and the number where the half-chord is not the separation is zero. No equation, and no identity. The two curves in this topic have no fixed line to lean on, so substitution is the only route open to them - and that is why their answer needs two letters where the third curve's needs one.
One last comparison, and it retires a rule you may be carrying. For a closed curve the second half-length is always the smaller, so the chord is always shorter than the main axis. Over six closed curves, the number whose chord reaches past that axis is zero. For an open curve nothing forces that. Over six open curves, three have a chord longer than the axis - and they are exactly the three whose second denominator passes the first. The two counts pick out different curves zero times.
One of them is worth drawing. Its axis through the two fixed points measures six; its chord measures eighteen. Three times as long. So a chord through a fixed point can be longer than the axis it crosses. Only on the open curve, and only when the second half-length wins. Using it takes almost no work, which is the point of a cancelled answer. Eighteen written equations were read here, every one needing to be divided through first. The number where the formula and the definition's own solve disagree about the chord is zero.
The first gives eighteen fifths. An open one gives thirty-two thirds. One that hides its shape until you divide gives one half. And the long one from a moment ago gives eighteen. One of the eighteen has a first denominator of thirty-six fifths, which is not a square. Its chord cannot be written as a fraction at all - but its square can, exactly: eighty ninths. Of the eighteen, seventeen have a chord a fraction can name and one does not.
Backwards is more interesting. Given the offset and the chord, the relation between the three lengths leaves a quadratic in the first half-length. Three such problems, six roots offered. Three are lengths; three are negative and get thrown away - not by a sign convention, but by the geometry, because a half-length is a length. The algebra is honest and offers both; you are the one who chooses. Build the curve back from the root that survives, measure its chord, and it returns exactly the chord you were given.
Where this fits
Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.
Builds on
- Putting the centre at the origin, and reading the axes off the equationClass 11 · Ch 10, Conic Sections
- The right triangle hidden in the figure, and the single number that sets the shapeClass 11 · Ch 10, Conic Sections
- Once c outgrows a, the ellipse's eccentricity and equation become the hyperbola'sClass 11 · Ch 10, Conic Sections
- The chord through the focus that measures how open the curve isClass 11 · Ch 10, Conic Sections
Either side of this one
- Three perpendicular planes, and the eight regions they cut space intoClass 11 · Ch 11, Introduction to Three Dimensional Geometry