PrepShorts · Study sheet · Class 10 Mathematics · Chapter 7, Coordinate Geometry
Chapter 7 · Coordinate Geometry
Deriving the distance rule by hanging a right triangle off the two points
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Two points, a slant between them, and no right angle anywhere in the question. So we put one there - three lines that were not in the problem, drawn for the single reason that a right triangle is a thing we already know how to finish.
The idea
There is no new theorem in the distance rule — it is Pythagoras, and the only inventive step is a construction that manufactures a right angle where none was drawn. Dropping a perpendicular from each point to the horizontal axis and then running a horizontal through the lower point produces a right triangle whose two legs you never have to measure, because the axes have already measured them: one leg is the gap between the two first coordinates, the other the gap between the two second coordinates. And because the legs enter the theorem squared, the result cannot notice which point you called first, or which quadrants the points sit in — which is exactly why the chapter can add a remark interchanging the two labels and still get the same rule. The one thing squaring cannot settle is which root to take at the end, and there the chapter reaches outside the algebra for its reason: a separation is a size, so only the non-negative root survives.
What you should be able to do
- Set up the auxiliary construction for two given points — two perpendiculars to the horizontal axis and one horizontal segment — and name the right angle it creates
- Express each leg of that triangle as a difference of coordinates, justifying the expression from the figure rather than quoting it
- Apply Pythagoras to obtain the separation of two points in the first quadrant, and simplify the surd
- Repeat the derivation for two points in different quadrants and show that nothing in the argument changes
- Carry out the same construction with letters in place of numbers and arrive at the general rule the chapter names the distance formula
- Explain why only the non-negative square root is taken
- Derive the special case for a point measured from the origin, without treating it as a separate rule to memorise
- Explain why the rule is unchanged when the two points swap roles
- Use the rule in reverse: given a separation, solve for a missing coordinate
Words to know
| Term | Definition in one line | First introduced |
|---|---|---|
| distance formula | the printed name for the general rule this topic derives | printed and named in §7.2, p. 102 |
| Pythagoras Theorem | the right-triangle result the whole derivation rests on | printed in §7.2, p. 100, and applied on pp. 101–102 |
| perpendicular | a segment dropped from a point to meet a line at a right angle | printed in §7.2, p. 100 |
| quadrant | one of the four regions the axes cut the plane into | printed in §7.2, pp. 100–101 |
| origin | the meeting point of the two axes, the reference for Remark 1 | printed in §7.2, p. 102 |
| units | the chapter's own way of reporting a separation on a coordinate diagram, without a physical unit attached | printed throughout §7.2, pp. 100–102 |
| square root | the operation undoing the squaring at the last step, taken here non-negative | printed in §7.2, p. 102 |
| coordinate difference | an added name for a quantity such as x₂ − x₁ once it is being read as the length of a leg | an added term; the chapter writes the quantity without naming it |
| auxiliary construction | an added name for the lines added to a figure purely to create a right angle | an added term; not printed in this chapter |
Where people slip up
- "You subtract the coordinates and that is the distance." It works along an axis and nowhere else. Show the two easy warm-ups from Fig. 7.2 first, then show that the same move on P(4, 6) and Q(6, 8) gives 2 and 2 and no separation at all until you square and add.
- "You have to put the smaller coordinate first." You do not, and Remark 2 is the chapter saying so. Deliberately run one of the examples in both orders on camera and land on the same surd.
- "Negative coordinates need a different formula." They need the same one. The two-quadrant example exists precisely to be worked identically to the first-quadrant one; the only skill it adds is subtracting across zero.
- "PT = 11 because you add 6 and 5." Adding happens to give the right number here only because the two points straddle the axis. Teach it as the single subtraction 6 − (−5), which also survives when both points sit on the same side.
- "The formula gives a length, so both roots are valid." A separation is a size and cannot be negative, which is the chapter's own stated reason for keeping one root. Contrast this deliberately with Exercise 7.1 question 8, where two answers are both valid — because there the unknown is a coordinate, not a length.
- "√8 is the answer." It is an answer; 2√2 is the same number written so that its size is readable. Do not attribute the habit to the chapter, which is inconsistent about it: Example 3 (p. 104) reduces all three of its radicals, Example 1 (p. 102) reduces none of its three and prints two-decimal approximations instead, and Example 2 (p. 103) leaves a reducible radical standing untouched. The same quantity, the root of fifty, appears once each way. If the explanation wants the readability lesson it has to argue for it in its own voice.
- "The right triangle is given." It is not. Nothing in the statement of the problem contains a right angle; the construction puts one there. This is the step the explanation exists to make visible.
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Worked answers: Exercise 7.1 · Exercise 7.2 · this video explains Exercise 7.1 Q1, Exercise 7.1 Q2, Exercise 7.1 Q8, Exercise 7.1 Q9
Transcript2,067 words
Two towns. The second one is thirty-six kilometres east of the first and fifteen kilometres north of it. How far apart are they? Not thirty-six plus fifteen. That is the distance you walk going east first and then north, and nothing travels in an L. Not thirty-six either, and not fifteen. Those are the two legs of the walk, not the journey. The straight line between the towns is shorter than the walk and longer than either leg, and so far we have no way at all to say what it is.
What we do have is two numbers laid at right angles to each other, which is the shape of every coordinate pair there has ever been. So this is not really a question about towns. It is a question about what two readings can tell you about a length. By the end there will be one rule that answers it, and the rule will turn out to contain no new mathematics whatsoever.
Start with the separations we can already do. Two points on the horizontal ruler, one at four across and one at six across. Six take away four. Two units. Two points on the vertical ruler, at three up and at eight up. Eight take away three. Five units. The reason those work is not that the points happen to sit on a ruler. It is that they agree in their other reading. Both of the first pair are at height zero, so the whole gap lies along one direction.
And when a gap lies along one direction, a single subtraction catches all of it. Take a grid of eighty points and look at every pair. Six hundred and forty pairs share a reading and subtracting handles them. On the other two thousand five hundred and twenty it fails every time. So here is a pair that does not cooperate. P sits at four across and six up. Q sits at six across and eight up.
Subtract the first readings: six take away four is two. Subtract the second readings: eight take away six is two. Two and two. Two what? Neither of those numbers is the separation. They are the two ways in which the points differ, and the separation is some third thing built out of both. You can see it in the picture. P and Q sit on a slant, and the slant is plainly longer than two.
But there is no ruler laid along that slant. Nothing in the diagram has measured it, and nothing is going to. So we are going to have to build something that has. Here is the move, and it is the only inventive step in this entire topic. Drop a perpendicular from P straight down to the horizontal ruler. Drop a second one from Q. Now run a horizontal line from P across until it meets that second perpendicular. Call the meeting point T.
Look at what has appeared. P, T and Q are the three corners of a triangle, and the corner at T is a right angle. Nothing in the question contained a right angle. Two points and the slant between them have no angle in them at all. We put one there. Three lines that were not in the problem, drawn for no reason except that a right angle is a thing we already know how to handle.
That is what a construction is. Not a discovery. A manufacture. Now the part that makes the whole manoeuvre worth doing. The two new sides never have to be measured, because the rulers measured them already. PT runs horizontally. Its two ends are at four across and six across, and the gap between two points on one horizontal line is the difference of their first readings. Two. TQ runs vertically. Its ends are at six up and eight up. The difference of the second readings. Also two.
Each leg is a coordinate difference. Not a length you squint at on a diagram, but an arithmetic you do on the numbers you were handed at the start. That is the second half of the trick. The construction makes a right triangle, and the coordinates fill in its two legs for nothing. Across two thousand five hundred and twenty pairs of points, every single time, both legs come out as differences and neither one is ever measured.
A right triangle with two known legs has a known third side. That is the oldest tool in the box. Square the first leg: two squared is four. Square the second: also four. Add them: eight. That is the square of the separation. Then take the square root. P and Q are the root of eight apart. And that is the whole rule. Square the difference of the first readings, square the difference of the second, add the two, take the root.
No new theorem entered anywhere in that. The only thing that happened is that a right triangle got built where there had not been one. Which means every separation you ever compute this way is Pythagoras, wearing coordinates. Try it somewhere the numbers are less friendly. P at six across and four up. Q five to the left and three down, so its two readings are minus five and minus three.
Same construction, line for line. Drop a perpendicular from Q to the horizontal ruler, run a horizontal from P across to meet it, and mark the corner. That corner sits at minus five across and four up, because it is below Q and level with P. The horizontal leg runs from minus five across to six across. Its length is six take away minus five. Eleven. The vertical leg runs from minus three up to four up. Four take away minus three. Seven.
Eleven squared is a hundred and twenty-one, seven squared is forty-nine, and they add to a hundred and seventy. The separation is the root of a hundred and seventy, and nothing about the method changed. But something in that example is worth stopping on, because it hides a mistake. Eleven is six take away minus five. Eleven is also six plus five. So on that figure you can get the right answer by ADDING the two distances from the ruler instead of subtracting the two readings, and nobody would ever catch you.
It works there because the two points sit on opposite sides. Adding two distances and subtracting two readings are the same arithmetic only when you cross zero between them. Move one point over so that both are on the same side and they part company immediately. Six and two: subtracting gives four, adding gives eight. Over every pair in the grid of eighty, the adding rule is right on one thousand eight hundred and eighty-four of them and wrong on one thousand two hundred and seventy-six.
And there is a cleaner reason it cannot be a length. Slide the entire picture a hundred units in each direction: every real separation is untouched, and the adding rule's answer changes on every single pair. A length does not know where you put the origin. That one does. Now run the identical construction with nothing but letters in it. P has readings x-one and y-one. Q has x-two and y-two. Drop the two perpendiculars, run the horizontal across, mark the corner.
The corner sits directly below Q and directly across from P, so its readings are x-two and y-one. The horizontal leg is therefore x-two minus x-one, and the vertical leg is y-two minus y-one. Same argument, no numbers. Square them. Add them. Take the root. The separation of P and Q is the square root of x-two minus x-one all squared, plus y-two minus y-one all squared. That is the rule, and you have just watched it get built instead of being handed it.
Two loose ends, and both of them are about squaring. Squaring throws away a sign, so at the last step there are two numbers whose square is what we computed. One positive, one negative. We keep the non-negative one, and not because somebody decided to. A separation is a size, and a size cannot be less than nothing. The second loose end is which point you called first. Swap them and every single difference changes sign.
But every difference goes into the rule squared, and a squared number cannot tell you what sign it used to have. So the two orders agree, and they agree term by term rather than by some cancellation in the total. On three thousand one hundred and sixty pairs of points, run both ways round, the rule does not once return a different answer. Two more things fall out at no extra cost, and neither is a new rule.
Put one of the two points at the origin. Both of its readings are nought, so both differences collapse to the other point's own readings. The separation of a point from the origin is the root of its first reading squared plus its second reading squared. That is not a second formula to memorise. It is the same one with two zeros substituted in, and the substituting is the part you should actually do.
The other one is the swap we just made. Written out with the two points interchanged, the rule looks like a different expression. It is not. x-one minus x-two is the negative of x-two minus x-one, and squaring destroys every trace of the difference between them. Term by term, not by coincidence in the sum. Which is a thing worth checking rather than believing. One habit left, and it is worth arguing for rather than assuming.
The first example came out as the root of eight. That is a correct answer and a fairly useless one, because nobody has any feel for how big the root of eight is. Eight is four times two, and four is a perfect square, so the root of eight is two roots of two. The root of two is about one point four, so the separation is about two point eight. Now you know its size.
Same move on the root of fifty. Fifty is twenty-five times two, so it is five roots of two. But the root of a hundred and seventy has nothing to pull out. Two, five and seventeen multiply to give it, and not one of them appears twice. So it stays exactly as it is. Simplifying a root is not a ritual you perform on every answer. It is something you do when there is a square factor sitting there to be taken.
The rule also runs backwards, and there it behaves differently in a way that is worth watching closely. P sits at two across and three down. Q sits at ten across, at some height we do not know. The two are ten units apart. What is the height? The horizontal difference is eight. Eight squared is sixty-four, the whole separation squared is a hundred, so the vertical difference squared has to be thirty-six.
The vertical difference is six. Or it is minus six. And this time we keep both of them. Q is either six above P or six below. Its second reading is three, or it is minus nine, and putting either one back into the rule returns a hundred. Now compare that with the last step of the rule itself, where we deliberately threw one root away. There the unknown was a length, and a length has no sign to lose. Here the unknown is a coordinate, and a coordinate does. Same equation, different question, different number of answers.
Back to where we started. One town, and the other thirty-six kilometres east of it and fifteen north. Put the first at the origin and the second one's readings are thirty-six and fifteen. Thirty-six squared is one thousand two hundred and ninety-six. Fifteen squared is two hundred and twenty-five. Those add to one thousand five hundred and twenty-one, and one thousand five hundred and twenty-one is thirty-nine squared, exactly. Thirty-nine kilometres. Not fifty-one, which is the walk, and not thirty-six, which is only the eastward part of it.
Look back at what actually did the work there. Not the formula. The three lines nobody asked for. There was no right angle, and then there was one, and everything after that was arithmetic we already had.
Where this fits
Taken from the notes each video was made from, not from the reading order — these are the ideas this one rests on and the ones that later rest on it.
Builds on
- Abscissa and ordinate, and what a coordinate pair actually recordsClass 10 · Ch 7, Coordinate Geometry
Comes up again in
- Using distances alone to classify a triangle or a quadrilateralClass 10 · Ch 7, Coordinate Geometry
- Getting the section rule from a pair of similar trianglesClass 10 · Ch 7, Coordinate Geometry
- The midpoint as the ratio 1 : 1, and recovering an unknown ratioClass 10 · Ch 7, Coordinate Geometry